overriding

问题 In one base class, there's a protected procedure. When inheriting that class, I want to hide that procedure from being used from the outside. I tried overriding it from within the private and even strict private sections, but it can still be called from the outside. The Original class is not mine, so I can't change how TOriginal is defined. Is it possible to hide this procedure in my inherited class? And how? type TOriginal = class(TObject) protected procedure SomeProc; end; TNew = class

问题 This is basically a copy from the example given in Item 21. Overriding Virtual Functions in Herb Sutter's book Exceptional C++ . #include <iostream> #include <complex> using namespace std; class Base { public: virtual void f(int); virtual void f(double); virtual ~Base() {}; }; void Base::f(int) { cout << "Base::f(int)" << endl; } void Base::f( double ) { cout << "Base::f(double)" << endl; } class Derived: public Base { public: void f(complex<double>); }; void Derived::f(complex<double>) {

问题 Is it possible to over-ride methods that are part of Ruby itself, such as rb_error_frozen , that are written in C, with Ruby code? Background : I'm wondering if it's possible to make Ruby merely log a warning, rather than raise an exception, when a frozen object is modified. That way, I can log a variety of state modifications, rather than stopping when the first one occurs. I'm primarily thinking of doing this with YARV, but I could use another implementation if that made it easier. And yes,

问题 class Parent { public: void func1(); // Complete meaningful definition in parent given. virtual HRESULT func2()=0; // Bcoz of this function Parent class is abstract. }; class Child: public Parent { public: void func1(); // Different definition in child. }; Is this possible in C++ ? I am overriding func1() which is NOT virtual and it already has a definition in parent abstract class. 回答1: [assuming here Child extends Parent , unlike what the code snap shows] Yes it is possible [it is called

问题 I'm aware that a params modifier (which turns in one parameter of array type into a so-called "parameter array") is specifically not a part of the method signature. Now consider this example: class Giraffid { public virtual void Eat(int[] leaves) { Console.WriteLine("G"); } } class Okapi : Giraffid { public override void Eat(params int[] leaves) { Console.WriteLine("O"); } } This compiles with no warnings. Then saying: var okapi = new Okapi(); okapi.Eat(2, 4, 6); // will not compile! gives an

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 months ago . Let's say I have a class Person which looks like this: class Person { constructor( public firstName: string, public lastName: string, public age: number ) {} } Is it possible to override the toString() method in this class, so I could do something like the following? function alertMessage(message: string) {

问题 In Odoo, the quantities of a product are calculated each time the products form is opened. This happens in model product.product ==> function _product_available. This function returns a dictionary called res. Example: res = {8: {'qty_available': 5000.0, 'outgoing_qty': 1778.5, 'virtual_available': 3221.5, 'incoming_qty': 0.0}} Now I want to modify those values. I've managed to do this by coding it directly in the original function _product_available. Since this is not the correct way to do

问题 If the generic type argument (of either a calling class or calling method) is constrained with where T : Base the new method in T == Derived is not called, instead the method in Base is called. Why is the type T ignored for method call even though it should be known before run time? Update : BUT, when the constraint is using an interface like where T : IBase the method in Base class is called (not the method in interface, which is also impossible). So that means the system actually is able to

问题 To the point, I want to override the standard js confirm() function within a jQuery plugin. I have figured out how to do it with the simple function layout below. function confirm(opts) { //code } Now, what I want to do is call another function within the confirm function above, like so... function confirm(opts) { openModal(opts); } The openModal function will open a custom modal window with the message and required buttons. The buttons are both <span> with the id of either submit or cancel .

问题 I'm wondering if it is possible to override the default value of a field when it is returned. Say I had a model: class ModelA(models.Model) name = models.CharField(max_length=30) Is there any way that calling modela_instance.name can return a modified value, for example name + " foo", but have the code that appends foo run by default within the model itself, so all I would need to do is call name to get the appended value? I should elaborate and say that what I'm actually hoping to do is have