paging

Unit Testing Spring MVC Controller that returns PagedResources

☆樱花仙子☆ 提交于 2019-12-14 02:16:11
问题 I am building an application with Spring Boot 1.4.1, Spring Data Jpa and Spring Data Test. I have the following controller with which I want to return paged accounts: @RequestMapping(method=RequestMethod.GET) public HttpEntity<PagedResources<Account>> getAccounts( Pageable pageable, PagedResourcesAssembler assembler, @RequestParam(value="name", required = false) String name, @RequestParam(value="username", required = false) String username, @RequestParam(value="email", required = false)

LINQ-to-NHibernate: Cannot use Linq Skip() and Take() with FetchMany

匆匆过客 提交于 2019-12-14 02:06:54
问题 I have these entities: public class BlogPost { public virtual int Id { get; set; } public virtual IList<Keyword> Keywords { get; set; } public virtual IList<BlogComment> Comments { get; set; } } public class BlogComment { public virtual int Id { get; set; } public virtual BlogPost Post { get; set; } } public class Keyword { public virtual int Id { get; set; } public virtual IList<BlogPost> BlogPosts { get; set; } } I want to load a paged-list of BlogPost s by their Keyword s and comments

In context of ARMv7 what is the advantage of Linux kernel one to one mapped memory when mmu has to do a page table translation

*爱你&永不变心* 提交于 2019-12-14 01:19:34
问题 Linux kernel virtual address are one-to-one mapped. So by subtracting a PAGE_OFFSET to virtual address we will get the physical address. That is how virt_to_phys and phys_to_virt are implemented in memory.h. My question is what is the advantage of these one to one mapping on the armv7 mmu, when the mmu has to do the page table translation when there is a TLB miss? Is the only advantage of one to one mapping so that S/W can directly gets the physical address of respective virtual address by

Set PageIndex of DataPager

一曲冷凌霜 提交于 2019-12-13 14:26:34
问题 I have a ListView that I am paging with a DataPager. I would like to set the initial page of the pager on Page_Load. I have tried the DataPager.SetPageProperties method but it's not doing what I need. Here's how I'm calling this method: dataPager.SetPageProperties(3, dataPager.TotalRowCount, false); The line above trims the datasource to start at the third item and paging still starts at 1. This is not what I want. I want to keep the entire list of items and just jump to a specific page in

Jpa paging with numbers and next, previous

蹲街弑〆低调 提交于 2019-12-13 11:35:48
问题 I apologize for asking this question if someone already asked it and for asking a perhaps dumb question but I am new to this and you are experts and I would love to learn from your expert advice and experience. I want to add paging to an application displaying 200 records per page. The bottom of the page should have numbers. If there are 1050, the first page will display 100 and the bottom of the page will show numbers 1,2,3,4,5 & 6. What is the general logic to accomplish this? I know that

Sorting and Paging on repository

被刻印的时光 ゝ 提交于 2019-12-13 10:17:22
问题 I have a simple ASP.NET MVC application which has possibility to search, filter and page a list of vehicle makes. I implemented sorting, filtering and paging on controller (on "Index" action) following the tutorials from kudvenkat on youtube https://www.youtube.com/watch?v=srN56uxw76s So, this is my "VehicleMakeController" and "Index" action: public class VehicleMakeController : Controller { private readonly IVehicleRepository _vehicleRepository; public VehicleMakeController() {

Calling Javascript On PageListPager MVC

こ雲淡風輕ζ 提交于 2019-12-13 09:22:37
问题 I want to call below mention javascript on paging i.e PageListPager which is on my view page <script type="text/javascript"> (document).on('click', 'a', function someFunction() { alert("ok") document.getElementById('page').value = cnt; $("#testStartedForm").submit(); }); </script> <div class="pagedList"> @Html.PagedListPager(Model, page => Url.Action("TestStarted", "Student", new { page,TestId = ViewBag.TestId,onclick="someFunction(" + page + ")" }), PagedListRenderOptions

ASP.Net GridView UpdatePanel Paging Gives Error On Second Click

北慕城南 提交于 2019-12-13 04:09:07
问题 I'm trying to implement a GridView with paging inside a UpdatePanel. Everything works great when I do my first click. The paging kicks in and the next set of data is loaded quickly. However, when I then try to click a link for another page of data, I get the following error: Sys.WebForms.PageRequestManagerServerErrorException: An unknown error occurred while processing the request on the server. The status code returned from the server was: 12030 aspx code <asp:UpdatePanel ID="UpdatePanel1"

Dynamic Pagination in C#

走远了吗. 提交于 2019-12-13 03:25:05
问题 I'm new here I have the same problem as Marcus in here the paging I'm trying to do should look something like this: 1 2 3 4 5 6 ... 101 When i click on number 5 i would like it to display the numbers like this: 1 ... 3 4 5 6 7 ... 101 when I'm at the last couple of pages i want it to look similar to the first one: 1 ... 96 97 98 99 100 101 The bold number is the page that you're currently viewing. I want the dots to appear only when there is more than 7 pages available, if not it should look

ExtJS Grid Paging: next button is disabled!

左心房为你撑大大i 提交于 2019-12-13 00:23:37
问题 I created a basic grid that has a paging toolbar. For some reason when I load up at index 0, the Next Page button is disabled, even though the text says "Displaying page 1 of 5". If I choose anything higher than 0 in the load params for the store, it allows me to page forward and back, but it does not properly display the max # of pages and if I go back to the first page, the next button is once again disabled. Any ideas? function getBugGrid(activityPanelWrapper){ var pageSize = 5; var