object

Calculating 2 object keys/columns from array of objects Javascript [duplicate]

十年热恋 提交于 2020-07-10 06:42:36
问题 This question already has answers here : How to aggregate objects properties? (6 answers) Closed 4 months ago . So I was working on the some column merging and filtering,but I am having trouble calculating 2 object keys (columns) from an array of objects and then mapping that result to an object key to a new array Example: var foodRevenue = [{ "Month": "2011-01", "week1_Revenue": "100.00", "week2_Revenue": "300.51", "Week3_Reenue": "200.09", "Month1_TotalRevenue": "0" }]; I want to calculate

Calculating 2 object keys/columns from array of objects Javascript [duplicate]

試著忘記壹切 提交于 2020-07-10 06:41:08
问题 This question already has answers here : How to aggregate objects properties? (6 answers) Closed 4 months ago . So I was working on the some column merging and filtering,but I am having trouble calculating 2 object keys (columns) from an array of objects and then mapping that result to an object key to a new array Example: var foodRevenue = [{ "Month": "2011-01", "week1_Revenue": "100.00", "week2_Revenue": "300.51", "Week3_Reenue": "200.09", "Month1_TotalRevenue": "0" }]; I want to calculate

Returning a Type as a Variable in TypeScript

妖精的绣舞 提交于 2020-07-10 06:23:00
问题 I'm currently writing a class factory in TypeScript, and would like to return a type as the output of a function. Although TypeScript handles types as an input--i.e. generics--beautifully, I've not yet found a way to handle types as an output. This StackOverflow question on class factories offered a particularly helpful solution, but did not fully answer my question. Given the below structure, function factory(someVar: any) { return class A { // Do something with someVar that makes this class

Returning a Type as a Variable in TypeScript

你。 提交于 2020-07-10 06:22:28
问题 I'm currently writing a class factory in TypeScript, and would like to return a type as the output of a function. Although TypeScript handles types as an input--i.e. generics--beautifully, I've not yet found a way to handle types as an output. This StackOverflow question on class factories offered a particularly helpful solution, but did not fully answer my question. Given the below structure, function factory(someVar: any) { return class A { // Do something with someVar that makes this class

Cannot apply indexing with [] to an expression of type `object'

安稳与你 提交于 2020-07-05 06:26:10
问题 H ere is my code: An ArrayList of ArrayList that returns a float: public ArrayList walls=new ArrayList(); public void Start() { walls[0] = ReturnInArrayList(279,275,0,0,90); walls[1] = ReturnInArrayList(62,275,0,0,0); walls[2] = ReturnInArrayList(62,275,62,0,90); walls[3] = ReturnInArrayList(217,275,62,-62,0); walls[4] = ReturnInArrayList(62,275,279,0,90); walls[5] = ReturnInArrayList(41,275,279,0,0); walls[6] = ReturnInArrayList(279,275,320,0,9); walls[7] = ReturnInArrayList(320,275,0,-279,0

Cannot apply indexing with [] to an expression of type `object'

陌路散爱 提交于 2020-07-05 06:24:49
问题 H ere is my code: An ArrayList of ArrayList that returns a float: public ArrayList walls=new ArrayList(); public void Start() { walls[0] = ReturnInArrayList(279,275,0,0,90); walls[1] = ReturnInArrayList(62,275,0,0,0); walls[2] = ReturnInArrayList(62,275,62,0,90); walls[3] = ReturnInArrayList(217,275,62,-62,0); walls[4] = ReturnInArrayList(62,275,279,0,90); walls[5] = ReturnInArrayList(41,275,279,0,0); walls[6] = ReturnInArrayList(279,275,320,0,9); walls[7] = ReturnInArrayList(320,275,0,-279,0

Objects.deepToString(Object o) method

ⅰ亾dé卋堺 提交于 2020-07-04 01:58:32
问题 The class java.util.Objects contains the deepEquals(Object a, Object b) method that can be used to compare objects of any type (including arrays and null references), but doesn't contain a similar deepToString(Object o) . This is disappointing. (By the way, the private constructor of this class contains the message "No java.util.Objects instances for you!" that explains to some extent why this class is so mean). That being the case, I've tried to implement the method myself: public static

passing JavaScript object to PHP not working

自古美人都是妖i 提交于 2020-07-03 15:20:55
问题 I'm trying to send my javascript object to PHP via JSON.stringify() Javascript: $('#save').on('click touch', function(){ obj = { "1" : { "1" : "hey", "2" : "hay" }, "2" : { "1" : "hey", "2" : "hay" } } var json = JSON.stringify( obj ); console.log(json) $.ajax({ type: 'POST', url: 'ajax.php', success: function(data) { alert(data); $("p").text(data); } }); }); ajax.php: <?php $obj = json_decode($json); echo $obj; ?> But this code returns an error saying that $json is not defined. I have no

passing JavaScript object to PHP not working

感情迁移 提交于 2020-07-03 15:17:27
问题 I'm trying to send my javascript object to PHP via JSON.stringify() Javascript: $('#save').on('click touch', function(){ obj = { "1" : { "1" : "hey", "2" : "hay" }, "2" : { "1" : "hey", "2" : "hay" } } var json = JSON.stringify( obj ); console.log(json) $.ajax({ type: 'POST', url: 'ajax.php', success: function(data) { alert(data); $("p").text(data); } }); }); ajax.php: <?php $obj = json_decode($json); echo $obj; ?> But this code returns an error saying that $json is not defined. I have no

javascript for loop changes original list variable

偶尔善良 提交于 2020-07-03 10:28:26
问题 I have a collection of objects called the response and I am creating another variable called object that's an empty object and creating object.array and set it to the response variable. I would think I am creating a new scope. However, if I set the age inside object.array as null, this sets the age in my response array to null . Why is this happening and how can I create a duplicate variable that doesn't affect the original? I need to keep the above variables as is. So object needs to be an