opengl-es-2.0

I'm having a very difficult problem creating a shader program on android. when I call glCreateShader or glCreateProgram each always returns 0. I've covered all my bases with regards to troubleshooting: I checked to make sure I had an ogl context (I do, i tested this by clearing the frame buffer with various colors, which worked). I tried glGetError but it returned nothing (GL_NO_ERROR) I'm not an opengl or android expert so I don't know of any thing else that could be causing this. I've been running my app on a nexus 7 tablet and I use OpenGL ES 2.0, and I target the latest version of Android

This two are My VertexShader and Fragment Shader file: Vertex Shader File: attribute vec4 position; attribute vec4 inputTextureCoordinate; varying vec2 textureCoordinate; varying vec4 co; void main() { gl_Position = position; textureCoordinate = inputTextureCoordinate.xy; co = inputTextureCoordinate; } Fragment Shader File: uniform sampler2D videoFrame; // the texture with the scene you want to blur varying mediump vec2 textureCoordinate; varying mediump vec4 co; precision mediump float; vec4 nightVision() { float luminanceThreshold = 0.2; // 0.2 float colorAmplification = 2.0; // 4.0 float

I'm working with Android and OpenGL ES 2.0 and I am having an issue that I can't really formulate into a solid question. In the image, http://i.imgur.com/XuCHF.png , I basically have a shape to represent a ship in the middle and when it's moved to the side it gets stretched toward the vanishing point. What I am wanting to accomplish is to have the ship maintain most of its shape when it is moved. I believe it may be due to my matrices but every resource I've looked seems to use the same method. //Setting up the projection matrix final float ratio = (float) width / height; final float left =

Can I have Stencil prepared with a texture (Image) in OpenGL 2.0 So that some part of the Image will be transparent and as a result it will be transfered as is to Stencil buffer and then will use this use this stencil buffer for further drawing. EDIT by datenwolf to account for OPs question update in a answer: By @InfiniteLoop: @datenwolf thanks a lot for ur reply but no success :( here is my code - (void)render { [EAGLContext setCurrentContext:context]; glBindFramebuffer(GL_FRAMEBUFFER, defaultFramebuffer); glUseProgram(program); glClearColor(0, 104.0/255.0, 55.0/255.0, 1.0); glViewport(0, 0,

In GLSL-ES it's possible to have arrays. For example, the GLSL ES Specification gives the following example of a uniform variable that's an array: uniform vec4 lightPosition[4]; Is it possible to have vertex attributes that are arrays? In other words, is the following legal according to the spec? attribute vec4 foo[3]; // three vec4s per vertex Is the answer (either yes or no) explicitly mentioned anywhere in the GLSL ES Specification? (I can't find it, but I haven't read every line of the spec.) Also, if it is legal, how does one initialize such an attribute using the OpenGL ES 2.0 API?

I try to render using GLSurfaceView, and by docs I set format: getHolder().setFormat(PixelFormat.TRANSLUCENT); The I use GLSurfaceView.Renderer, which draws in onDrawFrame: GLES20.glClearColor(0, 0, 1, .5f); GLES20.glClear(GLES20.GL_DEPTH_BUFFER_BIT | GLES20.GL_COLOR_BUFFER_BIT); However, the GL rendering in GLSurfaceView is not translucent, and is fully blue. If I omit glClear call, then it's fully black. How do I make GL rendering to have transparent background, so that it is blended with views drawn behind it? EDIT : here is my GLSurfaceView: class GLView extends GLSurfaceView{ MyRenderer r

I want to display mesh models in OpenGL ES 2.0, where it clearly shows the actual mesh, so I don't want smooth shading across each primitive/triangle. The only two options I can think about are Each triangle has its own set of normals, all perpendicular to the triangles surface (but then I guess I can't share vertices among the triangles with this option) Indicate triangle/primitive edges using black lines and stick to the normal way with shared vertices and one normal for each vertex Does it have to be like this? Why can't I simply read in primitives and don't specify any normals and somehow