paging

I have ten local HTML files in my Resource folder and I want to performing paging effect like ScrollView and ImageView so please help me how I can do that. I have displayed HTML page in webView , but i don't have any more ideas. My code is (but it's for only One page): arrHtmlPage=[[NSMutableArray alloc] initWithObjects:@"2",@"3",@"5",@"6",@"8",@"9",@"11",@"13",nil]; NSBundle *bundle = [NSBundle mainBundle]; NSString *htmlTemplateLink = [bundle pathForResource:@"2" ofType:@"htm"]; NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL fileURLWithPath:htmlTemplateLink]]; wview=[[UIWebView

I would like to change the the labels of pages in Yii. I used Zii.widegt.CListView to show the list of items. The default structure of yii pagination is [previous] 1 2 4 5 6 7 [next] required structure is < 1....10 11 12 13 14 ....40 > . I read " How can I customize the labels for the pager in Yii? " which is helpful, but how can I show the firstPageLabel as page number 1 instead of << and lastPageLabel as 40 instead of >> . If you can't find a way to pass in the total item count (i.e. 40) to the lastPageLabel override, you will need to override the CLinkPager class to have this work

This is a followup on the question: ASP.NET next/previous buttons to display single row in a form As it says on the page above, theres a previous/next button on the page, that retrieves a single row one at a time. Totally there's ~500,000 rows. When I "page" through each subscribtion number, the form gets filled with subscriber details. What approach should I use on the SQL server? Using the ROW_NUMBER() function seems a bit overkill as it has to number all ~500.000 rows (I guess?), so what other possible solutions are there? Thanks in advance! ROW_NUMBER() is probably your best choice. From

in a paged-segmented system we have the virtual address of 32 bits and 12 bits for the offset,11 bits for segment and 9 bits for page number.the how can we calculate the page size ,maximum segment size and maximum number of segment size? 12 bits are reserved for offset, so the page size is 2^12 = 4KB 9 bits are reserved for page number, so each segment can contain 2^9 = 512 pages Each segment can grow up to size of (# of pages) * (pages size), so maximum segment size is 512 * 4K = 2M For more information see http://www.cs.umass.edu/~weems/CmpSci535/Discussion21.html 来源： https://stackoverflow