python-2.6

I can see first-class member variables using self.__dict__ , but I'd like also to see a dictionary of properties, as defined with the @property decorator. How can I do this? You could add a function to your class that looks something like this: def properties(self): class_items = self.__class__.__dict__.iteritems() return dict((k, getattr(self, k)) for k, v in class_items if isinstance(v, property)) This looks for any properties in the class and then creates a dictionary with an entry for each property with the current instance's value. The properties are part of the class, not the instance.

My application creates custom URIs (or URLs?) to identify objects and resolve them. The problem is that Python's urlparse module refuses to parse unknown URL schemes like it parses http. If I do not adjust urlparse's uses_* lists I get this: >>> urlparse.urlparse("qqqq://base/id#hint") ('qqqq', '', '//base/id#hint', '', '', '') >>> urlparse.urlparse("http://base/id#hint") ('http', 'base', '/id', '', '', 'hint') Here is what I do, and I wonder if there is a better way to do it: import urlparse SCHEME = "qqqq" # One would hope that there was a better way to do this urlparse.uses_netloc.append

I've had a look at the documentation for both of them. This question is prompted by J.F.'s comment here: Retrieving the output of subprocess.call() The current Python documentation for subprocess.call() says the following about using PIPE for subprocess.call() : Note Do not use stdout=PIPE or stderr=PIPE with this function. The child process will block if it generates enough output to a pipe to fill up the OS pipe buffer as the pipes are not being read from. Python 2.7 subprocess.call() : Note Do not use stdout=PIPE or stderr=PIPE with this function as that can deadlock based on the child

In python 2.6, the following code: import urlparse qsdata = "test=test&test2=test2&test2=test3" qs = urlparse.parse_qs(qsdata) print qs Gives the following output: {'test': ['test'], 'test2': ['test2', 'test3']} Which means that even though there is only one value for test, it is still being parsed into a list. Is there a way to ensure that if there's only one value, it is not parsed into a list, so that the result would look like this? {'test': 'test', 'test2': ['test2', 'test3']} You could fix it afterwards... import urlparse qsdata = "test=test&test2=test2&test2=test3" qs = dict( (k, v if

I use a MS SQL express db. I can connect and fetch data. But inserting data does not work: cursor.execute("insert into [mydb].[dbo].[ConvertToolLog] ([Message]) values('test')") I get no error but nothing is inserted into the table. Directly after I fetch the data the inserted row is fetched. But nothing is saved. In MS SQL Server Management Studio the insertion does work. You need to commit the data. Each SQL command is in a transaction and the transaction must be committed to write the transaction to the SQL Server so that it can be read by other SQL commands. Under MS SQL Server Management

In python 2.6 , I want to do: f = lambda x: if x==2 print x else raise Exception() f(2) #should print "2" f(3) #should throw an exception This clearly isn't the syntax. Is it possible to perform an if in lambda and if so how to do it? thanks The syntax you're looking for: lambda x: True if x % 2 == 0 else False But you can't use print or raise in a lambda. why don't you just define a function? def f(x): if x == 2: print(x) else: raise ValueError there really is no justification to use lambda in this case. You can easily raise an exception in a lambda, if that's what you really want to do. def