percentage

问题 I want to get a percentage of a particular value in a df column. Say I have a df with (col1, col2 , col3, gender) gender column has values of M or F. I want to get the percentage of M and F values in the df. I have tried this, which gives me the number M and F instances, but I want these as a percentage of the total number of values in the df. df.groupby('gender').size() Can someone help? 回答1: Use value_counts with normalize=True : df['gender'].value_counts(normalize=True) * 100 回答2: If you

问题 Alright, I'm trying to calculate the percentage of two values. This should be really simple but for some weird reason it's not working. I'm too tired/dumb to figure it out. Here's my code, it keeps returning 0, i checked the values while debugging and with FilesCompleted being 295 and TotalFilesCount being 25002 the returnvalue var is just 0, it should be 1 already. private int CalculatePercentComplete(int FilesCompleted, int TotalFilesCount) { int returnvalue = (FilesCompleted /

问题 I have read a lot of articles on this topic (and searched for Q&A), and I have found, but I still don't understand what the difference between em units and percents is. Help? P.S. I've seen this code example: p { font-size: 10px; } p { line-height: 120%; } /* 120% of 'font-size' */ What is that supposed to mean? Why on earth would anyone want to set a line height to a percentage value of a font size? 回答1: OK, so I've decided to sum up the answers. line-height's percentage value is relative to

问题 We have a very data intensive system. It stores raw data, then computes percentages based on the number of correct responses / total trials. Recently we have had customers who want to import old data into our system. I need a way to covert a percentage to the nearest fraction. Examples. 33% needs to give me 2/6. EVEN though 1/3 is .33333333 67% needs to give me 4/6. EVEN though 4/6 is .6666667 I realize I could just compute that to be 67/100, but that means i'd have to add 100 data points to

问题 I'm making a portfolio website that contains a simple dropdownlist and one big GIF image in a div (10659px × 6850px). As I intended, when you make selections from the list, you jump to certain anchor points on the page using a simple javascript that's being activated onChange. The html: <div id="background"> <img src="img/background.gif" width="10659" /></div> <select id="dropdownlist" onChange="jumpScroll(this.value);"> <option alt="selected works" value="0">Selected works:</option> <option

问题 First up, for extreme clarity, here a JS fiddle demonstrating what I'm trying to achieve: http://jsfiddle.net/bb_matt/VsH7X/ Here's the explanation - my rationale: I'm creating a responsive site using the 1140 grid framework. It's a fairly complex layout. I've created a re-usable simple gallery class which can drop into any defined column size & using media queries, I apply relevant percentage widths to the li elements. Each of the li elements has a right margin of 5%. I'm using nth-child(xn

问题 how do I determine the positions in percentages? $(document).ready(function(){ $("#button").toggle(function(){ $("#slide").animate({top:-100%},1000); },function(){ $("#slide").animate({top:0%},1000); }); }); Please suggest. 回答1: $(document).ready(function(){ $("#button").toggle(function(){ $("#slide").animate({top:'-100%'},1000); },function(){ $("#slide").animate({top:'0%'},1000); }); }); Add quotes. (I used single quotes, but js doesn't care if it is ' or ") 来源： https://stackoverflow.com

问题 I have a dataframe and want to use pct_chg method to calculate the % change between only 2 of the selected columns, B and C, and put the output into a new column. the below code doesnt seem to work. can anyone help me? df2 = pd.DataFrame(np.random.randint(0,50,size=(100, 4)), columns=list('ABCD')) df2['new'] = df2.pct_change(axis=1)['B']['C'] 回答1: Try: df2['new'] = df2[['B','C']].pct_change(axis=1)['C'] 回答2: pct_change returns pct_change across all the columns, you can select the required

问题 I have a database and I want to create a table with COUNT function in it. Is it possible ? I have 3 existing tables: Member Feedback Attendance In Feedback table, 2 columns Class_ID, Likes (Class_ID link with the attendance, as each member attend 1 class eg. class 1,2,3,etc. and Likes is for the number of people like the class). In Attendance table, 3 columns: Class_ID Member_ID Non_member_name Now I want to alter Feedback table to add 2 new columns. One to count the number of people attend

问题 I've already have my vector and number of zeros and ones with this code: u=[1 1 1 1 1 0 0 0 1 1 0 0 0 0 0 0 0 1 1 1 1 1 0 0 0] transitions=(find(u~=[u(2:end), u(end)+1])); value=u(transitions) transitions(2:end)=transitions(2:end)-transitions(1:end-1) i get this value = 1 0 1 0 1 0 transitions = 5 3 2 7 5 3 Now, please if someone could help me and explain how I can get percentage of ones and percentage of zeros in my vector (all together, and by each value). Thank You very much. 回答1: If I