paging

问题 I quickly view this MSDN article using datacolumn.expression, but have found nothing. It looks like 'select expression' syntax doesn't support paging... 回答1: Paging is a mechanism of how you SELECT the data. Consider the following test data: ID Name Date 1 Bob 1/1/2013 2 Bill 1/3/2013 3 Andy 2/1/2013 ... if I wanted to page that data, and I didn't care how it was sorted, I could do it by ID so I could do something like this: var rows = table.Select().Take(10); _id = (int)rows.Last()["ID"];

问题 I have implemented a paging html helper (adapted from steven sanderson's book). This is the current code: public static string PageLinks(this HtmlHelper html, int currentPage, int totalPages, Func pageUrl) { StringBuilder result = new StringBuilder(); for (int i = 1; i <= totalPages; i++) { TagBuilder tag = new TagBuilder("a"); tag.MergeAttribute("href", pageUrl(i)); tag.InnerHtml = i.ToString(); if (i == currentPage) tag.AddCssClass("selectedPage"); result.AppendLine(tag.ToString()); }

问题 I'm doing a webpage with a search that brings a lot of information from MSSQL. What I did is a stored procedure that return only the page to be seen on the website. Right now I'm working on the paging as I need to show something similar than google. If you are at page 1 they show first 10 pages and if you are at page 19 they show since page 9 to 28. I think the best option to show the page numbers is using a linkbutton inside a repeater. The problem that I have now is that I do not know the

问题 I've been struggling with some code for a paging for a couple of days (YES! days) now but can't get it to work properly, probably because I don't have any experience on this kind of problems yet. the paging I'm trying to do should look something like this: 1 2 3 4 5 6 ... 101 When i click on number 5 i would like it to display the numbers like this: 1 ... 3 4 5 6 7 ... 101 when I'm at the last couple of pages i want it to look similar to the first one: 1 ... 96 97 98 99 100 101 The bold

问题 I want to do something like this... return GetSession() .ToPagedList<Employee>(page, pageSize, x=> x.SetFetchMode(DomainModelHelper.GetAssociationEntityNameAsPlural<Team>(), FetchMode.Eager)); But I don't know how to pass this Func<ICriteria,ICriteria> into the ISession or ICriteria . I have a standard paging extension method and this extension method shall have an overload where I can pass additional ICriteria methods, so that I can additionally set up the FetchMode or something else.

问题 I am trying to get paging work on my jqgrid, but it always reads "1 of 0", I am loading data using addRowData to populate data on my grid. for (var i = 0; i <= mydata1[0].rows.length; i++) jQuery("#list").jqGrid('addRowData', i + 1, mydata1[0].rows[i]); The data returned is in the format: {total:'1',records:'10',page:'1',rows:[{ 'name': "Beginners Guide to the Stock Market"}] Any help will be much appreciated 回答1: Either you have an old problem with refreshing of the jqGrid pager see

问题 I am trying to get paging work on my jqgrid, but it always reads "1 of 0", I am loading data using addRowData to populate data on my grid. for (var i = 0; i <= mydata1[0].rows.length; i++) jQuery("#list").jqGrid('addRowData', i + 1, mydata1[0].rows[i]); The data returned is in the format: {total:'1',records:'10',page:'1',rows:[{ 'name': "Beginners Guide to the Stock Market"}] Any help will be much appreciated 回答1: Either you have an old problem with refreshing of the jqGrid pager see

问题 I am trying to get paging work on my jqgrid, but it always reads "1 of 0", I am loading data using addRowData to populate data on my grid. for (var i = 0; i <= mydata1[0].rows.length; i++) jQuery("#list").jqGrid('addRowData', i + 1, mydata1[0].rows[i]); The data returned is in the format: {total:'1',records:'10',page:'1',rows:[{ 'name': "Beginners Guide to the Stock Market"}] Any help will be much appreciated 回答1: Either you have an old problem with refreshing of the jqGrid pager see

问题 I would like to change the the labels of pages in Yii. I used Zii.widegt.CListView to show the list of items. The default structure of yii pagination is [previous] 1 2 4 5 6 7 [next] required structure is < 1....10 11 12 13 14 ....40 > . I read "How can I customize the labels for the pager in Yii?" which is helpful, but how can I show the firstPageLabel as page number 1 instead of << and lastPageLabel as 40 instead of >> . 回答1: If you can't find a way to pass in the total item count (i.e. 40)

问题 I have been trying to look around in the linux source code for a structure/union that'd correspond to the PTE on x86 system with PAE disabled. So far I've found only the following in arch/x86/include/asm/page_32.h typedef union { pteval_t pte; pteval_t pte_low; } pte_t; I'm a bit confused right now since I have the Intel Reference Manual Vol 3A open in front of me and nothing in that union corresponds to the dozen odd fields present in the PTE as the manual explains. This might be a trivial