php4

Can I login to a protected directory via a link?

由 不羁的心 提交于 2019-12-08 14:32:02
问题 I want to create links to pages and content that are in protected directories. I didn't program the protected directories I set them up from the host admin page. I want to be able to give links to user that will take them to page and login as well. Also if there is a way I want to be able to embed content from the protected directories in other places and not have the password box shop up in order to display the content. I am using PHP4 Thanks! 回答1: Depending on the authentication, you can

building a 'simple' php url proxy

由 痴心易碎 提交于 2019-12-08 06:52:38
问题 I need to implement a simple PHP proxy in a web application I am building (Its flash based and the destination service provider doesn't allow edits to their crossdomain.xml file) Can any php gurus offer advice on the following 2 options? Also, I think, but am not sure, that I need to include some header info as well. Thanks for any feedback! option1 $url = $_GET['path']; readfile($path); option2 $content .= file_get_contents($_GET['path']); if ($content !== false) { echo($content); } else { /

PHP - Question about uploading & uploaded image file

由 ◇◆丶佛笑我妖孽 提交于 2019-12-08 02:26:34
问题 I have read the following tutorial "Uploading Files To the Server Using PHP" and have several questions related to the topics. Q1> The tutorial mentions that "Note that PHP must have write access to $uploadDir or else the upload will fail" For me, I only allow the user to upload the file after the user has login to the website. If we set that $uploadDir permission as 777, then everyone can have written permission to that folder. How to avoid this problems? Also I am using WAMP as my testing

Why PHP 4.4.9 throws 'Parse error: syntax error, unexpected T_STATIC'? [closed]

由 坚强是说给别人听的谎言 提交于 2019-12-07 05:51:16
问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 6 years ago . I just realized the professor Google is unable to present a specific page where I can find out, when static keyword added to PHP 4. Though following the

truly unique random number generate by php?

由 不打扰是莪最后的温柔 提交于 2019-12-06 16:59:00
问题 I'm have build an up php script to host large number of images upload by user, what is the best way to generate random numbers to image filenames so that in future there would be no filename conflict? Be it like Imageshack. Thanks. 回答1: Keep a persistent list of all the previous numbers you've generated(in a database table or in a file) and check that a newly generated number is not amongst the ones on the list. If you find this to be prohibitively expensive, generate random numbers on a

Failed to validate oauth signature and token

由 好久不见. 提交于 2019-12-06 13:17:17
问题 For reasons beyond my control I am using PHP4 to write a twitter client. Requests don't work properly - I am having a tough time seeing what's wrong. Any ideas? I have grabbed the code and banged it in a very simple script here to illustrate essentially what's going on. I've hidden OAuth keys for security purposes. <?php $requestTokenURL = 'https://api.twitter.com/oauth/request_token'; $consumerKey = 'fLxA6J1111111111PnvVOg'; $consumerSecret = 'H5QxDHAOHn1111111111111Ozet1HRTtVAV1FM3oYk';

Codeigniter Call to a member function set_userdata() on a non-object

由 偶尔善良 提交于 2019-12-06 06:06:40
I am getting a fatal error in a CI app that I just moved from a php4 shared host to a php5 shared host. Fatal error: Call to a member function set_userdata() on a non-object in /home/chuck_ravenna/bob.ravennainteractive.com/system/application/helpers/authenticate_helper.php on line 13 Code in full located in the link below https://gist.github.com/1474173 I am trying to figure out if the php version could be the issue. The site runs fine on the old server, and the new server doesn't have php4 as an option. The specific code line thats breaking is: $this->session->set_userdata("admin", $user[0][

PHP - Question about uploading & uploaded image file

由 拥有回忆 提交于 2019-12-06 04:35:55
I have read the following tutorial " Uploading Files To the Server Using PHP " and have several questions related to the topics. Q1> The tutorial mentions that "Note that PHP must have write access to $uploadDir or else the upload will fail" For me, I only allow the user to upload the file after the user has login to the website. If we set that $uploadDir permission as 777, then everyone can have written permission to that folder. How to avoid this problems? Also I am using WAMP as my testing bed, can I simulate the same case as a real web server? Q2> In order to prevent Preventing direct

Cannot re-assign $this?

由 孤人 提交于 2019-12-06 00:18:20
I have a script on a server that had php version 4. Now it is changed to php5 and the script does not function any more. I get this error: Fatal error: Cannot re-assign $this in URL database.php line 88 In the file is a class that has a function. Inside is the line 88: $this = new $db( $serv, $user, $pass, $dbName ); What does the error mean and how can I change it? $this is a special "variable" that always refers to the object the current function is executing in. It only makes sense inside functions that belong to a class ; however, you are not allowed to use it anywhere else, and you may

Why PHP 4.4.9 throws 'Parse error: syntax error, unexpected T_STATIC'? [closed]

由 孤街浪徒 提交于 2019-12-05 11:41:02
This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center . Closed 6 years ago . I just realized the professor Google is unable to present a specific page where I can find out, when static keyword added to PHP 4. Though following the change log for php 4 I can see that it was available since Version 4.0.6 (or before) but why does it
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