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How to miss points in a ZedGraph line graph in C#

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I have bit of code that draws nice line charts in ZedGraph . I can not change the code entirely, but I would like to have some of the lines not have a y value for each point on the x-axis. I can do this in Excel, but I don't know how to in ZedGraph. I create graph with .AddCurve . How do I do this? NaN values should do the trick. If you want to break the line for example between x=1 and x=2, just add a point (1.5, double.NaN). Zedgraph should make the gap by itself. 来源： https://stackoverflow.com/questions/5154848/how-to-miss-points-in-a-zedgraph-line-graph-in-c-sharp

Generator of evenly spaced points in a circle in python

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问题 I am tasked with generating evenly (more or less) spaced points on concentric rings of an invisible circle. The function should take a list of radii, and number of points to plot for a given radius as arguments. For example for a radius of 0 it should plot 1 point at (0,0). For a circle of radius of 1, it should plot 10 points along the circumference of the circle, spaced out by an angle of 2pi/10. For a circle of radius 2, 20 points along the circumference, spaced out by an angle of 2pi/20.

Given a set of points, how do I find the two points that are farthest from each other? [duplicate]

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问题 This question already has answers here : Closed 6 years ago . Possible Duplicate: Greatest linear dimension 2d set of points I could compute the distance between each point and take the largest but that doesn't sound like a very efficient way to do it when there are a large (> 1000) number of points. Note: This is for iPhone so I don't have a ton of processing power. 回答1: You're asking to compute the diameter of the set. The standard technique is to first compute the convex hull, which

OpenCV: How to get inlier points using findHomography()/findFundamental() and RANSAC

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问题 OpenCV does not provide a RANSAC-function per se or at least in such a form that you can just call it and be done with it (e.g. cv::ransac(...) ). All functions/methods that are able to use RANSAC have a flag that enables it. However this is not always useful if you actually want to do something else with the inliers RANSAC computes after you have estimated a homography/fundamental matrix for example create a nice plot in Octave or similar software/library of the points, apply additional

Calculating angle between two points - java

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I need to calculate the angle in degrees between two points, with a fixed point that is connected with the given two points by a line. Here is an image that illustrates what I need: Here is what I have tried so far: public static float GetAngleOfLineBetweenTwoPoints(float x1, float x2, float y1, float y2) { float xDiff = x2 - x1; float yDiff = y2 - y1; return (float) (Math.atan2(yDiff, xDiff) * (180 / Math.PI)); } It's pointless to say that it doesn't provide the correct answer. You can have the following method that calculates the angle in radians using the Math.atan2 method: public static

Finding points on a line with a given distance

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I have a question i know a line i just know its slope(m) and a point on it A(x,y) How can i calculate the points(actually two of them) on this line with a distance(d) from point A ??? I m asking this for finding intensity of pixels on a line that pass through A(x,y) with a distance .Distance in this case will be number of pixels. I would suggest converting the line to a parametric format instead of point-slope. That is, a parametric function for the line returns points along that line for the value of some parameter t. You can represent the line as a reference point, and a vector representing

Algorithm to cover maximal number of points with one circle of given radius

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问题 Let's imagine we have a plane with some points on it. We also have a circle of given radius. I need an algorithm that determines such position of the circle that it covers maximal possible number of points. Of course, there are many such positions, so the algorithm should return one of them. Precision is not important and the algorithm may do small mistakes. Here is an example picture: Input: int n (n<=50) – number of points; float x[n] and float y[n] – arrays with points' X and Y coordinates

Generate a large list of points with no duplicates

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问题 I want to create a large list containing 20,000 points in the form of: [[x, y], [x, y], [x, y]] where x and y can be any random integer between 0 and 1000. How would I be able to do this such that there are no duplicate coordinates [x, y]? 回答1: You could just use a while loop to pad it out until it's big enough: >>> from random import randint >>> n, N = 1000, 20000 >>> points = {(randint(0, n), randint(0, n)) for i in xrange(N)} >>> while len(points) < N: ... points |= {(randint(0, n),

How to miss points in a ZedGraph line graph in C#

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问题 I have bit of code that draws nice line charts in ZedGraph. I can not change the code entirely, but I would like to have some of the lines not have a y value for each point on the x-axis. I can do this in Excel, but I don't know how to in ZedGraph. I create graph with .AddCurve . How do I do this? 回答1: NaN values should do the trick. If you want to break the line for example between x=1 and x=2, just add a point (1.5, double.NaN). Zedgraph should make the gap by itself. 来源： https:/

how to order vertices in a non-convex polygon (how to find one of many solutions)

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I have the same problem as here: how to order vertices in a simple, non-convex polygon but there is no solutions I can use. I have coordinates of points and need to find some polygon. Does not matter that there is more solutions for one list of dots. I need some algorithm to find one of them. Does not matter which one. I really don't know how to solve this. (I have stored coordinates in array and I want to use some algorithm in Javascript) Thanks a lot. First, find the center of the bounding box that contains all of your vertices. We'll call this point C. Sort your list of vertices based on