parseexception

This question already has an answer here: Converting ISO 8601-compliant String to java.util.Date 26 answers Java - SimpleDateFormat formatter to return epoch time with milliseconds [duplicate] 6 answers I have date in the format "yyyy-MM-dd'T'HH:mm:ss.sssZ". for example the date is "2018-07-17T09:59:51.312Z". I am using the below code to parse the String in Java. String date="2018-07-17T09:59:51.312Z"; SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.sssZ"); Date transactionDateTime = simpleDateFormat.parse(date); This is giving me "Unparseable date:" Exception.

I get the following error: ´java.text.ParseException: Unparseable date: "Aug 31 09:53:19 2011"´ with this format: new SimpleDateFormat("MMM dd HH:mm:ss yyyy"); Does anyone see the problem? Make sure you're using the correct locale. (The SimpleDateFormat(String) constructor uses the system default locale , which may not be the one you want to use.) This works fine on my machine: String input = "Aug 31 09:53:19 2011"; DateFormat df = new SimpleDateFormat("MMM dd HH:mm:ss yyyy", Locale.US); System.out.println(df.parseObject(input)); (While using Locale.FRENCH for instance, results in a

I am getting a parsing exception while I am trying the following code: String date="Sat Jun 01 12:53:10 IST 2013"; SimpleDateFormat sdf=new SimpleDateFormat("MMM d, yyyy HH:mm:ss"); Date currentdate; currentdate=sdf.parse(date); System.out.println(currentdate); Exception: Exception in thread "main" java.text.ParseException: Unparseable date: "Sat Jun 01 12:53:10 IST 2013" at com.ibm.icu.text.DateFormat.parse(DateFormat.java:510) Input: Sat Jun 01 12:53:10 IST 2013 Expected output: Jun 01,2013 12:53:10 How to solve this? assylias Your pattern does not correspond to the input string at all... It