probability

问题 How can I generate a list of 3-digit numbers for which the sum of their digits equal 17? For example assuming number XYZ , we would have X+Y+Z=17 This is how far I got: numbers = list(range(1, 1000)) 回答1: It appears that you want the sum of the digits to be 17 and not the sum of the numbers as the "but I want the first number + the second number + the third number = 17 ?" implies. So, take a look at this: result = [x for x in range(100, 1000) if sum(int(y) for y in str(x))==17] print(result)

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: A weighted version of random.choice Let's say for simplicity a function takes in 4 inputs: 2 names and their respective 'bias/weights', how can I write a function such that it returns either a or b at random but still considers those weights into the random outcome. a = 'x' b = 'y' p_a = 10 p_b = 90 def myRand(a, p_a, b, p_b): return 'x' 10% of the time, 'y' 90% of time What I've done so far import random def

问题 I am trying to plot the PDF and CDF for a biased die roll for 10^4 samples using Central Limit Theorem.(CLT) The die is biased or unfair where even sides are twice as likely as odd sides. Here is the diefaces = [1,3,2,4,6,2].What can I use in Matlab to find probability of an odd number in this case with CLT where Sn = X1 + X2 + ... + Xn , n = 40. Here is what I have tried so far. The part that I am struggling with is passing the samples which in this case is 10^4 and n=40. Appreciate any help

问题 This question is an extension of Java- Math.random(): Selecting an element of a 13 by 13 triangular array. I am selecting two numbers at random (0-12 inclusive) and I wanted the values to be equal. But now, since this is a multiplication game, I want a way to bias the results so certain combinations come up more frequently (like if the Player does worse for 12x8, I want it to come up more frequently). Eventually, I would like to bias towards any of the 91 combinations, but once I get this

问题 Is there any algorithm to achieve this combination of output? Input : arr1 = {x, y, z} arr2 = {a, b} Output : xa, ya, za xa, ya, zb xa, yb, za xa, yb, zb xb, ya, za xb, ya, zb xb, yb, za xb, yb, zb 回答1: static char[] arr1 = {'x', 'y', 'z'}; static char[] arr2 = {'a', 'b'}; public static void main(String[] args) { print(new char[arr1.length - 1], 0); } static void print(char[] store, int depth) { for(char c : arr2) { if(depth < store.length) { store[depth] = c; print(store, depth + 1); } else

问题 I already checked the "Making predictions" documentation of WEKA and it contains explicit instructions for command line and GUI predictions. I want to know how to get a prediction value like the one below I got from the GUI using the Agrawal dataset ( weka.datagenerators.classifiers.classification.Agrawal ) in my own Java code: inst#, actual, predicted, error, prediction 1, 1:0, 2:1, +, 0.941 2, 1:0, 1:0, , 1 3, 1:0, 1:0, , 1 4, 1:0, 1:0, , 1 5, 1:0, 1:0, , 1 6, 1:0, 1:0, , 1 7, 1:0, 2:1, +,

问题 I have a table that shows the probability of an event happening. I'm fine with part 1, but part 2 is not clicking with me. I'm trying to get my head around how the binary numbers are derived in part 2? I understand 0 is assigned to the largest probability and we work back from there, but how do we work out what the next set of binary numbers is? And what do the circles around the numbers mean/2 shades of grey differentiate? It's just not clicking. Maybe someone can explain it in a way that

问题 How do you determine the probability that an intensity value appears in an image in Matlab or is there some other way to determine it? The mathematical equation is Pr = Nk / M*N Where Pr is the probability, Nk is number of times that a Kth intensity appears in the image. M*N represents the MxN image. 回答1: Assuming your intensity values are all integers, you can do what you want as Pr=nnz(img(:)==value)/numel(img); %# here img is your image, value is the intensity What the above code does is

问题 I am trying to generate class scores by calling predict_proba() of Keras model, but it seems that this function does not exist! Is it deprecated because I see some examples in Google? I am using Keras 2.2.2. 回答1: The predict_proba() and predict_classes() methods are not well-defined for models created using functional API (i.e. keras.models.Model() ). That's because the models created using functional API may have multiple output layers each with different configurations. Therefore predicting

问题 You have a function rand(3) which generates random integers from 1 to 3. Using this function, construct another function rand(9) which generates random integers from 1 to 9. 回答1: Using rand(3) twice, one can generate 3^2 pairs of integers, i.e. (1,1), (1,2), ..., (3,3). Assigning each pair to one of the values [1,9] (e.g. (1,1) to 1, (1,2) to 2 etc.) will give you rand(9). Symbolically: rand(9):=(rand(3),rand(3)). 回答2: Here's a simple solution: rand(3) + 3*(rand(3) - 1) The reason why you