parentheses

Regular expression for math operations with parentheses

由 社会主义新天地 提交于 2019-11-27 16:31:15
In java, I'm trying to write a regular expression that will match a unit within a mathematical expression, i.e. things that are between operators What I mean is, in an expression like 1 + [1 + 2], the regex should match the first 1 and then the [1 + 2]. What I have is *[([-+]?\d+(\.\d+)?)(\[.+\])] * Of which ([-+]?\d+(\.\d+)?) is supposed to match any number and (\[.+\]) Is supposed to match something inside parentheses, but it isn't working...it's matching things like ']' and ' ' for some reason. Any help would be great :) Unfortunately this is part of an exercise and so I can only use the

parsing nested parentheses in python, grab content by level

由 我只是一个虾纸丫 提交于 2019-11-27 14:23:26
Apparently this problem comes up fairly often, after reading Regular expression to detect semi-colon terminated C++ for & while loops and thinking about the problem for a while, i wrote a function to return the content contained inside an arbitrary number of nested () The function could easily be extended to any regular expression object, posting here for your thoughts and considerations. any refactoring advice would be appreciated (note, i'm new to python still, and didn't feel like figuring out how to raise exceptions or whatever, so i just had the function return 'fail' if it couldin't

How to remove nested parentheses in LISP

由 时光怂恿深爱的人放手 提交于 2019-11-27 14:21:43
How can I remove nested parentheses recursively in Common LISP Such as (unnest '(a b c (d e) ((f) g))) => (a b c d e f g) (unnest '(a b)) => (a b) (unnest '(() ((((a)))) ())) => (a) Thanks Here's what I'd do: (ql:quickload "alexandria") (alexandria:flatten list) That works mainly because I have Quicklisp installed already. (defun flatten (l) (cond ((null l) nil) ((atom l) (list l)) (t (loop for a in l appending (flatten a))))) (defun flatten (l) (cond ((null l) nil) ((atom (car l)) (cons (car l) (flatten (cdr l)))) (t (append (flatten (car l)) (flatten (cdr l)))))) I realize this is an old

Escaping parentheses within parentheses for batch file

由 ╄→尐↘猪︶ㄣ 提交于 2019-11-27 12:46:54
问题 This is what I am trying to do: ( @echo This is some code that is @echo Important to echo exactly as-is @echo Even if I use parenthesis @echo for something (like this) )|clip So having that copied into clipboard. I have tried the following: ( @echo This is some code that is @echo Important to echo exactly as-is @echo Even if I use parenthesis @echo for something ^(like this^) )|clip But this seems to affect my WANTED parentheses as well because I receive an error. To test this, I simply done:

Complex Git branch name broke all Git commands

由 柔情痞子 提交于 2019-11-27 08:58:01
问题 I was trying to create a branch from master with the following command, git branch SSLOC-201_Implement___str__()_of_ProductSearchQuery when Git suddenly stopped responding. I suspect the unescaped () are to blame, somehow. Now, whenever I try to run any Git command, I get the same error: git:176: command not found: _of_ProductSearchQuery with the number after git increasing every time I type a command. Can anyone explain what happened? And how do I get back to normal? I'd like to delete that

Find String Inside Outermost Parenthesis

由 徘徊边缘 提交于 2019-11-27 08:43:00
问题 Say that I have a string which contains both multiple sets and nesting of parenthesis. I want to extract only the string in the first parenthesis encountered, including whatever nested parenthesis it contains. For example: this (is(maybe)) a test (and maybe not) I want to extract: is(maybe) I believe this can be accomplished without the use of regexes, by which I can easily do it. So my question is how can this be accomplished without regexes? 回答1: Pseudo code: iterate over chars if char is (

What is the point of wrapping JavaScript statements in parentheses?

由 旧街凉风 提交于 2019-11-27 07:18:11
问题 I have discovered that wrapping different statements in parentheses will return the last one: (34892,47691876297,2000) => 2000 ('test',73,document.createElement('p')) => <p></p> And I also found out that all the statements are executed anyway: (console.log('test'), console.log('test2'), console.log('test3'), 6) Will log: test test2 test3 And the result will be 6. However, I've also found that some statements can't be used: (throw new Error(), 10) => SyntaxError: Unexpected token throw (if (1)

List of all unicode's open/close brackets?

由 China☆狼群 提交于 2019-11-27 06:01:41
What is a list of every unicode bracket-like characters (including, for example: {}[]()<> )? What is a good way to search for unicode characters? There is a plain-text database of information about every Unicode character available from the Unicode Consortium; the format is described in Unicode Annex #44 . The primary information is contained in UnicodeData.txt . Open and close punctuation characters are denoted with Ps (punctuation start) and Pe (punctuation end) in the General_Category field (the third field, delimited by ; ). Look for those character, and you'll find what you're looking for

Do parentheses make a difference when determining the size of an array?

由 余生长醉 提交于 2019-11-27 05:48:43
问题 The following program prints the same number twice on gcc 4.8.2: #include <stdio.h> int main() { char a[13]; printf("sizeof a is %zu\n", sizeof a ); printf("sizeof(a) is %zu\n", sizeof(a)); } According to this reddit post, gcc is not standard-conformant in this respect, because a parenthesized expression is not on the list of exceptions for when array-to-pointer decay does not happen. Is this guy correct? Here is the relevant standard quote: Except when it is the operand of the sizeof

Is there a good reason for always enclosing a define in parentheses in C?

由 和自甴很熟 提交于 2019-11-27 05:18:32
问题 Clearly, there are times where #define statements must have parentheses, like so: #define WIDTH 80+20 int a = WIDTH * 2; // expect a==200 but a==120 So I always parenthesize, even when it's just a single number: #define WIDTH (100) Someone new to C asked me why I do this, so I tried to find an edge case where the absence of parentheses on a single number #define causes issues, but I can't think of one. Does such a case exist? 回答1: Yes . The preprocessor concatenation operator ( ## ) will
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