operator-overloading

问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: Why do multiple-inherited functions with same name but different signatures not get treated as overloaded functions? This fails to compile in the indicated place with g++ 4.6.1: enum Ea { Ea0 }; enum Eb { Eb0 }; struct Sa { void operator()(Ea) {} }; struct Sb { void operator()(Eb) {} }; struct Sbroken : Sa, Sb {}; struct Sworks { void operator()(Ea) {} void operator()(Eb) {} }; int main() { Sworks()(Ea0);

问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: Why do multiple-inherited functions with same name but different signatures not get treated as overloaded functions? This fails to compile in the indicated place with g++ 4.6.1: enum Ea { Ea0 }; enum Eb { Eb0 }; struct Sa { void operator()(Ea) {} }; struct Sb { void operator()(Eb) {} }; struct Sbroken : Sa, Sb {}; struct Sworks { void operator()(Ea) {} void operator()(Eb) {} }; int main() { Sworks()(Ea0);

问题 This question already has answers here : Operator[][] overload (18 answers) Closed 3 years ago . How can I overload multi-dimensional brackets? Let's say that I have a class which enables me to access points in an n -vector space. For example: class NSpaceVector { private: int vectorSpace[8][8][8][8][8][8][8]; public: const NSpaceVector operator[][][][][][][](int i, int j, int k, int l, int m, int n, int p)const {return vectorSpace[i][j][k][l][m][n][p]; } NSpaceVector operator[][][][][][][]

问题 As I know here is the way to overload the post-increment operator: const MyClass& MyClass::operator++(int); Why does it have int as an argument? 回答1: D&E, §11.5.3: I conisdered the obvious solution, adding the keywords prefix and postfix to C++ [ ... ] However I received the usual howl of outrage from people who dislike new keywords. Several alternatives that did not involve new keywords were suggested. For example: class Ptr_to_X { X ++operator(); // prefix ++ X operator++(); // postfix ++ }

问题 I am writing a C# class that is exposed to VB.Net. I would like to overload the vb.net ^ operator so that I can write: Dim c as MyClass Set c = New ... Dim d as MyClass Set d = c^2 In C#, the ^ operator is the xor operator and the power operator doesn't exist. Is there a way I can do this anyway? 回答1: EDIT It turns out there's a SpecialNameAttribute that lets you declare "special" functions in C# that will allow you (among other things) to overload the VB power operator: public class

问题 I've found some good examples of functors on SO like this one, and all the convincing examples seem to use state in the class that defines operator() . I came across an example in a book that defines the function call operator without having state, and I can't help but feel like this is an awkward usage, and that a normal style function pointer, would be better than using operator() in every way here - less code, less variables (you have to instantiate the comparators), its probably more

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: why private value of the obj can be changed by class instance? Consider the following (partial) code: class Group { private: int id; public: void set_id(int); int get_id(); bool operator==(const Group&); }; bool Group::operator==(const Group& g) { if(g.id == this->id) { /* id is private? */ return true; } return false; } The code compiles and results seem proper. However, in the if part of the operator

问题 I'd like to ensure my RAII class is always allocated on the stack. How do I prevent a class from being allocated via the 'new' operator? 回答1: All you need to do is declare the class' new operator private: class X { private: // Prevent heap allocation void * operator new (size_t); void * operator new[] (size_t); void operator delete (void *); void operator delete[] (void*); // ... // The rest of the implementation for X // ... }; Making 'operator new' private effectively prevents code outside

问题 I want to overload any operator . i want to do such a simple function that for instance think about overloading of == operator .Overload == such that x==y returns x . Or x==y return x+y. It doesn't matter what . Can you show me any simple operator overloading example? I cannot find any example on the web unfortunately. For example;when i call Tree a == Tree a return 5 (it always return 5. I select it ,it is not related to any thing) or when i call 3==4 return : 7 I tried the below codes(i

问题 I have two classes, one which inherits from the other. The relevant part of the base class is as follows (obviously this class has ctors, a dtor, etc., and particularly an operator[] , but I thought those irrelevant to the matter at hand): #include <array> template < class T, unsigned int N > class Vector { public: template < class U, unsigned int M > friend Vector< U, M > operator+ ( const Vector< U, M >&, const Vector< U, M >& ); template < class U, unsigned int M > friend std::ostream&