python-3.2

Good morning, I'm trying to add a Gtk.Entry to a Gtk.MessageDialog . With the following code it seems that I added the Gtk.Entry but it's not visible on the dialog window (Python3/Gtk3) : #!/usr/bin/python3 from gi.repository import Gtk def get_user_pw(parent, message, default=''): dialogWindow = Gtk.MessageDialog(parent, Gtk.DialogFlags.MODAL | Gtk.DialogFlags.DESTROY_WITH_PARENT, Gtk.MessageType.QUESTION, Gtk.ButtonsType.OK_CANCEL, message) dialogBox = dialogWindow.get_content_area() userEntry = Gtk.Entry() userEntry.set_visibility(False) userEntry.set_invisible_char("*") userEntry.set_size

/proc/net/tcp gives me a local address, port, and inode number for a socket (0.0.0.0:5432 and 9289, for example). I'd like to find the PID for a specific process, given the above information. It's possible to open every numbered folder in /proc, and then check symlinks for matching socket/inode numbers with a shell command like "$ sudo ls -l /proc/*/fd/ 2>/dev/null | grep socket". However, this seems more computationally expensive than necessary, since <5% of the processes on any given system have open TCP sockets. What's the most efficient way to find the PID which has opened a given socket?

According to the documentation from python.org, python 3.2 install on mac os requires an upgrade to tcl/tk 8.5.9 (for use of IDLE). In my haste, I have done both. Now my friend told me that python 3 is not recommended yet because only the built-ins and a few modules have been released for 3. The stable one so far is 2.7 (especially if one wants to make extensive use of a variety of modules). My machine has both 2.6.1 and 3.2 (because some OS services make use of 2.6.1 that comes as default with the OS). 1. How do i remove 3.2 completely to avoid any compatibility issues? tcl/tk 8.5.9 was also

I have a string called Message. Message = "Hello, welcome!\nThis is some text that should be centered!" Yeah, it's just a test statement... And I'm trying to centre it for a default Terminal window, i.e. of 80 width, with this statement: print('{:^80}'.format(Message)) Which prints: Hello, welcome! This is some text that should be centered! I'm expecting something like: Hello, welcome! This is some text that should be centered! Any suggestions? You need to centre each line separately: '\n'.join('{:^80}'.format(s) for s in Message.split('\n')) Here is an alternative that will auto center your

I want to read an array of integers from single line of input in python3. For example: Read this array to a variable/list 1 3 5 7 9 What I have tried arr = input.split(' ') But this does not convert them to integers. It creates array of strings arr = input.split(' ') for i,val in enumerate(arr): arr[i] = int(val) 2nd one is working for me. But I am looking for an elegant(Single line) solution. Saullo G. P. Castro Use map : arr = list(map(int, input().split())) Just adding, in Python 2.x you don't need the to call list() , since map() already returns a list , but in Python 3.x "many processes

I'm working on a Python script that uses the scissor character (9986 - ✂) and I'm trying to port my code to Mac, but I'm running into this error. The scissor character shows up fine when run from IDLE (Python 3.2.5 - OS X 10.4.11 iBook G4 PPC) and the code works entirely fine on Ubuntu 13.10, but when I attempt to run this in the terminal I get this error/traceback: Traceback (most recent call last): File "snippets-convert.py", line 352, in <module> main() File "snippets-convert.py", line 41, in main menu() File "snippets-convert.py", line 47, in menu print ("|\t ",snipper.decode(),"PySnipt'd"