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问题 After I do: $temp = tmpfile(); fwrite($temp, "writing to tempfile"); I'd like to get a full path to the $temp file that tmpfile has created. What do I need to do to get that information? 回答1: $path = tempnam(sys_get_temp_dir(), 'prefix'); See this example. 回答2: tmpfile returns a stream-able file pointer. To get the corresponding path, ask the stream for its meta data: $file = tmpfile(); $path = stream_get_meta_data($file)['uri']; // eg: /tmp/phpFx0513a The benefit of the tmpfile approach? PHP

问题 In a batch, specifying a path whose name contains an accented character, files are not being found into the file System while stripping out all accented character in the path, these files are found. Nevertheless, I have to manage paths written with accented character. Is there any way to solve this issue? If you need to know my OS, I'm on SEVEN 32. Thanks 回答1: Batch by default configuration can't print unicode characters but CAN recognize that chars and use it. That means you can't print "ú"

问题 Below is my .bashrc file # ~/.bashrc: executed by bash(1) for non-login shells. # see /usr/share/doc/bash/examples/startup-files (in the package bash-doc) # for examples $export=$PATH:./home/ssrp/workspace/android-sdk-linux/platform-tools $export PATH=$PATH:./home/ssrp/workspace/android-sdk-linux/tools $export JAVA_HOME=./usr/lib/jvm/java-6-openjdk $export NDK=./home/ssrp/workspace/android-ndk-r9 # If not running interactively, don't do anything [ -z "$PS1" ] && return # don't put duplicate

问题 Now, I set path variable path : D:..;C:\Program Files\Google\Chrome\Application Chrome : C:\Program Files\Google\Chrome\Application\chromedriver.exe I can call open Chrome in command line. But error when run in RIDE FAIL : WebDriverException: Message: unknown error: Chrome failed to start: crashed (Driver info: chromedriver=2.13.307647 (5a7d0541ebc58e69994a6fb2ed930f45261f3c29),platform=Windows NT 6.1 SP1 x86) 回答1: You need chromeDriver not Chrome. Start by downloading the chrome driver.

问题 Path p1 = Paths.get("/Users/jack/Documents/text1.txt"); Path p2 = Paths.get("/Users/jack/text2.txt"); Path result1 = p1.resolve(p2); Path result2 = p1.relativize(p2); System.out.println("result1: "+result1); System.out.println("result2: "+result2); OUTPUT result1: /Users/jack/text2.txt result2: ../../text2.txt I cannot understand how resolve() and relativize() works? What is the actual use of result1 and result2 ? 回答1: These are the code snippets from my code base that help you to understand

问题 I am starting to get into R development and I was following a tutorial that in a certain point opens the "X11" to display graphics but when that window opens I get the following error: Error in axis(side = side, at = at, labels = labels, ...) : could not find any X11 fonts Check that the Font Path is correct. In addition: Warning messages: 1: In function (display = "", width, height, pointsize, gamma, bg, : locale not supported by Xlib: some X ops will operate in C locale 2: In function

问题 I am a student developer and I have built several installers for the company I am working with now. So I am fairly familiar with WIX. We recently decided to have a Build server that auto builds our solution. It builds both debug, and release, as well as Obfuscated (and non obfuscated) projects. And you really don't have to understand any of this. All you have to understand is that I have the same Wix project building different MSIs dynamically. So the way we build them is we call MSBuild.exe

问题 If I have a list of FilePaths , how can I filter them to return only the ones that are regular files (namely, not symlinks or directories)? For example, using getDirectoryContents main = do contents <- getDirectoryContents "/foo/bar" let onlyFiles = filterFunction contents in print onlyFiles where "filterFunction" is a function that returns only the FilePaths that represent files. The answer may just work on Linux, but cross platform support is preferred. [EDIT] Just using doesDirectoryExist

问题 from pack.mod import f How to get from object f information about import - 'pack.mod' I can get it using f.__module__ but if function def in module where i get this attribute ( f.__module__ ) it return '__main__' . But i need real path here - 'pack.mod' I found this way to get this information: inspect.getmodule(f).__file__ then i can sub start path from sys.path , replace / on . and get path like - 'pack.mod' But may be exist some more convenient way? 回答1: What inspect.getmodule(f) does

问题 I want to export my database and i am using this code: mysqldump -p -u markazo_b markazo_b > /tmp/file.sql But SSH show this error: -bash: mysqldump: command not found How i fix this problem? 回答1: The solution I found is adding MySql's installation directory to PATH Steps: 1. Find where MySql is installed 2. Add the bin directory of MySql installation to PATH (In the terminal), locate mysqldump export PATH=$PATH:MY_SQL_INSTALLATION_DIRECTORY/bin MY_SQL_INSTALLATION_DIRECTORY is the directory