ordereddict

How to pack multilines results (OrderedDict with differents keys) into pandas dataframe? [duplicate]

China☆狼群 提交于 2021-01-29 15:34:14
问题 This question already has answers here : Generate a pandas dataframe from ordereddict? (4 answers) Closed 1 year ago . I did a loop over multiple files to get as a result an OrderedDict for each one (possibility to have different keys, which means not the same from an OrderedDict to another). I want to write/ pack the result into the same pandas dataframe. So we will have all the different keys as column names, and each row of the dataframe will represent an OrderedDict. I have already my

Extracting Data from OrderedDict

时光总嘲笑我的痴心妄想 提交于 2021-01-28 05:04:09
问题 So i have a firebase database and this is my code to get specific data db = firebase.database() test = db.child("Users").order_by_child("IDNumber").equal_to(222333123).get().val() print(test) then the result returns as an OrderedDict OrderedDict([('Ays', {'Ays': 'Baby', 'IDNumber': 222333123})]) i want to extract the data and have Ays = Baby and IDNumber = 222333123 as two separate variables. i tried using .items() and putting it into list but i can't seem to separate it. is there any other

Extracting Data from OrderedDict

旧时模样 提交于 2021-01-28 03:46:50
问题 So i have a firebase database and this is my code to get specific data db = firebase.database() test = db.child("Users").order_by_child("IDNumber").equal_to(222333123).get().val() print(test) then the result returns as an OrderedDict OrderedDict([('Ays', {'Ays': 'Baby', 'IDNumber': 222333123})]) i want to extract the data and have Ays = Baby and IDNumber = 222333123 as two separate variables. i tried using .items() and putting it into list but i can't seem to separate it. is there any other

How to add an element to the beginning of an OrderedDict?

安稳与你 提交于 2019-12-28 04:52:05
问题 I have this: d1 = OrderedDict([('a', '1'), ('b', '2')]) If I do this: d1.update({'c':'3'}) Then I get this: OrderedDict([('a', '1'), ('b', '2'), ('c', '3')]) but I want this: [('c', '3'), ('a', '1'), ('b', '2')] without creating new dictionary. 回答1: There's no built-in method for doing this in Python 2. If you need this, you need to write a prepend() method/function that operates on the OrderedDict internals with O(1) complexity. For Python 3.2 and later, you should use the move_to_end method

How to add an element to the beginning of an OrderedDict?

天涯浪子 提交于 2019-11-27 17:47:32
I have this: d1 = OrderedDict([('a', '1'), ('b', '2')]) If I do this: d1.update({'c':'3'}) Then I get this: OrderedDict([('a', '1'), ('b', '2'), ('c', '3')]) but I want this: [('c', '3'), ('a', '1'), ('b', '2')] without creating new dictionary. There's no built-in method for doing this in Python 2. If you need this, you need to write a prepend() method/function that operates on the OrderedDict internals with O(1) complexity. For Python 3.2 and later, you should use the move_to_end method. The method accepts a last argument which indicates whether the element will be moved to the bottom ( last

Will OrderedDict become redundant in Python 3.7?

断了今生、忘了曾经 提交于 2019-11-26 15:57:25
问题 From the Python 3.7 changelog: the insertion-order preservation nature of dict objects has been declared to be an official part of the Python language spec. Would this mean that OrderedDict will become redundant? The only use I can think of it will be to maintain backwards compatibility with older versions of Python which don't preserve insertion-order for normal dictionaries. 回答1: No it won't become redundant in Python 3.7 because OrderedDict is not just a dict that retains insertion order,