operator-keyword

I've a few lines of code within a project, that I can't see the value of... buffer[i] = (currentByte & 0x7F) | (currentByte & 0x80); It reads the filebuffer from a file, stored as bytes, and then transfers then to buffer[i] as shown, but I can't understand what the overall purpose is, any ideas? Thanks As the other answers already stated, (currentByte & 0x7F) | (currentByte & 0x80) is equivalent to (currentByte & 0xFF) . The JLS3 15.22.1 says this is promoted to an int : When both operands of an operator &, ^, or | are of a type that is convertible (§5.1.8) to a primitive integral type, binary

I am attempting to override the << operator for a class. The purpose is basically to implement a toString() like behavior for my class, so that sending it to cout will produce useful output. Using a dummy example, I have the code below. When I attempt to compile, I get the foollowing error: $ g++ main.cpp Rectangle.cpp /tmp/ccWs2n6V.o: In function `operator<<(std::basic_ostream<char, std::char_traits<char> >&, CRectangle const&)': Rectangle.cpp:(.text+0x0): multiple definition of `operator<<(std::basic_ostream<char, std::char_traits<char> >&, CRectangle const&)' /tmp/ccLU2LLE.o:main.cpp:(.text

I was looking at the signature of new operator. Which is: void* operator new (std::size_t size) throw (std::bad_alloc); But when we use this operator, we never use a cast. i.e int *arr = new int; So, how does C++ convert a pointer of type void* to int* in this case. Because, even malloc returns a void* and we need to explicitly use a cast. There is a very subtle difference in C++ between operator new and the new operator. (Read that over again... the ordering is important!) The function operator new is the C++ analog of C's malloc function. It's a raw memory allocator whose responsibility is

Ok I do have the following code def update_state_actions states.each do |state| @state_turns[state.id] -= 1 if @state_turns[state.id] > 0 && state.auto_removal_timing == 1 end end now in the line of... @state_turns[state.id] -= 1 if @state_turns[state.id] > 0 && state.auto_removal_timing == 1 it says the error in 'block update_state_actions' : Undefined method '>' for nil:NilClass <NoMethodError> what is the cause of the error? how come > is considered as a method but it is a logical operator? Arup Rakshit how come > is considered as a method but it is a logical operator? There is no problem

I write code below: let array1: [Int] = [0,1] let array2 = array1 + [2] It just works.I want to find where + operator define. I search ArrayExtension in my workspace without result.I search Apple doc Collection Sequence Array , there is no result. Is there a way to navigate to operator definition ,like CMD + CTRL + J for func You can select the operator in the Xcode source editor, and choose "Navigate -> Jump to definition" from the menu, or press CMD+CTRL+J. (This was broken in Xcode 10, but works again in Xcode 11, which is currently in beta.) 来源： https://stackoverflow.com/questions/53651936

This question already has an answer here: How do the post increment (i++) and pre increment (++i) operators work in Java? 14 answers How is this possible as post increment operator should increase x to 66? When I did the same for y= ++x + ++x + x++; it gave a value 65 for y and 23 for x. So let me know how is java compilers solving these expression. Let Java show you. javap -c MyClass shows you bytecode: public static void main(java.lang.String[]); Code: 0: bipush 20 2: istore_1 3: getstatic #2 // Field java/lang/System.out:Ljava/io/PrintStream; 6: iinc 1, 1 9: iload_1 10: iinc 1, 1 13: iload