php-password-hash

I am trying out a new function from PHP 5.5 called password_hash(). No matter what i do the $hash and the $password wont match. $password = "test"; $hash = "$2y$10$fXJEsC0zWAR2tDrmlJgSaecbKyiEOK9GDCRKDReYM8gH2bG2mbO4e"; if (password_verify($password, $hash)) { echo "Success"; } else { echo "Error"; } The problem with your code is that you are using the double quotation marks " instead of the single quotation marks ' when dealing with your hash. When assigning: $hash = "$2y$10$fXJEsC0zWAR2tDrmlJgSaecbKyiEOK9GDCRKDReYM8gH2bG2mbO4e"; It's making php think you have a variable called $2y and

I'm making a login system, and I want to hash the passwords to make them more secure, but it returns a different hash every time, and can't even be verified using password_verify(), here is my code: $password = password_hash($password4, PASSWORD_DEFAULT); and here is my code for verifying: if(password_verify($password4, $dbpassword)) So let's take it one part at a time but it returns a different hash every time That's the idea. password_hash is designed to generate a random salt every time. This means you have to break each hash individually instead of guessing one salt used for everything and

My registration script accepts a user's password and then uses PHP's password_hash function to encrypt the password, then places it in a database. When I go to login using the just created user, I'm getting the error that checks if the passwords are the same or not. In my case, they're not. What am I doing wrong when I make the call to the password_verify function in the login script? REGISTER if($_SERVER["REQUEST_METHOD"] == "POST"){ function secure($data){ $data = trim($data); $data = stripslashes($data); $data = htmlspecialchars($data); return($data); } $p_num = secure($_POST["p_number"]);