points

how can I access to the next point of the series from the tooltip formatter. Because I want to do a sum between both points. Like this.y + next.y. But I don't know how to have an access to the next point. If someone have an answer. Thanks This need to be done in a few steps: get x-index according to x-value: var index = this.series.xData.indexOf(this.x); now get y-value: var nextY = this.series.yData[index+1]; And all you need to do is to sum values, like this: var sum = this.y + nextY; . 来源： https://stackoverflow.com/questions/21578555/how-to-get-next-point-in-highcharts-tooltip

I am trying to add up all the x and y coordiantes respectively from points of ArrayList. public static ArrayList knots = new ArrayList<Point>(); public Point centroid() { Point center = new Point(); for(int i=0; i<knots.size(); i++) { ???????????????????? return center; } How do I find the centroid ?? public Point centroid() { double centroidX = 0, centroidY = 0; for(Point knot : knots) { centroidX += knot.getX(); centroidY += knot.getY(); } return new Point(centroidX / knots.size(), centroidY / knots.size()); } public Point centroid() { Point center = new Point(); int sumofx=0,sumofy=0; for

I have a 3D plot and two points coordinates A(0,0,0) and B(13,-11,19). I just want to plot a visible line connecting this two points ... I tried plot3(0,0,0, 13,-11,19) and other stuff but everything i tried failed miserably. Here's how: % Your two points P1 = [0,0,0]; P2 = [13,-11,19]; % Their vertial concatenation is what you want pts = [P1; P2]; % Because that's what line() wants to see line(pts(:,1), pts(:,2), pts(:,3)) % Alternatively, you could use plot3: plot3(pts(:,1), pts(:,2), pts(:,3)) Admittedly, this might seem a bit counter-intuitive at first, but in the long run it'll make sense

I have to find which points are inside a grid of square cells, given the points coordinates and the coordinates of the bounds of the cells, through two pandas dataframes. I'm calling dfc the dataframe containing the code and the boundary coordinates of the cells (I simplify the problem, in the real analysis I have a big grid with geographical points and tons of points to check): Code,minx,miny,maxx,maxy 01,0.0,0.0,2.0,2.0 02,2.0,2.0,3.0,3.0 and dfp the dataframe containing an Id and the coordinates of the points: Id,x,y 0,1.5,1.5 1,1.1,1.1 2,2.2,2.2 3,1.3,1.3 4,3.4,1.4 5,2.0,1.5 Now I would

My current implementation doesn't show anything on the form even though the collections I thought bounded have data (I checked in debug). Here's some code: public event PropertyChangedEventHandler PropertyChanged; PointCollection imagePoints; public PointCollection ImagePoints { get { return this.imagePoints; } set { if (this.imagePoints != value) { this.imagePoints = value; if (this.PropertyChanged != null) { PropertyChanged(this, new PropertyChangedEventArgs("ImagePoints")); } } } } and the corresponding xaml: <Polygon x:Name="imagePolygon" Points="{Binding ImagePoints}" Stretch="Fill" Fill=

I need to find the 2 points of the visual horizon , of a curved face. I have: XYZ of the 4 corner points XYZ of the 2 curved edge bezier points And I need to calculate either: XY of the 2 horizon points XYZ of the 2 horizon points Note: I got a solution the last time I asked this question, but it only found the extrema of the curves, not the horizon points , which changes based on the position and rotation of both curves in respect to each other. You don't say how your surface is defined, only that it is bounded by two quadratic Bézier curves. There are lots of ways to build such a surface,

I'm trying to draw an arbitrary quadrilateral over an image using the polylines function in opencv. When I do I get the following error OpenCV Error: Assertion failed (p.checkVector(2, CV_32S) >= 0) in polylines, file /tmp/buildd/ros-fuerte-opencv2-2.4.2-1precise-20130312-1306/modules/core/src/d rawing.cpp, line 2065 I call the function as like so, cv2.polylines(img, points, 1, (255,255,255)) Where points is as numpy array as shown below (The image size is 1280x960): [[910 641] [206 632] [696 488] [458 485]] and img is just a normal image that I'm able to imshow. Currently I'm just drawing

I know how to implement n log n closest pair of points algorithm (Shamos and Hoey) for 2D cases (x and y). However for a problem where latitude and longitude are given this approach cannot be used. The distance between two points is calculated using the haversine formula. I would like to know if there is some way to convert these latitudes and longitudes to their respective x and y coordinates and find the closest pair of points, or if there is another technique that can be used to do it. I would translate them to three dimensional coordinates and then use the divide and conquer approach using