operator-precedence

Scala: Can you use “foo match { bar }” in an expression without parentheses?

北战南征 提交于 2019-12-01 14:43:48
问题 Why are the parentheses needed here? Are there some precedence rules I should know? scala> 'x' match { case _ => 1 } + 1 <console>:1: error: ';' expected but identifier found. 'x' match { case _ => 1 } + 1 ^ scala> ('x' match { case _ => 1 }) + 1 res2: Int = 2 Thanks! 回答1: As Agilesteel says, a match is not considered as a simple expression, nor is an if statement, so you need to surround the expression with parentheses. From The Scala Language Specification, 6 Expressions, p73, the match is

Which has more priority: || or && or ==

久未见 提交于 2019-12-01 14:28:18
问题 I have this expression: y[i] = ( z[i] == a && b || c ) Which of these elements ( && , || , == ) have the priority? Can you please show the order of operations with brackets? 回答1: First == , then && , then || . Your expression will be evaluated as y[i] = (((z[i] == a) && b) || c) . https://docs.oracle.com/javase/tutorial/java/nutsandbolts/operators.html 回答2: The priority list: == && || 回答3: This would be : y[i] = ((( (z[i]) == a )&& b) || c) ref: http://introcs.cs.princeton.edu/java

Python: what does “import” prefer - modules or packages?

元气小坏坏 提交于 2019-12-01 13:56:56
问题 Suppose in the current directory there is a file named somecode.py , and a directory named somecode which contains an __init__.py file. Now I run some other Python script from this directory which executes import somecode . Which file will be imported - somecode.py or somecode/__init__.py ? Is there even a defined and reliable search order in which this is resolved? Oh, and does anyone have a reference to official documentation for this behavior? :-) 回答1: Packages will be imported before

Operator precedence in C for the statement z=++x||++y&&++z

无人久伴 提交于 2019-12-01 13:31:30
I was studying operator precedence and I am not able to understand how the value of x became 2 and that of y and z is 1 x=y=z=1; z=++x||++y&&++z; This evaluates to x=2 y=1 z=1 ++ has higher priority than || , so the whole RHS of the assignment boils down to an increment of x and an evaluation to a truth value (1). z = ++x || ++y&&++z; truthy (1) never executed This is because ++x evaluates to true and the second branch is not executed. ++x is 2 which, in a boolean context, evaluates to true or 1 . z takes the value of 1 , giving you the observed final state. x=y=z=1 z=++x||++y&&++z is

Parameter order evaluation

☆樱花仙子☆ 提交于 2019-12-01 12:55:13
In previous versions of the standard (C++03) the order of evaluation of parameters to a function call was unspecified. Has this been changed in subsequent version of the standard (C++11 or C++14)? i.e. Can we rely on a specific ordering (left to right) or not. No this has not changed but there is a very recent proposal to change this: N4228: Refining Expression Evaluation Order for Idiomatic C++ , this was part of the Pre-Urbana mailing that came out this October The introduction says ( emphasis mine going forward ): Expression evaluation order is a recurring discussion topic in the C++

Operator precedence in C for the statement z=++x||++y&&++z

旧时模样 提交于 2019-12-01 11:12:11
问题 I was studying operator precedence and I am not able to understand how the value of x became 2 and that of y and z is 1 x=y=z=1; z=++x||++y&&++z; This evaluates to x=2 y=1 z=1 回答1: ++ has higher priority than || , so the whole RHS of the assignment boils down to an increment of x and an evaluation to a truth value (1). z = ++x || ++y&&++z; truthy (1) never executed This is because ++x evaluates to true and the second branch is not executed. ++x is 2 which, in a boolean context, evaluates to

difference between c's expression and c++'s expression

杀马特。学长 韩版系。学妹 提交于 2019-12-01 10:50:40
int main() { int i=3; (++i)++; printf("%d",i); } This programs works with g++ compiler but not gcc. If i write i++++ or ++i++ it doesn't work in cpp also. I think there is difference between c-expression and c++-expression. Can somebody explain about L-value and R-value ? Edit: This answer is incorrect for the updated question, it applies to the question as originally stated. (i++)++ shouldn't work with either gcc or g++, whether or not they are parsing the file as C or C++ in both languages postfix increment requires an lvalue as an operand and the result is an rvalue . (Note that rvalue is

Logical operators priority with NAND, NOR, XNOR

陌路散爱 提交于 2019-12-01 04:22:27
I've searched the web but I've found no solution to this problem. What is the logical priority for operators NAND , NOR and XNOR ? I mean, considering as example the expression A AND B NAND C which operator should be evaluated first? Obviously NAND can be translated as NOT-AND (as NOR is NOT-OR and XNOR is NOT-XOR ), but (A AND B) NAND C != A AND (B NAND C) = A AND NOT(B AND C) According to my researches there's no a defined priority for such an expression, so I think the simplest solution is to evaluate the operators according to the order they appear in the expression, but I may be wrong.

Make sure a Javascript script is first to run?

自闭症网瘾萝莉.ら 提交于 2019-12-01 04:06:17
I've noticed some scripts seem to be called before others on a certain page, I was wondering, what is the specific order for scripts to load? In-page before referenced .js scripts? Are they run in order from first <script> mentioned to last in page, or Is this browser-dependent? How can one make sure that a specific script is first to run in a page? I've noticed some scripts seem to be called before others on a certain page. I was wondering, what is the specific order for scripts to load? This is set by W3C in their language specifications. For the HTML 4.01 Specification , for instance, it's

Why does PHP evaluate $b and $b = $b differently when used with $b++ in array index

偶尔善良 提交于 2019-12-01 04:01:11
问题 I am unable to grasp the evaluation logic in the code listed below. Does anyone know why PHP evaluates $b and $b = $b differently in this case? I have read through a number of questions here at SO and checked the PHP manual. Doing so I've come to understand that "PHP does not (in the general case) specify in which order an expression is evaluated" and that "the behavior can change between versions of PHP or depending on the surrounding code" . I don't feel that that applies to this situation