performance

问题 Hi is there a better and faster way to clean many characters from beginning of a string? I have this one, but is this really the fastest way? $description_new = ltrim($description_new, '###'); $description_new = ltrim($description_new, '.'); $description_new = ltrim($description_new, ','); $description_new = ltrim($description_new, '!'); $description_new = ltrim($description_new, '?'); $description_new = ltrim($description_new, ')'); $description_new = ltrim($description_new, '('); Thanks Nik

问题 Hi is there a better and faster way to clean many characters from beginning of a string? I have this one, but is this really the fastest way? $description_new = ltrim($description_new, '###'); $description_new = ltrim($description_new, '.'); $description_new = ltrim($description_new, ','); $description_new = ltrim($description_new, '!'); $description_new = ltrim($description_new, '?'); $description_new = ltrim($description_new, ')'); $description_new = ltrim($description_new, '('); Thanks Nik

问题 The old way of doing it let min = Number.MAX_VALUE; for (let item of food) { let current = Problem.manhattan_distance(player, item); if (current > min){ min = current; this.goal = item; } } From the code you can see that after the for cycle has ended in the this.goal variable we will have the food item with the lowest Manhattan distance. Note: Problem.manhattan_distance(player, item) returns an integer I want to achieve the same result using JavaScript functional programming maybe something

问题 The old way of doing it let min = Number.MAX_VALUE; for (let item of food) { let current = Problem.manhattan_distance(player, item); if (current > min){ min = current; this.goal = item; } } From the code you can see that after the for cycle has ended in the this.goal variable we will have the food item with the lowest Manhattan distance. Note: Problem.manhattan_distance(player, item) returns an integer I want to achieve the same result using JavaScript functional programming maybe something

问题 Want to measure the performance of a web application for mobile devices (designed in Microsoft PowerApps) from my android and iOS devices. Basically, I am more interested towards the UI performance KPI's and response time from page to page. Want to perform this from the devices not with simulator. Is there any open source platform which can be installed on the mobile devices to achieve this, any suggestion or any work around for this? Couldn't find any similar post. 回答1: To measure key web

问题 I am new to R and I am trying to build a frequency/severity simulation. Everything is working fine except that it takes about 10min to do 10000 simulations for each of 700 locations. For the simulation of one individual location, I got a list of vectors with varying lengths and I would like to efficiently rbind these vectors, filling in NAs for all non-existing values. I would like R to return a data.frame to me. So far, I used rbind.fill.matrix after converting the vectors in the list to

问题 I am new to R and I am trying to build a frequency/severity simulation. Everything is working fine except that it takes about 10min to do 10000 simulations for each of 700 locations. For the simulation of one individual location, I got a list of vectors with varying lengths and I would like to efficiently rbind these vectors, filling in NAs for all non-existing values. I would like R to return a data.frame to me. So far, I used rbind.fill.matrix after converting the vectors in the list to

问题 I am using Exoplayer with ViewPager2. Home Fragment.java public class HomeFragment extends Fragment { View view; @Nullable @Override public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) { view= inflater.inflate(R.layout.fragment_home, container, false); ViewPager2 verticalViewPager = view.findViewById(R.id.vPager); verticalViewPager.setOrientation(ViewPager2.ORIENTATION_VERTICAL); ArrayList<VideoDataModel> dataset = new

问题 Here is my code import numpy as np import time from scipy.spatial import distance y1=np.array([0,0,0,0,1,0,0,0,0,0]) y2=np.array([0. , 0.1, 0. , 0. , 0.7, 0.2, 0. , 0. , 0. , 0. ]) start_time = time.time() for i in range(1000000): distance.sqeuclidean(y1,y2) print("--- %s seconds ---" % (time.time() - start_time)) ---15.212640523910522 seconds--- start_time = time.time() for i in range(1000000): np.sum((y1-y2)**2) print("--- %s seconds ---" % (time.time() - start_time)) ---8.381187438964844--

问题 Here is my code import numpy as np import time from scipy.spatial import distance y1=np.array([0,0,0,0,1,0,0,0,0,0]) y2=np.array([0. , 0.1, 0. , 0. , 0.7, 0.2, 0. , 0. , 0. , 0. ]) start_time = time.time() for i in range(1000000): distance.sqeuclidean(y1,y2) print("--- %s seconds ---" % (time.time() - start_time)) ---15.212640523910522 seconds--- start_time = time.time() for i in range(1000000): np.sum((y1-y2)**2) print("--- %s seconds ---" % (time.time() - start_time)) ---8.381187438964844--