openpyxl

How To Position Chart in Workbook

不羁岁月 提交于 2019-12-07 12:24:20
问题 I am running python2.7, and using openpyxl version 1.8.6. I am able to generate a chart just fine, but am unable to locate anything that indicates the chart can then be positioned in a particular location in a sheet. Any assistance would be appreciated. I am using the following code to generate the chart: ws = wb2.get_sheet_by_name('Traffic Data') rowcount = ws.get_highest_row() values = Reference(ws,(1,1), (rowcount - 1,1)) labels = Reference(ws,(0,1),(rowcount,0)) title = "Events recorded

No module named openpyxl - Python 3.6 - OSX

陌路散爱 提交于 2019-12-07 09:49:25
I've installed openpyxl from the Terminal using pip3 install openpyxl without any problems. I've even double-checked by simply running import openpyxl from the Terminal window once Python is running, and it imports no problem. The problem starts when I try and import openpyxl from a script I'm building to work with a spreadsheet. I'm using Sublime Text and can't even get past the import openpyxl at the beginning of the script without running into the following error: Traceback (most recent call last): File "/Users/wcw/Desktop/test.py", line 1, in import openpyxl ImportError: No module named

Python openpyxl read until empty cell

随声附和 提交于 2019-12-07 07:59:28
I'm trying to read one column out of my Excel-file until it hits an empty cell, then it needs to stop reading. My code so far: import openpyxl import os def main(): filepath = os.getcwd() + "\test.xlsx" wb = openpyxl.load_workbook(filename=filepath, read_only=True) ws = wb['Tab2'] for i in range(2, 1000): cellValue = ws.cell(row=i, column=1).Value if cellValue != None: print(str(i) + " - " + str(cellValue)) else: break; if __name__ == "__main__": main() By running this i get the following error when it hits an empty cell. Does anybody know how i can prevent this from happening. Traceback (most

How to switch between sheets in excel openpyxl python to make changes

给你一囗甜甜゛ 提交于 2019-12-07 04:54:37
import openpyxl wb = openpyxl.load_workbook('D:\excel.xlsx') wb.get_sheet_names() After this, i can see the worksheets(85) that the excel file has. Now i want to go into each sheet, edit data in 2-3 cells (which is same for all the sheets) and then save the file. I am very new to python and i need help. Thanks In your case I see the easiest is probably import openpyxl n = 0 wb = openpyxl.load_workbook('D:\excel.xlsx') sheets = wb.sheetnames ws = wb[sheets[n]] Where n is the sheetnumber (0 is the first). Put that in a loop and increase n when you want to change the sheet. I hope below code will

Can't read excel files, using openpyxl

你离开我真会死。 提交于 2019-12-07 04:09:26
I have a list of excel files with similar last row. It contains private information about client (his name, surname, phone). Each excel file corresponds to a client. I need to make one excel file with all data about every client. I decide to do it automatically, so looked to openpyxl library. I wrote the following code, but it doesn't work correctly. import openpyxl import os import glob from openpyxl import load_workbook from openpyxl import Workbook import openpyxl.styles from openpyxl.cell import get_column_letter path_kit = 'prize_input/kit' #creating single document prize_info = Workbook(

How do i get value present in a merged cell

早过忘川 提交于 2019-12-07 03:54:45
问题 I want to get value of a merged cell that has range from D3 to H3 using openpyxl library. As per my understanding most libraries read data from 1st cell itself. Thus the merged content is present in it but I get a none value when I read it. Following is my code: wb = load_workbook(work_directory_path+'/outputs/report_vap.xlsx') ws = wb.get_sheet_by_name("Summary") suite_path = ws.cell('D3').value if not isinstance(suite_path, unicode): value=unicode(suite_path) value=value.encode('utf8')

how to output xlsx generated by Openpyxl to browser?

家住魔仙堡 提交于 2019-12-07 03:46:01
问题 I was using stackoverflow for a while now and it helped me very often. Now I have a problem I couldn't solve myself or through searching. I'm trying to output my excel file generated by openpyxl in browser as I was doing it with phpexcel. The method appears to be the same, but I only get broken file. My code looks like this: from openpyxl.workbook import Workbook from openpyxl.writer.excel import ExcelWriter from openpyxl.writer.excel import save_virtual_workbook from openpyxl.cell import get

How to create a hyperlink to a different Excel sheet in the same workbook

时光毁灭记忆、已成空白 提交于 2019-12-07 01:13:24
问题 I'm using the module openpyxl for Python and am trying to create a hyperlink that will take me to a different tab in the same Excel workbook. Doing something similar to the following creates the hyperlink; however, when I click on it, it tells me it can't open the file. from openpyxl import Workbook wb = Workbook() first_sheet = wb.create_sheet(title='first') second_sheet = wb.create_sheet(title='second') first_sheet['A1'] = "hello" second_sheet['B2'] = "goodbye" link_from = first_sheet['A1']

Fill a image in a cell excel using python

北慕城南 提交于 2019-12-06 14:21:49
问题 I am trying to add a resized photo into a excel file using openpyxl module for python i am using the following code but didnt work... only adds the photo (not resized) from the specified cell. import openpyxl from openpyxl import load_workbook from openpyxl import Workbook wb = load_workbook('file.xlsx') ws = wb.active img = Image.open('photo.jpg') nimg = img.resize((140,92)) img=openpyxl.drawing.image.Image('photo.jpg') ws.add_image(img, 'F2') #where F2 is the cell where i want to add the

Is openpyxl the fastest package to use to read big xlsx files?

女生的网名这么多〃 提交于 2019-12-06 12:43:28
问题 I'm a python beginner but I'm writing a script using openpyxl to read in big xlsx files (60000x187) into Numpy arrays to do some machine learning. My code: from openpyxl import load_workbook import re from numpy import * wb = load_workbook(filename = 'dataSheet.xlsx', use_iterators = True) #dataSheet.xlsx ws1 = wb.get_sheet_by_name(name = 'LogFileData') startCol = 1 #index from 1 startRow = 2 #start at least from 2 because header is in 1st row endCol = ws1.get_highest_column() #index of last