prefix

Find *most* common prefix of strings - a better way?

故事扮演 提交于 2019-12-08 03:24:10
问题 I have a list of keys ['foo_a','foo_b','foo_c','fnord'] All of the similar solutions here assume that you have no fnord 's in your text. I have this code that does the job: def detect_prefix(keys): PCT = 0.70 # cutof pre = '' l = len(keys) for i in range(0, len(max(keys, key=len))): keys = filter(lambda k: k.startswith(pre), keys) cnt = dict() for k in map(lambda k: k[i], keys): cnt.setdefault(k,0) cnt[k] +=1 if cnt[max(cnt)] / float(l) >= PCT: pre += max(cnt) else: break return pre I have a

Jsp 报错 错误 PWC6188: The absolute uri: http://java.sun.com/jsp/jstl/core cannot be resolved in either

我的未来我决定 提交于 2019-12-07 17:25:21
1: <%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %> 问题:编译错误 原因:缺少jstl.jar 和standard.jar 解决方案:在webroot/web-inf/lib(没有则自己创建)下添加(拷贝进)两个包 2: This absolute uri http://java.sun.com/jsp/jstl/core ) cannot be resolved in either web.xml or the jar files deployed with this application 错误 可能性 原因 1 :jstl.jar 版本问题 错误可能性原因2:路径书写不对 解决方案: 修改为 <%@ taglib uri="http://java.sun.com/jstl/core_rt" prefix="c" %> 3:PWC6188: The absolute uri: http://java.sun.com/jsp/jstl/core cannot be resolved in either web.xml or the jar files deployed with this application 解决方案: 异常的原因是不能识别“${XXX}”,解决办法有两种: 一

Android文件上传带参数

风流意气都作罢 提交于 2019-12-07 10:08:39
//返回值 HttpResult可替换成自己想要的类型. public static < T > HttpResult<String> post( final String urlStr, final Map<String, String> params, T body) { String BOUNDARY = UUID. randomUUID ().toString(); // 边界标识 随机生成 String PREFIX = "--" , LINE_END = " \r\n " ; HttpResult<String> result = new HttpResult<>(); File file = (File) body; HttpURLConnection conn = null ; try { URL url = new URL(urlStr); conn = (HttpURLConnection) url.openConnection(); conn.setReadTimeout( 30 * 1000 ); conn.setConnectTimeout( 30 * 1000 ); conn.setDoInput( true ); // 允许输入流 conn.setDoOutput( true ); // 允许输出流 conn.setUseCaches( false )

Prefix vs Suffix Trie in String Matching

喜欢而已 提交于 2019-12-07 09:30:20
问题 I'm not too well-versed about the actual algorithms used in string matching with tries. I'm wondering why there seems to be more focus on suffix tries for string matching rather than prefix tries. Can we not use prefix tries for substring matching also? Put in another way, what are the advantages of suffix tries over prefix tries? 回答1: .retteb era seirt xiferp ,drawkcab daer uoy fI Seriously. Suffix tries allow you to traverse from the beginning of a string. 来源: https://stackoverflow.com

x86 multi-byte NOP and instruction prefix

笑着哭i 提交于 2019-12-07 05:51:32
问题 As a small recall, the x86 architecture defines 0x0F 0x1F [mod R/M] as a multi-byte NOP. Now I'm looking at the specific case of an 8-byte NOP: I have got 0x0F 0x1F 0x84 0x__ 0x__ 0x__ 0x__ 0x__ where the last 5 bytes have got arbitrary values. The third byte, [mod R/M] , split up gives: mod = 10b : argument is reg1 + a DWORD-sized displacement reg2 = 000b : (we don't care) reg1 = 100b : indicates that the argument is instead the SIB byte + a DWORD-sized displacement. Now, as a concrete

