python-2.7

问题 for my distutils package the yaml file along with python files is not getting copied setup.py from distutils.core import setup files = ["*.yaml", "package/*"] setup(name = "mypackage", version = "0.1", description = "description", author = "Ciasto", author_email = "me@email.com", packages = ['package'], package_data = {'package' : files }, scripts = ["scripts/runner"], ) this is the project directory structure: $ tree package/ |____ | |______init__.py | |____command.py | |____constants.py | |

问题 I'm having issues building a Kivy dropdown with word wrapping enabled for the text, such that the button widgets size accordingly to accommodate the full text. I have followed guidance from the stack overflow thread below and similar blog post that is also linked. Wrapping the text of a Kivy Label https://blog.kivy.org/2014/07/wrapping-text-in-kivys-label/ The text wraps as expected, however as the text string gets longer, there is an increasing amount of "padding" above and below the text

问题 Using python 2.7, I want to display the values in tabular format, without using pandas/prettytable. I am a beginner to python and am trying to learn. Below is the values I have in list listA = ["Alpha","Beta","gama","cat"] data = [["A","B","C","D"],["E","F","G","H"],["I","J","K","L"],["M","N","O","P"]] Expected output - to be displayed like below in tabular format : Alpha Beta gama cat A B C D E F G H I J K L M N O P I tried the following code, I am not getting the desired result: def print

问题 Writing a blog engine with Django 1.5 and using the Django Admin. Everything was fine, until I added a ManyToManyField to a model, and added that field to the ModelAdmin's fieldsets, then I started to get this mysterious error when trying to load the admin page: 'NoneType' object has no attribute 'user' (Full stack trace further on below.) Why would the response object suddenly be None? If I remove the field from the fieldset, everything's fine again. My models look something a bit like this

问题 I have a list: f_array=['1000,1','100,10','100,-10'] I am trying to sum up all the first element in each value of the above array. I tried something like: number = sum([ num for num in item.split(",")[1] for item in f_array]) but it dint work. What would be the best way to do it ? 回答1: If you want to use nested loops then need to swap the order of the for loops: number = sum([num for item in f_array for num in item.split(",")[1]]) List comprehension loops are listed in nesting order , left to

问题 My questioon is about cossim usage. I have this fragment of a very big fuction: for elem in lList: temp = [] try: x = dict(np.ndenumerate(np.asarray(model[elem]))) except: if x not in embedDict.keys(): x = np.random.uniform(low=0.0, high=1.0, size=300) embedDict[elem] = x else: x = dict(np.ndenumerate(np.asarray(embedDict[elem]))) for w in ListWords: try: y = dict(np.ndenumerate(np.asarray(model[w]))) except: if y not in embedDict.keys(): y = np.random.uniform(low=0.0, high=1.0, size=300)

问题 I'm having a lot of trouble with this segment of code: command = "!ip" string = "!ip 127.0.0.1" if command in string: That's where I get stuck. After the first if statement I need another one to recognize any IP address just not 127.0.0.1. What's the easiest way of doing this? 回答1: I would give it a shot using regular expressions, where the regular expression (?:[0-9]{1,3}\.){3}[0-9]{1,3} is a simple match for an IP address. ip = '127.0.0.1' match = re.search(r'(?:[0-9]{1,3}\.){3}[0-9]{1,3}',

问题 To start, I created a Network using 2014 flight data as explained here:https://ipython-books.github.io/142-drawing-flight-routes-with-networkx/ I'm trying to create smaller graphs using airline specific flight paths to test connectivity within each business, starting with American Airlines, I did the following: AASys = routes[ routes['source'].isin(airports_us.index) & routes['dest'].isin(airports_us.index) & routes['airline'].str.contains('AA')] AASys AAedges = AASys[['source', 'dest']]

问题 I am trying to write a function that takes two arguments, a string and a letter. The function should then double the number of letter in the string. For example: double_letters("Happy", "p") Happppy what i have done so far; def double_letter(strng, letter): new_word = "" for char in strng: if char == letter: pos = strng.index(char) new_word = letter+strng[pos:] But this is giving me the output: pppy how can i change the function to get the output: Happppy? 回答1: Use string.replace string =

问题 I am trying to get python to open a website URL. This code works. import webbrowser url = 'http://www.example.com/' webbrowser.open(url) I have noticed that python will only open the URL is it has https:// at the beginning. Is it possible to get python to open the URL if it's in any of the formats in the examples below? url = 'http://www.example.com/' url = 'https://example.com/' url = 'www.example.com/' url = 'example.com/' The URLs will be pulled from outside sources so I can't change what