query-parameters

Is a url like http://example.com/foo?bar valid? I'm looking for a link to something official that says one way or the other. A simple yes/no answer or anecdotal evidence won't cut it. Valid to the URI RFC Likely acceptable to your server-side framework/code The URI RFC doesn't mandate a format for the query string. Although it is recognized that the query string will often carry name-value pairs, it is not required to (e.g. it will often contain another URI). 3.4. Query The query component contains non-hierarchical data that, along with data in the path component (Section 3.3), serves to

I came across the following URL today: http://www.sfgate.com/cgi-bin/blogs/inmarin/detail??blogid=122&entry_id=64497 Notice the doubled question mark at the beginning of the query string: ??blogid=122&entry_id=64497 My browser didn't seem to have any trouble with it, and running a quick bookmarklet: javascript:alert(document.location.search); just gave me the query string shown above. Is this a valid URL? The reason I'm being so pedantic (assuming that I am) is because I need to parse URLs like this for query parameters, and supporting doubled question marks would require some changes to my

I am facing an issue on getting the value of tagid from my URL: localhost:8888/p?tagid=1234 . Help me out to correct my controller code. I am not able to get the tagid value. My code is as follows: app.js : var express = require('express'), http = require('http'), path = require('path'); var app = express(); var controller = require('./controller')({ app: app }); // all environments app.configure(function() { app.set('port', process.env.PORT || 8888); app.use(express.json()); app.use(express.urlencoded()); app.use(express.methodOverride()); app.use(app.router); app.use(express.static(path.join

Is there a way to parse a URL (with some python library) and return a python dictionary with the keys and values of a query parameters part of the URL? For example: url = "http://www.example.org/default.html?ct=32&op=92&item=98" expected return: {'ct':32, 'op':92, 'item':98} Martijn Pieters Use the urllib.parse library : >>> from urllib import parse >>> url = "http://www.example.org/default.html?ct=32&op=92&item=98" >>> parse.urlsplit(url) SplitResult(scheme='http', netloc='www.example.org', path='/default.html', query='ct=32&op=92&item=98', fragment='') >>> parse.parse_qs(parse.urlsplit(url)