prefix

Renaming prefixes of table names within phpmyadmin?

由 一笑奈何 提交于 2019-12-05 02:58:52
Is there a more dynamic way to rename all prefixes in a database within phpmyadmin, rather than manually typing to replace the name for each table? I have about 50 tables to change prefixes on... Maybe I should grab a snickers bar? Thomas Have all the corresponding tables in phpMyadmin ticked and select With Selected.. -> Replace table prefix xngigez Click/open the database. Click Structure at the top bar. This will display all your tables. Note the existing prefix . Scroll to the bottom, to the last table. Click "Check all" . This will check all tables. Click the drop down menu just next to

X-MSG-IM-系统依赖的第三方library编译

由 大憨熊 提交于 2019-12-05 02:15:45
X-MSG-IM系统核心网元编译时依赖较多第三方库, 较为繁琐. 这是为了在部署时更方便, 更少地依赖宿主系统环境. 除非你知道自己在做什么, 否则不要变更这些库的版本. zlib-1.2.11编译 wget http://www.zlib.net/zlib-1.2.11.tar.gz tar -xzvf zlib-1.2.11.tar.gz cd zlib-1.2.11 export CFLAGS="-O3" ./configure --prefix=/home/xzwdev/tools/zlib-1.2.11 --static make;make install libuuid-1.0.3编译 wget https://nchc.dl.sourceforge.net/project/libuuid/libuuid-1.0.3.tar.gz tar -xzvf libuuid-1.0.3.tar.gz cd libuuid-1.0.3 export CFLAGS="-O3" ./configure --prefix=/home/xzwdev/tools/libuuid-1.0.3 make;make install openssl-1.1.1d编译 http://ftp.openssl.org/source/openssl-1.1.1d.tar.gz tar -xzvf

Shell脚本条件测试

由 五迷三道 提交于 2019-12-04 21:09:57
Shell 条件测试 文件测试 数值比较 逻辑判断 字符串比较 正则对比 toc Shell 条件测试 格式1: test 条件表达式 格式2: [ 条件表达式 ] 格式3: [[ 条件表达式 ]] 文件测试 [ -e dir|file ]测试文件或目录是非存在 [ -d dir ] 测试是否存在，而且是目录 [ -f file ] 测试是否存在，而且是文件 [ -r file ] 测试文件是否有读权限 [ -x file ] 测试文件是否有执行权限 [ -w file ] 测试文件是否有写权限 [ -L file ] 测试文件是否是链接文件 [ -b file ] 测试文件是否是块设备 [ -c file ] 测试文件是否是字符设备 [ -s file ] 测试文件是否存在且非空 [ -S file ] 测试文件是否是socket [ file1 -nt file2 ] 第一个文件比第二个文件新 [ file1 -ot file2 ] 第一个文件比第二个文件旧 [ file1 -ef file2 ] 第一个文件与第二个文件是同一个设备inode 命令行使用方式 ## 测试 /soft 目录是否存在，不存在就创建 /soft 目录 [root@Shell ~]# [ ! -d /soft ] && mkdir /soft [root@Shell ~]# [ -d /soft ] |

centos6安装tengine

由 蓝咒 提交于 2019-12-04 17:08:33
1、安装必要的编译环境好 由于Tengine安装需要使用源代码自行编译，所以在安装前需要安装必要的编译工具： # yum update # yum install gcc gcc-c++ autoconf automake 2、安装需要的组件 A、PCRE PCRE(Perl Compatible Regular Expressions)是一个Perl库，包括 perl 兼容的正则表达式库。nginx rewrite依赖于PCRE库，所以在安装Tengine前一定要先安装PCRE，最新版本的PCRE可在官网（http://www.pcre.org/）获取。具体安装流程为： # cd /usr/local/src # wget http://ncu.dl.sourceforge.net/project/pcre/pcre/8.38/pcre-8.38.tar.gz # tar zxvf pcre-8.38.tar.gz # cd pcre-8.38 # ./configure --prefix=/usr/local/pcre # make && make install 附加信息： 源码的安装一般由3个步骤组成：配置(configure)、编译(make)、安装(make install)。 Configure是一个可执行脚本，它有很多选项，在待安装的源码路径下使用命令.

