operator-overloading

来源： https://stackoverflow.com/questions/3188666/python-operator-overloading-a-specific-type

来源： https://stackoverflow.com/questions/3188666/python-operator-overloading-a-specific-type

来源： https://stackoverflow.com/questions/61141894/why-is-stdstrings-member-operator-not-lvalue-ref-qualified

来源： https://stackoverflow.com/questions/63145955/how-do-i-compare-a-char-array-from-a-class-with-another-char-array-using-the-ove

来源： https://stackoverflow.com/questions/45956271/stdgetline-reads-carriage-return-r-into-the-string-how-to-avoid-that

问题 In the book of "The C++ Programming Language", the author gave the following example along with several statements: Defining an operator, such as [], to be used for both reading and writing is difficult where it is not acceptable simply to return a reference and let the user decide what to do with it. Cref, is to help implement a subscript operator that distinguishes between reading and writing. Why [] is difficult to be defined when to be used for both reading and writing? How does the

问题 Applying Documentation to Multi-Dispatched Functions I am using the multipledispatch package, in a fashion similar to the example code below. I want to be able to see the docstring text when I ask for help(my_add) in the Python command line, but instead all I see is information about the decorator. Functools.wraps must be the way to do it, but how? I have looked up functools.wraps, which I'm sure is what I want to use. I have found examples of how to use it, such as this and this. But I still

问题 I found this code online for the singleton design pattern: class Foo { public: static Foo& getInstance() { static Foo instance; return instance; } private: Foo() {}; Foo(Foo const&); Foo& operator=(Foo const&); } I don't understand why the constructor Foo(Foo const&); and the Foo& operator=(Foo const&); are both needed. Can someone explain to me please? 回答1: Wouldn't you want the following code to fail? int main() { // Utilizes the copy constructor Foo x = Foo::getInstance(); Foo y = Foo:

问题 I have a template class Array: template <class T=int, int SIZE=10> class Array { T TheArray[SIZE]; public: void Initialize() { for (int idx=0; idx < SIZE; idx++) { TheArray[idx] = T(); } } T& operator [](int idx) { return TheArray[idx]; } T operator [](int idx) const { return TheArray[idx]; } } I have some questions on operator [] overloading (I found this example on net). I understand that T& operator [](int idx) returns a reference to an array value with index idx and that T operator [](int

问题 I have a template class Array: template <class T=int, int SIZE=10> class Array { T TheArray[SIZE]; public: void Initialize() { for (int idx=0; idx < SIZE; idx++) { TheArray[idx] = T(); } } T& operator [](int idx) { return TheArray[idx]; } T operator [](int idx) const { return TheArray[idx]; } } I have some questions on operator [] overloading (I found this example on net). I understand that T& operator [](int idx) returns a reference to an array value with index idx and that T operator [](int