SpringCloud-----Zuul的代理转发

我与影子孤独终老i 提交于 2019-12-06 23:58:56
1、Zuul是什么? Zuul即网关,即代理。 2、Zuul的原始代理路径? 服务A:service-a 端口:8001 用户信息接口名称:/user/get 服务B:service-b 端口:8002 Zuul服务:myzuul 端口:9001 IP:192.168.1.250 访问服务A的原始代理路径如下: http://192.168.1.250:9001/service-a/user/get?id=10 最终访问结果: 注意:这个时候暴露了我们的服务名称service-a,其实是很危险的。所以我们需要路由代理 3、zuul代理路由的几种配置方式 方式一: zuul: prefix: /me # 路由前缀 # ignored-services: provider-company # 方法一:忽略服务名称访问 ignored-services: "*" # 方法二:如果微服务比较多,则采用通配符的方式配置,进行忽略 routes: provider-company: /company-proxy/** # 写法一: 左边服务名称、右边服务代理名称 方式二: zuul: prefix: /me # 路由前缀 # ignored-services: provider-company # 方法一:忽略服务名称访问 ignored-services: "*" # 方法二

Renaming prefixes of table names within phpmyadmin?

ぃ、小莉子 提交于 2019-12-06 23:36:28
问题 Is there a more dynamic way to rename all prefixes in a database within phpmyadmin, rather than manually typing to replace the name for each table? I have about 50 tables to change prefixes on... Maybe I should grab a snickers bar? 回答1: Have all the corresponding tables in phpMyadmin ticked and select With Selected.. -> Replace table prefix 回答2: Click/open the database. Click Structure at the top bar. This will display all your tables. Note the existing prefix . Scroll to the bottom, to the

etcd学习之安装与命令

夙愿已清 提交于 2019-12-06 18:10:25
ETCD学习 下载etcd #下载 wget https://github.com/etcd-io/etcd/releases/download/v3.3.18/etcd-v3.3.18-linux-amd64.tar.gz #解压 tar zxvf etcd-v3.3.18-linux-amd64.tar.gz cd etcd-v3.3.18-linux-amd64.tar.gz #复制到用户目录 cp etcd etcdctl /usr/local/bin #赋予执行权限 chmod +x etcd chmod +x etcdctl 启动etcd 本人是作为练习,将etcd暴露在公网,可以直接通过ip访问,一般不建议这么做 ./etcd --listen-client-urls 'http://0.0.0.0:2379' --advertise-client-urls 'http://0.0.0.0:2379' # 后台启动 #nohup etcd --listen-client-urls 'http://0.0.0.0:2379' --advertise-client-urls 'http://0.0.0.0:2379' & 设置V3环境变量(默认V2) export ETCDCTL_API=3 #或者永久设置 vim /etc/profile 在最后添加export

nginx编译安装配置模块大全

人走茶凉 提交于 2019-12-06 17:00:51
使用configure命令配置构建。它定义了系统的各个方面,包括允许nginx用于连接处理的方法。最后,它会创建一个Makefile。 该configure命令支持以下参数: --help 打印帮助信息。 --prefix=path 定义将保留服务器文件的目录。此相同目录还将用于设置的所有相对路径 configure(库源路径除外)和nginx.conf配置文件中。/usr/local/nginx默认情况下设置为目录。 --sbin-path=path 设置nginx可执行文件的名称。此名称仅在安装期间使用。默认情况下,文件名为 prefix/sbin/nginx。 --modules-path=path 定义将在其中安装nginx动态模块的目录。默认情况下使用prefix/modules目录。 --conf-path=path 设置nginx.conf配置文件的名称。如果需要,可以通过在命令行参数中指定nginx来始终使用其他配置文件来启动它 。默认情况下,文件名为 。 -c fileprefix/conf/nginx.conf --error-log-path=path 设置主要错误,警告和诊断文件的名称。安装后,可以始终nginx.conf使用error_log伪指令在配置文件中 更改文件名 。默认情况下,文件名为 prefix/logs/error.log。 --pid

Code igniter prepending db prefix in table aliases

守給你的承諾、 提交于 2019-12-06 09:47:42
I have configured code igniter to use db prefix. At all other places it is working as expected but while creating table aliases it is prepending db prefix. Code is as under:- $this->db->from('table_a'); $this->db->join('table_b', 'table_a.id = table_b.a_id', 'left'); ----- $this->db->join('table_b as tablebAlias', 'table_c.id = tablebAlias.a_id', 'left'); Assuming my dbprefix is set to value 'foo'. Final query which is getting executed is as under:- Select * From foo_table_a left join foo_table_b on foo_table_a.id = foo_table_b.a_id --- left join foo_table_b as tablebAlias on foo_table_c.id =