python-2.x

I am trying to decode from a Brazilian Portogese text: 'Demais Subfun\xc3\xa7\xc3\xb5es 12' It should be 'Demais Subfunções 12' >> a.decode('unicode_escape') >> a.encode('unicode_escape') >> a.decode('ascii') >> a.encode('ascii') all give: UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 13: ordinal not in range(128) on the other hand this gives: >> print a.encode('utf-8') Demais Subfun├â┬º├â┬Áes 12 >> print a Demais Subfunções 12 Martijn Pieters You have binary data that is not ASCII encoded. The \xhh codepoints indicate your data is encoded with a different codec, and

I was looking at this question and started wondering what does the print actually do. I have never found out how to use string.decode() and string.encode() to get an unicode string "out" in the python interactive shell in the same format as the print does. No matter what I do, I get either UnicodeEncodeError or the escaped string with "\x##" notation... This is python 2.x, but I'm already trying to mend my ways and actually call print() :) Example: >>> import sys >>> a = '\xAA\xBB\xCC' >>> print(a) ª»Ì >>> a.encode(sys.stdout.encoding) Traceback (most recent call last): File "<stdin>", line 1,

I'm having problems supporting python2 and python3 on a type() call. This demonstrates the problem: from __future__ import unicode_literals name='FooClass' type(name, (dict,), {}) No problem on python3, but on python2: Traceback (most recent call last): File "test.py", line 6, in <module> type(name, (dict,), {}) TypeError: type() argument 1 must be string, not unicode This is related to Any gotchas using unicode_literals in Python 2.6? . In that question, someone recommends typecasting to a bytestring, so naively I thought about using six.b() : A “fake” bytes literal. data should always be a

In the past, there's codecs which got replaced by io . Although it seems like it's more advisable to use io.open , most introductory python classes still teaches open . There's a question with Difference between open and codecs.open in Python but is open a mere duck-type of io.open ? If not, why is it better to use io.open ? And why is it easier to teach with open ? In this post ( http://code.activestate.com/lists/python-list/681909/ ), Steven DAprano says that the built in open is using the io.open in the backend. So should we all refactored our code to use open instead of io.open ? Other

This works as expected def outer_func(): from time import * print time() outer_func() I can define nested functions in the context fine and call them from other nested functions: def outer_func(): def time(): return '123456' def inner_func(): print time() inner_func() outer_func() I can even import individual functions: def outer_func(): from time import time def inner_func(): print time() inner_func() outer_func() This, however, throws SyntaxError: import * is not allowed in function 'outer_func' because it contains a nested function with free variables : def outer_func(): from time import *

I want to make a 2d dictionary with multiple keys per value. I do not want to make a tuple a key. But rather make many keys that will return the same value. I know how to make a 2d dictionary using defaultdict: from collections import defaultdict a_dict = defaultdict(dict) a_dict['canned_food']['spam'] = 'delicious' And I can make a tuple a key using a_dict['food','canned_food']['spam'] = 'delicious' But this does not allow me to do something like print a_dict['canned_food]['spam'] Because 'canned_food' is not a key the tuple ['food','canned_food'] is the key. I have learned that I can simply

I have some data in CSV file that are in Russian: 2-комнатная квартира РДТ', мкр Тастак-3, Аносова — Толе би;Алматы 2-комнатная квартира БГР', мкр Таугуль, Дулати (Навои) — Токтабаева;Алматы 2-комнатная квартира ЦФМ', мкр Тастак-2, Тлендиева — Райымбека;Алматы Delimiter is ; symbol. I want to read data and put it into array. I tried to read this data using this code: def loadCsv(filename): lines = csv.reader(open(filename, "rb"),delimiter=";" ) dataset = list(lines) for i in range(len(dataset)): dataset[i] = [str(x) for x in dataset[i]] return dataset Then I read and print result: mydata =