paramiko

Python Paramiko - Run command

由 丶灬走出姿态 提交于 2019-11-26 09:59:03
问题 I\'m try to run this script: hostname = \'192.168.3.4\' port = 22 username = \'username\' password = \'mypassword\' y = \"2012\" m = \"02\" d = \"27\" if __name__ == \"__main__\": s = paramiko.SSHClient() s.load_system_host_keys() s.connect(hostname, port, username, password) command = \'ls /home/user/images/cappi/03000/y/m/d\' s.close The question is: how can I put the variables y , m , d into the variable command ? 回答1: Python has lots of ways to perform string formatting. One of the

How to run sudo with paramiko? (Python)

由 ￡可爱￡侵袭症＋ 提交于 2019-11-26 09:56:22
问题 What I\'ve tried: invoke_shell() then channel.send su and then sending the password resulted in not being root invoke_shell() and then channel.exec_command resulted in a \"Channel Closed\" error _transport.open_session() then channel.exec_command resulted in not being root invoke_shell() then writing to stdin and flushing it resulted in not being root 回答1: check this example out: ssh.connect('127.0.0.1', username='jesse', password='lol') stdin, stdout, stderr = ssh.exec_command( "sudo dmesg")

SSH key generated by ssh-keygen is not recognized by Paramiko: “not a valid RSA private key file”

由 两盒软妹~` 提交于 2019-11-26 09:52:15
问题 I have the following code: ssh_key = paramiko.RSAKey.from_private_key_file(key_filename) the key looks like this: -----BEGIN OPENSSH PRIVATE KEY----- b3BlbnNzaC1rZXktdjEAAAAABG5vbmUAAAAEbm9uZQAAAAAAAAABAAABFwAAAAdzc2gtcn NhAAAAAwEAAQAAAQEAqdgmJ2AQlmvpCsDWjbpIvIrx4AwtKn2t10wmGZIN9pqcJgQpo3HD and is valid: $ ssh-keygen -l -f <mykeyfile> $ 2048 SHA256:x8jlUAObU3q2KXRtuGpxwhnGvB/ZoeD2IUqSA1OkCmI thomas@Thomas-MBP-2017 (RSA) but I get the the following error: not a valid RSA private key file This

Automate ssh connection and execution of program with Python&#39;s Paramiko

由 血红的双手。 提交于 2019-11-26 08:38:59
问题 I want to automate a specific task using python. This task includes, among some other things, connecting with ssh to a remote server, and running a specific program (call it prog.out ) that may or may not ask for user input . After some research and after weighting my options, I decided to use Python\'s Paramiko (which may turned out to be wrong, considering the below...). Let\'s start with the easy possibility of prog.out not asking any input, but rather just prints some info to console: int

Python 常用外部模块详解(12)

由 社会主义新天地 提交于 2019-11-26 08:34:49
Python 的创始人为吉多·范罗苏姆(Guido van Rossum).1989年的圣诞节期间,吉多·范罗苏姆为了在阿姆斯特丹打发时间,决心开发一个新的脚本解释程序,作为ABC语言的一种继承.Python是纯粹的自由软件,源代码和解释器CPython遵循 GPL(GNU General Public License)协议.关于python的哲学：python崇尚:"优雅"、"明确"、"简单",Python是用最简单最优雅最明确的方法来解决问题. RabbitMQ RabbitMQ是一个在AMQP基础上完整的,可复用的企业消息系统,他遵循Mozilla Public License开源协议,MQ全称为Message Queue,消息队列(MQ)是一种应用程序对应用程序的通信方法,应用程序通过读写出入队列的消息(针对应用程序的数据)来通信,而无需专用连接来链接它们.消息传递指的是程序之间通过在消息中发送数据进行通信,而不是通过直接调用彼此来通信,直接调用通常是用于诸如远程过程调用的技术.排队指的是应用程序通过队列来通信,队列的使用除去了接收和发送应用程序同时执行的要求,说的笼统点是queue+socket实现. ◆MQ的基础应用◆ 如果启动了多个消费者,那么他们之间是串行获取数据的,也就是说如果1号消费者收不到数据,那么MQ将默认发送给2号消费者,以此类推,如果全部消费者不在线

Paramiko and Pseudo-tty Allocation

由 守給你的承諾、 提交于 2019-11-26 08:23:38
问题 I\'m trying to use Paramiko to connect to a remote host and execute a number of text file substitutions. i, o, e = client.exec_command(\"perl -p -i -e \'s/\" + initial + \"/\" + replaced + \"/g\'\" + conf); Some of these commands need to be run as sudo, which results in: sudo: sorry, you must have a tty to run sudo I can force pseudo-tty allocation with the -t switch and ssh. Is it possible to do the same thing using paramiko? 回答1: I think you want the invoke_shell method of the SSHClient

Nested SSH session with Paramiko

由 不羁的心 提交于 2019-11-26 06:30:31
问题 I\'m rewriting a Bash script I wrote into Python. The crux of that script was ssh -t first.com \"ssh second.com very_remote_command\" I\'m having a problem with the nested authentication with paramiko. I wasn\'t able to find any examples dealing with my precise situation, but I was able to find examples with sudo on a remote host. The first method writes to stdin ssh.connect(\'127.0.0.1\', username=\'jesse\', password=\'lol\') stdin, stdout, stderr = ssh.exec_command(\"sudo dmesg\") stdin

Running interactive commands in Paramiko

由 ∥☆過路亽．° 提交于 2019-11-26 05:58:01
问题 I\'m trying to run an interactive command through paramiko. The cmd execution tries to prompt for a password but I do not know how to supply the password through paramiko\'s exec_command and the execution hangs. Is there a way to send values to the terminal if a cmd execution expects input interactively? ssh = paramiko.SSHClient() ssh.connect(server, username=username, password=password) ssh_stdin, ssh_stdout, ssh_stderr = ssh.exec_command(\"psql -U factory -d factory -f /tmp/data.sql\") Does

Execute multiple commands in Paramiko so that commands are affected by their predecessors

由 霸气de小男生 提交于 2019-11-26 04:56:33
问题 I am slowly trying to make a python script to SSH then FTP to do some manual file getting I have to do all the time. I am using Paramiko and the session seems to command, and prints the directory but my change directory command doesn\'t seem to work, it prints the directory I start in /01/home/ import paramiko hostname = \'\' port = 22 username = \'\' password = \'\' #selecting PROD instance, changing to data directory, checking directory command = { 1:\'ORACLE_SID=PROD\',2:\'cd /01

Some Unix commands fail with “<command> not found”, when executed using Python Paramiko exec_command

由 假装没事ソ 提交于 2019-11-26 02:25:43
问题 I am trying to run sesu command in Unix server from Python with the help of Paramiko exec_command . However when I am running this command exec_command(\'sesu test\') , I am getting sh: sesu: not found When I am running simple ls command it giving me desired output. Only with sesu command it is not working fine. This is how my code looks like: import paramiko host = host username = username password = password port = port ssh=paramiko.SSHClient() ssh.set_missing_host_key_policy(paramiko
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