paramiko

Paramiko, exec_command get the output stream continuously

由 自闭症网瘾萝莉.ら 提交于 2019-12-10 17:15:04
问题 I dry on a Python script. I create a python script for a given IP will connect via Paramiko to a server to execute another Python script. Here is some code: self._client = paramiko.SSHClient() self._client.set_missing_host_key_policy(paramiko.AutoAddPolicy()) self._client.connect(self._ip, username=self._server['username'], password=self._server['password']) channel = self._client.get_transport().open_session() channel.exec_command('python3 /tmp/scrap.py /tmp/' + self._ip + '.txt 0 1') The

Python Paramiko send CTRL+C to an ssh shell

由 廉价感情. 提交于 2019-12-10 15:32:23
问题 I'm invoking a shell using Paramiko in order to use a CLI over an ssh connection. The problem with this CLI is if I do not close it specifically using CTRL+C, the program will not be able to be opened again without rebooting my system. I've tried the below commands: SSH.send("^C\n") SSH.send("\x003") is there another way to call these? Again, I've established an SSH connection using paramiko.SSHClient() and then invoked a shell using ssh.invoke_shell() and now i need to send CTRL+C to that

Python - pysftp / paramiko - Verify host key using its fingerprint

由 本小妞迷上赌 提交于 2019-12-10 12:07:01
问题 This code throws an exception. How can I verify an SSH fingerprint without storing it in a file? I believe the code below is designed for a public key. But the client with the SFTP server validated the fingerprint and did not get me the public key. import os import shutil import pysftp import paramiko connection_info = { 'server': "example.com", 'user': "user", 'passwd': "password", 'target_dir': "out/prod", 'hostkey': "ssh-rsa 2048 d8:4e:f1:f1:f1:f1:f1:f1:21:31:41:14:13:12:11:aa", } def move

centos7 python3 安装paramiko模块

由 蓝咒 提交于 2019-12-10 11:47:07
1. CentOS 7下 安装Python3.5 CentOS7默认安装了python2.7.5， 要用 Python3需要自己手动安装。注意不要删除python2。 1.1 下载python3源码包 wget https://www.python.org/ftp/python/3.5.2/Python-3.5.2.tgz 1.2 安装依赖 yum install openssl-devel libxslt-devel python3-dev python-dev -y 1.3 解压缩源码包然后编译安装。 tar -xvf Python-3.5.2.tgz ./configure --prefix=/usr/python3.5 make make install 1.4 将 Python3添加到系统环境中 #vi /etc/profile export PATH=$PATH:/usr/python3.5/bin # source /etc/profile 此时命令行输入python3就可以使用python3了 2. pip3安装paramiko（国内一般安装失败） python3自带了pip3。直接使用pip3为python3安装paramiko。如果使用pip install则是安装到python 2.7上。 pip3 install paramiko 3.

How can I ssh into a server that requires 2 password authentication using python's paramiko module?

由 萝らか妹 提交于 2019-12-10 11:45:33
问题 How do I ssh to a server that requires dual password authentication using paramiko? When using a particular user it first prompts for the user password and then for another password, so my session needs to be interactive. I have done the same using pexpect module to spawn an "ssh" process on Linux, but since I cannot do that in Windows I need a way to do it using paramiko. The server is our product that is a slightly modified version of CentOS. I am writing automation code to test some

Paramiko: calling “cd” command with exec_command does nothing

由 非 Y 不嫁゛ 提交于 2019-12-10 11:35:22
问题 I have the following program using Paramiko: #!/usr/bin/env python import paramiko hostname = '192.168.1.12' port = 22 username = 'root' password = 'whatl0ol' if __name__ == "__main__": paramiko.util.log_to_file('paramiko.log') ssh = paramiko.SSHClient() ssh.load_system_host_keys() ssh.connect(hostname, port, username, password) while True: pick = raw_input("sshpy: ") stdin, stdout, stderr = ssh.exec_command(pick) print stdout.readlines() But when I connect and try to use cd , it doesn't work

Unable to see ifconfig output using paramiko

由 孤者浪人 提交于 2019-12-10 11:06:44
问题 I am using below code to execute commands on a remote machine, import paramiko import os dssh = paramiko.SSHClient() dssh.set_missing_host_key_policy(paramiko.AutoAddPolicy()) dssh.connect('192.168.1.5', username='root', password='asdfghhh') import os stdin, stdout, stderr = dssh.exec_command('ls') print stdout.read() stdin, stdout, stderr = dssh.exec_command('ifconfig') print stdout.read() stdin, stdout, stderr = dssh.exec_command('ps') print stdout.read() dssh.close() when I execute the

using st_mode to identify file or directory

由 浪子不回头ぞ 提交于 2019-12-10 10:44:22
问题 is there any way to identify whether an object is file or directory using st_mode value? I'm using paramiko lstat() to retrieve the st_mode information from sftp files. 回答1: Yes, the stat structure st_mode does contain that information. Use the stat module to determine if it is a directory: import stat if stat.S_ISDIR(lstat_result.st_mode): 来源： https://stackoverflow.com/questions/15861967/using-st-mode-to-identify-file-or-directory

Paramiko get sorted directory listing

由 a 夏天 提交于 2019-12-10 10:15:50
问题 I am able to get a directory listing from Paramiko. And with listdir_attr I get the attributes. However, I need to sort this list by filename. If it returned a list of dictionaries I could use lambda to do the sort. But with it returning a list of SFTPAttributes I can't figure out how to do the sort other than creating a new list of dictionaries containing the data I care about and sorting that list. Before doing that is there a way to get a directory listing that is sorted by filename? 回答1:

Slow public key authentication with paramiko

由 孤街浪徒 提交于 2019-12-10 09:37:50
问题 I am using paramiko to connect to a remote server over ssh. When authenticating using a public key, the performance is slow (~90 secs). Here is the relevant logging output: 2012-05-14 17:37:21,378 Ciphers agreed: local=aes128-ctr, remote=aes128-ctr 2012-05-14 17:37:21,378 using kex diffie-hellman-group1-sha1; server key type ssh-rsa; cipher: local aes128-ctr, remote aes128-ctr; mac: local hmac-sha1, remote hmac-sha1; compression: local none, remote none 2012-05-14 17:37:21,481 Switch to new
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