parsefloat

parseFloat rounding

由 家住魔仙堡 提交于 2019-11-27 08:33:32
I have javascript function that automatically adds input fields together, but adding numbers like 1.35 + 1.35 + 1.35 gives me an output of 4.050000000000001, just as an example. How can I round the total to the second decimal instead of that long string? The input fields will have more than just the 1.35 example so I need the total to never have more than 2 points after the decimal. Here is the full working code: <html> <head> <script type="text/javascript"> function Calc(className){ var elements = document.getElementsByClassName(className); var total = 0; for(var i = 0; i < elements.length; +

Javascript parse float is ignoring the decimals after my comma

由 假装没事ソ 提交于 2019-11-26 18:52:43
Here's a simple scenario. I want to show the subtraction of two values show on my site: //Value on my websites HTML is: "75,00" var fullcost = parseFloat($("#fullcost").text()); //Value on my websites HTML is: "0,03" var auctioncost = parseFloat($("#auctioncost").text()); alert(fullcost); //Outputs: 75 alert(auctioncost); //Ouputs: 0 Can anyone tell me what I'm doing wrong? This is "By Design". The parseFloat function will only consider the parts of the string up until in reaches a non +, -, number, exponent or decimal point. Once it sees the comma it stops looking and only considers the "75"

Are there are any side effects of using this method to convert a string to an integer

由 天涯浪子 提交于 2019-11-26 17:53:36
Are there any side effects if i convert a string to a number like below.. var numb=str*1; If I check with the below code it says this is a number.. var str="123"; str=str*1; if(!isNaN(str)) { alert('Hello'); } Please let me know if there are any concerns in using this method.. Rob W When you use parseFloat , or parseInt , the conversion is less strict. 1b5 -> 1. Using 1*number or +number to convert will result in NaN when the input is not valid number. Though unlike parseInt , floating point numbers will be parsed correctly. Table covering all possible relevant options. //Variables // parseInt

parseFloat rounding

由 只谈情不闲聊 提交于 2019-11-26 14:11:45
问题 I have javascript function that automatically adds input fields together, but adding numbers like 1.35 + 1.35 + 1.35 gives me an output of 4.050000000000001, just as an example. How can I round the total to the second decimal instead of that long string? The input fields will have more than just the 1.35 example so I need the total to never have more than 2 points after the decimal. Here is the full working code: <html> <head> <script type="text/javascript"> function Calc(className){ var

Is NaN equal to NaN?

由 孤人 提交于 2019-11-26 06:39:17
问题 parseFloat(\"NaN\") returns \"NaN\", but parseFloat(\"NaN\") == \"NaN\" returns false. Now, that\'s probably a good thing that it does return false, but I don\'t understand how this is so. Did the JavaScript creators just make this a special case? Because otherwise I can\'t understand how this returns false. 回答1: When a JavaScript function returns NaN , this is not a literal string but an object property in the global space. You cannot compare it to the string "NaN" . See https://developer

Javascript parse float is ignoring the decimals after my comma

由 一世执手 提交于 2019-11-26 05:58:37
问题 Here\'s a simple scenario. I want to show the subtraction of two values show on my site: //Value on my websites HTML is: \"75,00\" var fullcost = parseFloat($(\"#fullcost\").text()); //Value on my websites HTML is: \"0,03\" var auctioncost = parseFloat($(\"#auctioncost\").text()); alert(fullcost); //Outputs: 75 alert(auctioncost); //Ouputs: 0 Can anyone tell me what I\'m doing wrong? 回答1: This is "By Design". The parseFloat function will only consider the parts of the string up until in
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