path

问题 On some input we allow the following paths: C:\Folder \\server\Folder http://example.com/... I wonder if I can mark them all as "URI"s? Thanks! 回答1: C:/Folder and /server/Folder/ are file paths. http://example.com/ is a URL, which is a URI sub-type, so you could mark it as a URI but not the other way around (like how squares are rectangles but not vice versa). Of course, here you have posted a clear, simple example. When discussing the distinction between URI and URL, not only is the answer

问题 What is the best way to combine a path with a filename? That is, given c:\foo and bar.txt , I want c:\foo\bar.txt . Given c:\foo and ..\bar.txt , I want either an error or c:\foo\bar.txt (so I cannot use Path.Combine() directly). Similarly for c:\foo and bar/baz.txt , I want an error or c:\foo\baz.txt (not c:\foo\bar\baz.txt ). I realize, I could check that the filename does not contain '\' or '/', but is that enough? If not, what is the correct check? 回答1: If you want "bad" filenames to

问题 Im adventuring at Java so Im building a minesweeper. The mechanics are done now I want to make it some user friendly. Tried to add an ImageIcon to a button on everyway but I cant do it! I dont know how Java works on this! Im doing this: (suppose this is extending a JButton) super(new ImageIcon("/minesweeper/resources/bomb.png")); I have packages like this: minesweeper minesweeper.components minesweeper.resources (trying to organize images here) test (some stuff for testing only) Am I doing it

问题 Im adventuring at Java so Im building a minesweeper. The mechanics are done now I want to make it some user friendly. Tried to add an ImageIcon to a button on everyway but I cant do it! I dont know how Java works on this! Im doing this: (suppose this is extending a JButton) super(new ImageIcon("/minesweeper/resources/bomb.png")); I have packages like this: minesweeper minesweeper.components minesweeper.resources (trying to organize images here) test (some stuff for testing only) Am I doing it

问题 I have to ask again because no one answered my question before (my problem is NOT a duplicate of How to draw a path on an Android canvas with animation?). Please read it carefully and help me, if possible by providing code. The abouve example is unclear for me, and the Path is created on the flow of drawing. This is NOT what I am looking for... I want to draw ONE Path, that already exist in my View class, by drawing its points with time interval, to simulate an animation. How should I modify

问题 I use Inno Setup 5 to create an ini file with {app} as the destination: [INI] Filename: "{userdocs}\JavaCppDemo.ini"; Section: "InstallSettings"; Flags: uninsdeletesection Filename: "{userdocs}\JavaCppDemo.ini"; Section: "InstallSettings"; Key: "InstallPath"; String: "{app}" Then I use ini4j to get the value of InstallPath: String DefaultFolder = new FileChooser().getFileSystemView().getDefaultDirectory().toString(); // tricky way of getting at user/documents folder String strFileName =

问题 I am trying to list all the .hpp files but those whose path contain a word, for example : find -name '*.hpp' would give folder1/folder2/something.hpp folder1/folder3/something.hpp folder1/folder4/something.hpp I'd like to exclude the files in the folder2 in order to have only these : folder1/folder3/something.hpp folder1/folder4/something.hpp 回答1: Just negate a -path condition: find -name '*.hpp' -not -path '*/folder2/*' To exclude several directories, either repeat the condition: find -name

问题 Let's say for instance I have this scenario C:\Users\Name\Documents\Workspace\Project\Src\Com\Name\Foo.java Public class Foo { public Foo() { Bar b = new Bar(); b.method(); } } Then lets say that class Bar is in a .JAR file that's being used as a library, is it possible to figure out where the class that called method() was from? (in this case, the Foo class) I've done a little looking around Google and can't find anything, and this code would definately simplify my library quite a bit. 回答1:

问题 I am calling a Perl script from cygwin. The issue that I am having is that when it calls $ENV{PATH}, the path is receives is a unix path. How do I change my shell so it returns a DOS path? 回答1: Cygwin is a Unix-emulation environment for Windows. It wouldn't work unless $PATH was a Unix-style path. If you want perl to give you a DOS path, use a DOS-compatible Perl, like Strawberry Perl. You can even run Strawberry Perl (or whatever Windows-build of perl you use) from Cygwin if you want to. 回答2

问题 When using dumpbin to view details on my library: dumpbin /headers Test.dll I see that {{FullFolder to Test.pdb}} is the full folder to the pdb. Debug Directories Time Type Size RVA Pointer -------- ------- -------- -------- -------- 95BA9373 cv A1 000199D4 17BD4 Format: RSDS, {4AF64893-BAF4-4FF3-9343-E8D5A55E94FF}, 1, {{FullFolder to Test.pdb}} 00000000 repro 0 00000000 0 Is there a way to exclude this in the csproj file ? My .csproj looks like: <DebugType>full</DebugType> <IncludeSource