polygon | 易学教程

fillColor in Google Maps API polygon not working

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I try to create a polygon to cover an area with these code: map.addPolygon(new PolygonOptions() .add(new LatLng(-7.542257, 110.446209), new LatLng(-7.557232, 110.420116), new LatLng(-7.580375, 110.400890), new LatLng(-7.592626, 110.389904), new LatLng(-7.596710, 110.391277), new LatLng(-7.599433, 110.381664), new LatLng(-7.604877, 110.376171), new LatLng(-7.617128, 110.361065), new LatLng(-7.628017, 110.345959), new LatLng(-7.636184, 110.334972), new LatLng(-7.655239, 110.303387), new LatLng(-7.678377, 110.288280), new LatLng(-7.705595, 110.271801), new LatLng(-7.683820, 110.259441), new

Fill Octagon in C#

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问题 I have created a method that draws an octagon, and it works well, as long as the size is 200 or higher public static void FillOctagon(PaintEventArgs e, Color color, int x, int y, int width, int height) { e.Graphics.SmoothingMode = SmoothingMode.AntiAlias; var points = new [] { new Point(((x + width) / 2) - (width / 4), y), //side 1 new Point(x, ((y + height) / 2) - (height / 4)), //side 2 new Point(x, ((y + height) / 2) + (height / 4)), //side 3 new Point(((x + width) / 2) - (width / 4), y +

Find Parallel or Offset SVG path

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问题 I need a parallel SVG path. I have path as 'M0 0 H50 A20 20 0 1 0 100 50 v25 C50 125 0 85 0 85 z'. Let Offset be 2px. Original Path O/P: Path Image Path Segments when further divided: 0: ["M", 0, 0] 1: ["H", 50] 2: ["A", 20, 20, 0, 1, 0, 100, 50] 3: ["V", 75] 4: ["C", 50, 125, 0, 85, 0, 85] Any algorithm or way to find the offset path for individual segments or on whole?? Updated Image: Red lines represent the offset SVG image, I need to get. Example Offset SVG Path 回答1: Algorithmic solution

Finding midlines of polygons using Voronoi diagrams

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问题 I am using the Voronoi diagram-based approach outlined here to find midlines of binary masks of root images. I am using the Python code more or less exactly as described: import skimage.morphology as morphology WHITE = 255 image_bool = binary_mask == WHITE d = morphology.disk(2) img = morphology.binary_closing(image_bool, selem=d) skeleton = morphology.medial_axis(img) Then comes the graphing: I feed the skeletonized image into buildTree, as described in user Gabriel's iPython notebook: https

Is there a better way for handling SpatialPolygons that cross the antimeridian (date line)?

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问题 TL;DR What is the best way in R to handle SpatialPolygons intersecting/overlapping the anti meridian at +/-180° of latitude and cut them into two sections along that meridian? Preface This is going to be a long one, but only because I'm going to include a lot of code and figures for illustration. I'll show you what my goal is and how I normally achieve that and then demonstrate how it all breaks together in a literal edge case. As the title suggests, I already found one possible solution to

save google map polygon to postgreSQL database

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问题 I develop a web-based application where a user will create a polygon on a map and the database will return points of interest. The problem is that the postgreSQL saves the polygon in a different way than google map polygon. So how I can save the user polygon to postgis? I already use google maps v3 api and geojson 回答1: Some code would be useful. In the absence of that here's a best guess generic answer: In general terms you will need to work out how to map (convert) each format to the other.

Android Freehand bitmap cropping

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问题 I know we can crop a bitmap in rectangular shape using: Bitmap.createBitmap(source, x, y, width, height) But I want to know to crop a bitmap in freehand mode or some polygon shape. Its best example can be seen in Jigsaw Puzzle game I have spent a lot of time googling about this but found no help. Can anybody help me in this regard? 回答1: You can use a Path to determine a clip area on your Canvas when drawing a Bitmap . For a full example see: Android - Crop an image from multipoints and also:

How can I form polygons from lines

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问题 I have a bunch of 2-dimensional lines, whose start and end points are known. The lines might occasionally cross each other, or one line might end in the middle of another line. I need to form polygons from this mesh of lines. If necessary, I can ensure that the left side of all lines are inside their polygons. 回答1: What you're describing is what we called "parcelization" or "spaghetti cutting", and then "polygonization" when I worked for GeoVision. Basically you want to cut the lines where

Cut a bounding box using numpy meshgrid python

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问题 I want to create a bounding box out of the following dimensions using meshgrid but just not able to get the right box. My parent dimensions are x = 0 to 19541 and y = 0 to 14394 . Out of that, I want to cut a box from x' = 4692 to 12720 and y' = 4273 to 10117 . However, I am not getting the right bounds. Could someone please help me here? from matplotlib.path import Path xmin, xmax = 4692, 12720 ymin, ymax = 4273, 10117 sar_ver = [(4692, 10117), (12720, 10117), (12658, 4274), (4769, 4273),

Determining the correct origin to rotate a QPolygonF around

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问题 Edit: Added more information. I'd like to rotate a QPolygonF around the origin illustrated below: I'd like this polygon (centre of image is origin - 0, 0 ): To rotate clockwise so that it ends up here: The QPolygonF has points in the same position as the first block in the image above: QPolygonF p1 = QPolygonF() << QPointF(0, 1) << QPointF(4, 1) << QPointF(4, 2) << QPointF(0, 2); I then rotate around what I think is the correct origin ( 2, 2 ): QTransform t; t.translate(2, 2); t.rotate(-90);