object

问题 I have two arrays of objects that are different in length but share similar information. qrySearchLocID = [{ LocalLabID: '123f', SystemID: 5000152, AppLabID: 3 }, { LocalLabID: '12BC', SystemID: 5000384, AppLabID: 3 }, ]; and qrySearch = [{ sName: 'SomePlace1', lBusinessID: 37343, SystemID: 5000152 }, { sName: 'SomePlace2', lBusinessID: 39780, SystemID: 5000156 }, { sName: 'SomePlace3', lBusinessID: 50772, SystemID: 5000519 }, { sName: 'SomePlace4', lBusinessID: 31079, SystemID: 5000384 }, ]

问题 I'm trying to assign a sub class object array to its super class. The program compiles successfully, but I' getting an ArrayStoreException . I know that arrays parent and child are references to same array, but shouldn't I be able to access method func at least? class Pclass { Pclass() { System.out.println("constructor : Parent class"); } public void func() { System.out.println("Parent class"); } } class Cclass extends Pclass { Cclass() { System.out.println("Constructor : Child class"); }

问题 I'm trying to assign a sub class object array to its super class. The program compiles successfully, but I' getting an ArrayStoreException . I know that arrays parent and child are references to same array, but shouldn't I be able to access method func at least? class Pclass { Pclass() { System.out.println("constructor : Parent class"); } public void func() { System.out.println("Parent class"); } } class Cclass extends Pclass { Cclass() { System.out.println("Constructor : Child class"); }

问题 I have a data set containing underscore(_) variable name. Such as below: const data = { m_name: 'my name', m_address: 'my address', p_1_category: 'cat 1', p_1_name: 'name 1', p_2_category: 'cat 2', p_2_name: 'name 2' } I want to split them into nested object/array, Below is the result I want. { m: { name: "my name", address: "my address" }, p: { "1": {category: 'cat 1', name: 'name 1'}, "2": {category: 'cat 2', name: 'name 2'} } } How can I write a recursive method to achive it instead of

问题 I have a piece of code like below: var selected = “A”; bool isSelected = selected == "A" || selected == "C"; var codeLists = new { displayProperty1 = isSelected ? "property1" : null, displayProperty2 = isSelected ? "property2" : null, displayProperty3 = selected == "C" ? "property3" : null }; So, my goal is to eliminate a property if it does not satisfy a condition. In the above code, selected is "A" . So, displayProperty3 would have a value of null . But I want to eliminate displayProperty3

问题 In the class 'Tosee' below, hiddenInt is visible when I call s.hiddenInt. However, when I create a "ToSee" object in another class, 'CantSee', the private variable isn't visible. Why is this so? I was under the impression that private means that in any instance of a class, the client cant see that particular instance variable or method? Why then am I able to see hiddenInt in the main method of 'ToSee'? public class ToSee { private int hiddenInt = 5; public static void main(String[] args) {

问题 I have this array of objects: var eventList = [ { eventName: "abc", status: "completed" }, { eventName: "def", status: "live" }, { eventName: "ghi", status: "live" }, { eventName: "jkl", status: "upcoming" }, ] I want to sort these array of objects using a priority array of a specific key, say ["live", "upcoming", "completed"] for status, meaning all live events come first, followed by upcoming followed by completed. Answers all over the internet seem like you can only sort array objects

问题 When searching for explanations of how logical equals == works in Java the answers are always something along the lines of: For primitives it returns whether the primitives have the same value (this includes comparing a primitive to its WrapperObject as the WrapperObject gets automatically unboxed to a primitive). For Objects it returns whether they represent the same Object on the Heap. But these explanations all seem to imply that these are 2 different things , that == behaves differently

问题 Can somebody explain the behaviour of the following code? let obj = {a:1, b:2} let i = ['a'] console.log(obj[i]) >> 1 Why is it that even an array can be used to access a property inside an object? As a side note this only works with an array of length 1. I have tried researching this but there's no documentation as far as I know that explains why this should work. 回答1: Property names are always strings or symbols. If you pass something which isn't a string or symbol, it gets converted to a

问题 Can somebody explain the behaviour of the following code? let obj = {a:1, b:2} let i = ['a'] console.log(obj[i]) >> 1 Why is it that even an array can be used to access a property inside an object? As a side note this only works with an array of length 1. I have tried researching this but there's no documentation as far as I know that explains why this should work. 回答1: Property names are always strings or symbols. If you pass something which isn't a string or symbol, it gets converted to a