python-2.x

问题 Just purchased sublime 3. I'm wondering how I can compile in python 3 and not in python 2. When I execute import sys print(sys.version) I receive "2.7.3 |EPD_free 7.3-2 (32-bit)| (default, Apr 12 2012, 14:30:37) [MSC v.1500 32 bit (Intel)]" I've been stuck for the last 2 or 3 hours. I know it has something to do with builds but it just doesn't seem to be clicking. Any help would be greatly appreciated. Thanks! 回答1: The Sublime Text Python builder uses the Python executable found in your PATH.

问题 I get this error when I run my python script in my docker image ImportError: No module named _tkinter, please install the python-tk package So I tried 'pip install python-tk' root@43d2222b15c8:/tf_files# pip install python-tk Collecting python-tk Could not find a version that satisfies the requirement python-tk (from versions: ) No matching distribution found for python-tk But that does not fix my issue. Can you please tell me how can I fix my issue? Thank you. 回答1: Use import Tkinter . It

问题 I have some basic code that I'm not grasping the behaviour of: L = [ 'a', 'bb', 'ccc' ] L.append(range(2)) print len(L) print len(L + range(1)) print len(L) The output of which is 4 5 4 This is confusing to me, as my thought process is that the length of the initial list is 3, and appending range(2) to the end brings it to length of 5. Therefore I'd expect the output to be 5 6 5 . I'm sure it's a simple quirk, but I'm a bit lost and having a hell of a time trying to find an answer online.

问题 I have a very basic parrot script written in Python that simply prompts for a user input and prints it back inside an infinite loop. The Raspberry Pi has a USB barcode scanner attached for the input. while True: barcode = raw_input("Scan barcode: ") print "Barcode scanned: " + barcode When you scan at a "normal" speed it works reliably and the command output looks like this: Scan barcode: 9780465031467 Barcode scanned: 9780465031467 Scan barcode: 9780007505142 Barcode scanned: 9780007505142

问题 I am using futurize --stage2 which aplies a number of source-source transformation to make the code python2 and python3 compatible. One of those fixes is that all divisions a/b are replaced by old_div(a/b) , which I would like to avoid (there is too many, and many of them are replaced unnecessarily, such as math.pi/2. . The documentation says that --nofix (or -x ) can be used to avoid running a certain fixes, but trying --nofix=fix_divison or --nofix=libfuturize.fixes.fix_divison has no

问题 How do I install pip on python 2.4? I've tried downloading the get-pip.py file, but it doesn't run on version 2.4 of python. Is there anyway to edit the file to run it? Or is there another download? 回答1: Python 2.4 was supported through v1.1. Try this: https://pypi.python.org/pypi/pip/1.1 回答2: From the Pip Installation guide: https://pip.pypa.io/en/latest/installing/ Python 2.5 was supported through v1.3.1, and Python 2.4 was supported through v1.1. 来源： https://stackoverflow.com/questions

问题 I have two questions converning metaclasses and multiple inheritance. The first is: Why do I get a TypeError for the class Derived but not for Derived2 ? class Metaclass(type): pass class Klass(object): __metaclass__ = Metaclass #class Derived(object, Klass): pass # if I uncomment this, I get a TypeError class OtherClass(object): pass class Derived2(OtherClass, Klass): pass # I do not get a TypeError for this The exact error message is: TypeError: Error when calling the metaclass bases Cannot

问题 I'm invoking a lambda function from another function and want to take a different action depending on the response, pretty standard stuff. However I get some unexpected behavior, it's probably something obvious, but it is eluding me. I've recreated my example in the simplest possible example any help would be much appreciated. The lambda function def lambda_handler(event, context): return 'Just a string' The code to call the lambda function def invoke_lambda(payload): r = lambda_client.invoke

问题 I'm invoking a lambda function from another function and want to take a different action depending on the response, pretty standard stuff. However I get some unexpected behavior, it's probably something obvious, but it is eluding me. I've recreated my example in the simplest possible example any help would be much appreciated. The lambda function def lambda_handler(event, context): return 'Just a string' The code to call the lambda function def invoke_lambda(payload): r = lambda_client.invoke

问题 Consider the following demo script: # -*- coding: utf-8 -*- from __future__ import division from __future__ import unicode_literals def myDivi(): """ This is a small demo that just returns the output of a divison. >>> myDivi() 0.5 """ return 1/2 def myUnic(): """ This is a small demo that just returns a string. >>> myUnic() 'abc' """ return 'abc' if __name__ == "__main__": import doctest extraglobs = {} doctest.testmod(extraglobs=extraglobs) The doctest passes on Python 3.5, but fails on