pi

淘宝网购的Raspberry Pi到货了，是中国版的。同时还购买了一个USBwifi网卡，一个5V2A的适配器，一张8GClass10的SD卡，一个20000mAh的移动电源能提供5V2A输出，一个黄色外壳。 店家将资料放在SD卡中提供。选择其中的Raspbian操作系统刷入SD卡。接到1080p液晶电视上正常启动。配置界面随便弄过了一下。重启进入图形界面。 玩机计划： 将Raspberry Pi做智能家居实验。先安装开源软件实现NAS和Web服务器。为Pi接入一个USB外置硬盘。用c51+温度传感器采集房间温度，再通过Pi的GPIO接口读取c51。 来源： oschina 链接： https://my.oschina.net/u/208024/blog/100747

def pi(): prompt=">>> " print "\nWARNING: Pi may take some time to be calculated and may not always be correct beyond 100 digits." print "\nShow Pi to what digit?" n=raw_input(prompt) from decimal import Decimal, localcontext with localcontext() as ctx: ctx.prec = 10000 pi = Decimal(0) for k in range(350): pi += (Decimal(4)/(Decimal(8)*k+1) - Decimal(2)/(Decimal(8)*k+4) - Decimal(1)/(Decimal(8)*k+5) - Decimal(1)/(Decimal(8)*k+6)) / Decimal(16)**k print pi[:int(n)] pi() Traceback (most recent call last): File "/Users/patrickcook/Documents/Pi", line 13, in <module> pi() File "/Users/patrickcook

One of the challenges on w3resources is to print pi to 'n' decimal places. Here is my code: from math import pi fraser = str(pi) length_of_pi = [] number_of_places = raw_input("Enter the number of decimal places you want to see: ") for number_of_places in fraser: length_of_pi.append(str(number_of_places)) print "".join(length_of_pi) For whatever reason, it automatically prints pi without taking into account of any inputs. Any help would be great :) Why not just format using number_of_places : ''.format(pi) >>> format(pi, '.4f') '3.1416' >>> format(pi, '.14f') '3.14159265358979' And more

I am a python beginner and I want to calculate pi. I tried using the Chudnovsky algorithm because I heard that it is faster than other algorithms. This is my code: from math import factorial from decimal import Decimal, getcontext getcontext().prec=100 def calc(n): t= Decimal(0) pi = Decimal(0) deno= Decimal(0) k = 0 for k in range(n): t = ((-1)**k)*(factorial(6*k))*(13591409+545140134*k) deno = factorial(3*k)*(factorial(k)**3)*(640320**(3*k)) pi += Decimal(t)/Decimal(deno) pi = pi * Decimal(12)/Decimal(640320**(1.5)) pi = 1/pi return pi print calc(25) For some reason this code yields the

How can I write a function which will return pi (π) to a given number of decimal places? Speed is not a concern. I've been looking at http://bellard.org/pi/ , but I still don't understand how to get the nth digit of pi. Alan In calculus there is a thing called Taylor Series which provides an easy way to calculate many irrational values to arbitrary precision. Pi/4 = 1 - 1/3 + 1/5 - 1/7 + ... (from http://www.math.hmc.edu/funfacts/ffiles/30001.1-3.shtml ) Keep adding those terms until the number of digits of precision you want stabilize. Taylor's theorem is a powerful tool, but the derivation

How can I calculate the value of PI using C#? I was thinking it would be through a recursive function, if so, what would it look like and are there any math equations to back it up? I'm not too fussy about performance, mainly how to go about it from a learning point of view. If you want recursion: PI = 2 * (1 + 1/3 * (1 + 2/5 * (1 + 3/7 * (...)))) This would become, after some rewriting: PI = 2 * F(1); with F(i): double F (int i) { return 1 + i / (2.0 * i + 1) * F(i + 1); } Isaac Newton (you may have heard of him before ;) ) came up with this trick. Note that I left out the end condition, to