quoting

Write CSV To File Without Enclosures In PHP

大兔子大兔子 提交于 2019-11-26 18:10:21
问题 Is there a native function or solid class/library for writing an array as a line in a CSV file without enclosures? fputcsv will default to " if nothing is passed in for the enclosure param. Google is failing me (returning results for a whole bunch of pages about fputcsv ), and PEAR's libraries do more or less the same things as fputcsv . Something that works exactly like fputcsv , but will allow the fields to remain unquoted. currently: "field 1","field 2",field3hasNoSpaces desired: field 1

How to pass arguments with special characters to call shell script

喜欢而已 提交于 2019-11-26 17:08:58
问题 Calling .sh(shell script) with the required parameters as below :- sh home/example.sh --context_param dbUserName=username --context_param dbPassword=exam!ple##### --context_param resultDate=2017-01-13 calling example.sh with paramters dbUsername and password but getting following error:- -bash: !ple#####: event not found I think special characters restrict the command to execute. Then how i have to pass the special characters. Any help will be appreciable. 回答1: Change the line, dbPassword

bash quotes in variable treated different when expanded to command [duplicate]

纵饮孤独 提交于 2019-11-26 16:47:51
问题 This question already has an answer here: Why does shell ignore quotes in arguments passed to it through variables? [duplicate] 3 answers Explaining the question through examples... Demonstrates that the single-quotes after --chapters is gets escaped when the variable is expanded (I didn't expect this): prompt@ubuntu:/my/scripts$ cat test1.sh #!/bin/bash actions="--tags all:" actions+=" --chapters ''" mkvpropedit "$1" $actions prompt@ubuntu:/my/scripts$ ./test1.sh some.mkv Error: Could not

Using a Variable (PowerShell) inside of a command

我只是一个虾纸丫 提交于 2019-11-26 11:35:51
问题 $computer = gc env:computername # Argument /RU \'$computer\'\\admin isn\'t working. SchTasks /create /SC Daily /tn \"Image Verification\" /ST 18:00:00 /TR C:\\bdr\\ImageVerification\\ImageVerification.exe /RU \'$computer\'\\admin /RP password Basically I need to provide the computer name in the scheduled task... Thank you in advance! 回答1: Single quoted strings will not expand variables in PowerShell. Try a double quoted string e.g.: "$computer\admin" 回答2: use the command 'hostname' to get the

Why do I get “/bin/sh: Argument list too long” when passing quoted arguments?

大城市里の小女人 提交于 2019-11-26 08:24:42
问题 How long can be a command line that can be passed to sh -c \'\' ? (in bash and in bourne shell) The limit is much lower than that from the OS (in case of modern Linux). For example: $ /bin/true $(seq 1 100000) $ /bin/sh -c \"/bin/true $(seq 1 100000)\" bash: /bin/sh: Argument list too long And how could I circumvent this problem? Update I want to note that getconf can\'t help here (because that is not a system limit): $ seq 1 100000 | wc -c 588895 $ getconf ARG_MAX 2097152 Update #2 Now I\'ve

Bash doesn't parse quotes when converting a string to arguments

纵饮孤独 提交于 2019-11-26 07:46:09
问题 This is my problem. In bash 3: $ test=\'One \"This is two\" Three\' $ set -- $test $ echo $2 \"This How to get bash to understand the quotes and return $2 as This is two and not \"This ? Unfortunately I cannot alter the construction of the variable called test in this example. 回答1: The reason this happens is because of the order in which the shell parses the command line: it parses (and removes) quotes and escapes, then replaces variable values. By the time $test gets replaced with One "This

I just assigned a variable, but echo $variable shows something else

拈花ヽ惹草 提交于 2019-11-25 22:54:26
问题 Here are a series of cases where echo $var can show a different value than what was just assigned. This happens regardless of whether the assigned value was \"double quoted\", \'single quoted\' or unquoted. How do I get the shell to set my variable correctly? Asterisks The expected output is /* Foobar is free software */ , but instead I get a list of filenames: $ var=\"/* Foobar is free software */\" $ echo $var /bin /boot /dev /etc /home /initrd.img /lib /lib64 /media /mnt /opt /proc ...

Why does shell ignore quotes in arguments passed to it through variables? [duplicate]

余生长醉 提交于 2019-11-25 21:46:12
问题 This question already has answers here : How to store a command in a variable in a shell script? (6 answers) Closed 10 months ago . This works as advertised: # example 1 #!/bin/bash grep -ir \'hello world\' . This doesn\'t: # example 2 #!/bin/bash argumentString=\"-ir \'hello world\'\" grep $argumentString . Despite \'hello world\' being enclosed by quotes in the second example, grep interprets \'hello as one argument and world\' as another, which means that, in this case, \'hello will be the

How to escape single quotes within single quoted strings

喜欢而已 提交于 2019-11-25 21:45:01
问题 Let\'s say, you have a Bash alias like: alias rxvt=\'urxvt\' which works fine. However: alias rxvt=\'urxvt -fg \'#111111\' -bg \'#111111\'\' won\'t work, and neither will: alias rxvt=\'urxvt -fg \\\'#111111\\\' -bg \\\'#111111\\\'\' So how do you end up matching up opening and closing quotes inside a string once you have escaped quotes? alias rxvt=\'urxvt -fg\'\\\'\'#111111\'\\\'\' -bg \'\\\'\'#111111\'\\\'\' seems ungainly although it would represent the same string if you\'re allowed to