LInux下安装ffmpeg视频转换工具

由 笑着哭i 提交于 2019-12-04 07:58:20
首先要安装各种解码器 1、lame lame-3.97.tar.gz Url： http://sourceforge.net/project/showfiles.php?group_id=290&package_id=309 安装方法如下： Java代码 tar -zxvf lame- 3.97 .tar.gz cd lame- 3.97 ./configure --enable-shared --prefix=/usr make make install 2、libogg libogg-1.1.3.tar.gz Url： http://downloads.xiph.org/releases/ogg/libogg-1.1.3.tar.gz 安装方法如下： Java代码 ./configure --prefix=/usr make make install 3、libvorbis libvorbis-1.1.2.tar.gz Url： http://downloads.xiph.org/releases/vorbis/libvorbis-1.1.2.tar.gz 安装方法如下： Java代码 ./configure --prefix=/usr make make install 4、xvid xvidcore-1.1.3.tar.gz Url： http://downloads

CondaValueError: Value error: prefix already exists:

由 元气小坏坏 提交于 2019-12-04 07:47:33
Reference: https://uoa-eresearch.github.io/eresearch-cookbook/recipe/2014/11/20/conda/ I've run the following commands to install conda and create a virtual environment. Continue reading after code block for my question. C:\Windows\System32>conda -V conda 4.1.11 C:\Windows\System32>conda update conda Fetching package metadata ......... Solving package specifications: .......... Package plan for installation in environment C:\Program Files\Miniconda2: The following packages will be downloaded: package | build ---------------------------|----------------- conda-env-2.6.0 | 0 498 B enum34-1.1.6 |

int b=0,a=1;b= ++a + ++a; what is the value of b? what is the calculation for it? [duplicate]

由 大兔子大兔子 提交于 2019-12-04 07:14:25
问题 This question already has answers here : Why are these constructs using pre and post-increment undefined behavior? (14 answers) Closed 6 years ago . int main() { int b=0,a=1;//initialize a and b b=++a + ++a;// calculate assign the value of b print f("%d",b); return 0; } what is the value of b? and what is the calculation for it? 回答1: This is Undefined Behaviour.Lack of sequence point. For more info have a look here and output-of-multiple-post-and-pre-increments-in-one-statement. 回答2: It would

Spring Security ROLE_ prefix no longer needed?

由 流过昼夜 提交于 2019-12-04 05:57:47
I was investigating on how to create custom role prefix until I realized that it doesn't matter. As long as my role from my db matches something like: <security:intercept-url pattern="/person/myProfile/**" access= "hasRole('BlaBla')" /> And it is not example, in db I literally set up role BlaBla to test and it works. I don't like when I get different behavior - many people had problem of setting up custom prefix to create custom role. What happens in here and should I expect hidden rocks? I have 3.0.7 release. And in my query for authorities I don't have 'default' values... Is it caused by

编译 bzip2

由 本秂侑毒 提交于 2019-12-04 02:03:57
PREFIX=$HOME/usr/local # yumdownloader --source bzip2-devel rpm2cpio bzip2-1.0.6-13.el7.src.rpm | cpio -id tar zxf bzip2-1.0.6.tar.gz patch -p0 < bzip2-1.0.4-saneso.patch patch -p0 < bzip2-1.0.4-cflags.patch cd bzip2-1.0.6 patch -p1 < ../bzip2-1.0.4-bzip2recover.patch make PREFIX=$PREFIX install || exit 1 make clean make -f Makefile-libbz2_so || exit 1 ln -s libbz2.so.1.0.6 libbz2.so.1 ln -s libbz2.so.1 libbz2.so cp libbz2.so.1.0.6 $PREFIX/lib cp -a libbz2.so.1 libbz2.so $PREFIX/lib 来源： https://www.cnblogs.com/hjbreg/p/11827811.html
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