putchar

No argument names in abstract declaration?

匿名 (未验证) 提交于 2019-12-03 03:04:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This is the typical declaration of an abstract member in F#: abstract member createEmployee : string -> string -> Employee You define the argument types but not their names. Without names, how do you tell what each parameter is when you implement the interface? In other words, how do you know if the interface expects to be implemented as 1- or 2-? 1- member this.createEmployee firstName lastName = ... 2- member this.createEmployee lastName firstName = ... Am I looking the problem from a wrong perspective (being used to C#)? 回答1: What about:

replace a dynamic shared library in run time

匿名 (未验证) 提交于 2019-12-03 02:48:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I need to use different dynamic library over a execution cycle of a program. Looking at dlfcn.h I thought this was possible. I confess of not reading much literature on dynamic library loading. OK here is what I do - I have created shared library called `libdynamicTest.so.1` The main APP opens this solib ( dlopen ), gets the function pointer ( dlsym ), run it and then close it back ( dlclose ) Everything is fine until here. Now suppose I replace my libdynamicTest.so.1 by another libdynamicTest.so.1 (some code diff) I see a Segmentation fault

读入优化&输出优化

匿名 (未验证) 提交于 2019-12-02 23:48:02
注意了注意了注意了,重要的事情说3遍,这个东西是骗分神器,骗分神器,骗分神器!!! 众所周知:scanf比cin快得多,printf比cout快得多,如果你不知道就……就现在知道了 那有没有更快的呢?当然。 请看: 好吧,这就是读入优化的效果,在数据很恐怖的情况下能比scanf多过1-5个点…… 比如说这种: 都说了要读入优化你还不读入优化,那不是找死吗…… 前面都是废话,现在开始说正事 读入优化 首先,读入优化这里是只是针对整数,getchar读字符是非常快的,所以我们就用getchar了。(下面都假设输入的数为x) 负数处理 很简单,用一个标志变量f,开始时为1,当读入了’-’时,f变为-1,最后x*=f即可 绝对值部分处理 显然getchar每次只能读一位,所以,每当读了一位时x*=10,为这一位“留位置”。 举个例子:现在读入了123,x为123,再读入了一个4,x*=10,变为了1230,现在它的最后一位空出来了,正好留给4,x+=4,x就变为了1234,当然,这里的’4’是char类型,需要减去’0’才是4,即:x=x*10+s-'0'(s为当前输入的字符) 关于细节 很多时候是有多余空格或者其他的乱码字符输入,为了防止bug,我们要严谨~详见代码。 代码 1 void read(int &x)//'&'表示引用,也就是说x是一个实参

putchar() vs printf() - Is there a difference?

女生的网名这么多〃 提交于 2019-12-01 16:55:34
I am currently in chapter 1.5.1 File copying and made a program like so: #include <stdio.h> /* copy input to output; 1st version */ main() { int c; c = getchar(); while (c != EOF) { putchar(c); c = getchar(); } } If I ran it like this: PS <..loc..> cc copy-0.c PS ./a Black Black White White Gray Gray The output is what I input. And here's a program I made for experimental purposes: #include <stdio.h> /* copy input to output; 1st version */ main() { int c; c = getchar(); while (c != EOF) { printf("%c",c); c = getchar(); } } It produces the same result but is there a difference between putchar

Codeforces Round #580 (Div. 1)

不羁岁月 提交于 2019-11-29 02:05:12
Codeforces Round #580 (Div. 1) https://codeforces.com/contest/1205 A. Almost Equal 随便构造一下吧...太水了不说了,放个代码吧。 #include<bits/stdc++.h> using namespace std; void read(int &x) { x=0;int f=1;char ch=getchar(); for(;!isdigit(ch);ch=getchar()) if(ch=='-') f=-f; for(;isdigit(ch);ch=getchar()) x=x*10+ch-'0';x*=f; } void print(int x) { if(x<0) putchar('-'),x=-x; if(!x) return ;print(x/10),putchar(x%10+48); } void write(int x) {if(!x) putchar('0');else print(x);putchar('\n');} #define lf double #define pii pair<int,int > #define vec vector<int > #define pb push_back #define mp make_pair #define fr first

Codeforces Round #549 (Div. 1)

喜你入骨 提交于 2019-11-28 16:10:32
Codeforces Round #549 (Div. 1) https://codeforces.com/contest/1142 A. The Beatles A题随便写写就行了( 直接暴力枚举间距就好了。 #include<bits/stdc++.h> using namespace std; #define int long long void read(int &x) { x=0;int f=1;char ch=getchar(); for(;!isdigit(ch);ch=getchar()) if(ch=='-') f=-f; for(;isdigit(ch);ch=getchar()) x=x*10+ch-'0';x*=f; } void print(int x) { if(x<0) putchar('-'),x=-x; if(!x) return ;print(x/10),putchar(x%10+48); } void write(int x) {if(!x) putchar('0');else print(x);putchar('\n');} #define lf double #define pii pair<int,int > #define vec vector<int > #define pb push_back #define mp make

Why putchar, toupper, tolower, etc. take a int instead of a char?

自古美人都是妖i 提交于 2019-11-28 10:51:58
In C, strings are arrays of char ( char * ) and characters are usually stored in char . I noticed that some functions from the libC are taking as argument integers instead of a char. For instance, let's take the functions toupper() and tolower() that both use int . The man page says: If c is not an unsigned char value, or EOF, the behavior of these functions is undefined. My guess is that with a int , toupper and tolower are able to deal with unsigned char and EOF . But in fact EOF is in practice (is there any rule about its value?) a value that can be stored with a char , and since those

What is the standard input buffer?

邮差的信 提交于 2019-11-28 04:48:56
问题 #include <stdio.h> int main(void) { int c; c = getchar(); putchar(c); c = getchar(); putchar(c); c = getchar(); putchar(c); return 0; } I want to understand why the function that is called three times working with a line that was entered only once. Some guy explained, that we working with the standard input buffer in this situation, and that is a piece of memory. I want to read something about it. Can you advise me some resources? 回答1: This is a feature of your terminal (the command line

HDU - 4417 Super Mario

喜欢而已 提交于 2019-11-28 04:03:40
放个 传送门 开溜 题意 给你一串序列,每次询问L~R范围内小于等于H数字的个数 题解 由于今天我们学的分块,所以被逼用分块 关于分块,蒟蒻不再赘述,推荐一篇讲分块的 blog 还是运用分块的思想,小于bol(bol为每块的长度)的首尾,暴力求ans 中间排好序用STL中的upper_bound统计小于等于H的 完了 注意 卡常是要卡滴,o2是要开的 注意好像原序列从0开始排,所以如果习惯for(int i=1;i<=n;++i),记得L++,R++ CODE #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<cmath> #include<cstring> #include<vector> #include<algorithm> #pragma GCC optimize (2) #pragma G++ optimize (2) #define N 100005 #define rint register int using namespace std; int t,n,m,bol,v[N],bel[N]; vector<int> xl[400]; inline int read() { rint x=0,f=1;char ch=getchar(); while(ch>

getch and putchar not working without return

↘锁芯ラ 提交于 2019-11-28 01:44:50
I have been trying to get getch to work in another program with no success. So I have made the most basic program I can using getch the way I want it to work in the main program. I have researched the need for noecho , cbreak , initscr and nodelay , I have also tried using newscr() but to no success. The problem I am having is that the chars aren't being printed to the screen till I hit "enter", when they should be put to the screen every loop. Why is this happening? Also the cursor doesn't return to the left of the screen at the new line. eg. abc def ghi I have looked for the answer but am