quicksort

Quick sort with middle element as pivot

戏子无情 提交于 2019-12-03 08:53:20
My understanding of quick sort is Choose a pivot element (in this case I am choosing middle element as pivot) Initialize left and right pointers at extremes. Find the first element to the left of the pivot which is greater than pivot. Similarly find the first element to the right of the pivot which is smaller than pivot Swap elements found in 3 and 4. Repeat 3,4,5 unless left >= right. Repeat the whole thing for left and right subarray as pivot is now placed at its place. I am sure I am missing something here and being very stupid. But above does not seems to be working fot this array: 8,7,1,2

In Java, How do you quicksort an ArrayList of objects in which the sorting field is multiple layers deep?

﹥>﹥吖頭↗ 提交于 2019-12-03 08:40:00
Basically, I have a Container class called "Employees" which has in it an ArrayList. This ArrayList contains "Employee" objects, which in turn contain "EmployeeData" objects which in turn contain String objects such as "first" or "last" (which are employee names). Here's a diagram of the ArrayList structure: ArrayList[Employee] emps ==> 1:Many ==> Employee emp Employee emp ==> 1:1 ==> EmployeeData data EmployeeData data ==> 1:2 ==> String last // A string that contains employee's last name. How in the world would I perform a quicksort on the ArrayList so that the "Employee" objects in it are

Quicksort- how pivot-choosing strategies affect the overall Big-oh behavior of quicksort?

痞子三分冷 提交于 2019-12-03 07:56:45
I have came up with several strategies, but I am not entirely sure how they affect the overall behavior. I know the average case is O(NlogN), so I would assume that would be in the answer somewhere. I want to just put NlogN+1 for if I just select the 1st item in the array as the the pivot for the quicksort, but I don't know whether that is either correct nor acceptable? If anyone could enlighten me on this subject that would be great. Thanks! Possible Strategies: a) Array is random: pick the first item since that is the most cost effective choice. b) Array is mostly sorted: pick middle item so

Is Quicksort a potential security risk?

一个人想着一个人 提交于 2019-12-03 06:59:52
问题 I just wondered whether (with some serious paranoia and under certain circumstances) the use of the QuickSort algorithm can be seen as a security risk in an application. Both its basic implementation and improved versions like 3-median-quicksort have the peculiarity of behaving deviant for certain input data, which means that their runtime can increase extremely in these cases (having O(n^2) complexity) not to mention the possibility of a stackoverflow. Hence I would see potential to do harm

Implementing quicksort algorithm

蓝咒 提交于 2019-12-03 05:47:14
问题 I found quicksort algorithm from this book This is the algorithm QUICKSORT (A, p, r) if p < r q = PARTITION(A, p, r) QUICKSORT(A, p, q-1) QUICKSORT(A, q+1, r) PARTITION(A, p, r) x=A[r] i=p-1 for j = p to r - 1 if A <= x i = i + 1 exchange A[i] with A[j] exchange A[i+1] with A[r] return i + 1 And I made this c# code: private void quicksort(int[] input, int low, int high) { int pivot_loc = 0; if (low < high) pivot_loc = partition(input, low, high); quicksort(input, low, pivot_loc - 1);

Quicksort slower than Mergesort?

自古美人都是妖i 提交于 2019-12-03 04:49:15
I was working on implementing a quicksort yesterday, and then I ran it, expecting a faster runtime than the Mergesort (which I had also implemented). I ran the two, and while the quicksort was faster for smaller data sets <100 elements (and I did verify that it works), the mergesort became the quicker algorithm fairly quickly. I had been taught that quicksort is almost always "quicker" than mergesort, and I understand that there is some debate on this topic, but I at least expected it to be closer than this. For data sets >10000 elements, the mergesort was over 4 times faster. Is this to be

Quicksort with 3-way partition

瘦欲@ 提交于 2019-12-03 04:08:28
问题 What is QuickSort with a 3-way partition? 回答1: Picture an array: 3, 5, 2, 7, 6, 4, 2, 8, 8, 9, 0 A two partition Quick Sort would pick a value, say 4, and put every element greater than 4 on one side of the array and every element less than 4 on the other side. Like so: 3, 2, 0, 2, 4, | 8, 7, 8, 9, 6, 5 A three partition Quick Sort would pick two values to partition on and split the array up that way. Lets choose 4 and 7: 3, 2, 0, 2, | 4, 6, 5, 7, | 8, 8, 9 It is just a slight variation on

JavaScript quicksort

六月ゝ 毕业季﹏ 提交于 2019-12-03 03:52:59
问题 I have been looking around the web for a while and I am wondering if there is a 'stable' defacto implementation of quicksort that is generally used? I can write my own but why reinvent the wheel... 回答1: You can easily "stabilize" an unstable sort using a decorate-sort-undecorate pattern function stableSort(v, f) { if (f === undefined) { f = function(a, b) { a = ""+a; b = ""+b; return a < b ? -1 : (a > b ? 1 : 0); } } var dv = []; for (var i=0; i<v.length; i++) { dv[i] = [v[i], i]; } dv.sort

Is Quicksort in-place or not? [duplicate]

Deadly 提交于 2019-12-03 03:37:54
问题 This question already has answers here : Is imperative Quicksort in situ (in-place) or not? (2 answers) Closed 5 years ago . So the space efficiency of Quicksort is O(log(n)). This is the space required to maintain the call stack. Now, according to the Wikipedia page on Quicksort, this qualifies as an in-place algorithm, as the algorithm is just swapping elements within the input data structure. According to this page however, the space Efficiency of O(log n) disqualifies Quicksort from being

When should we use Radix sort?

送分小仙女□ 提交于 2019-12-03 03:01:31
问题 It seems Radix sort has a very good average case performance, i.e. O(kN) : http://en.wikipedia.org/wiki/Radix_sort but it seems most people still are using Quick Sort, don't they? 回答1: Quick sort has an average of O(N logN), but it also has a worst case of O(N^2), so even due in most practical cases it wont get to N^2, there is always the risk that the input will be in "bad order" for you. This risk doesn't exist in radix sort. I think this gives a great advantage to radix sort. 回答2: Radix