numpy

Rearranging axes in numpy?

由 拟墨画扇 提交于 2021-02-06 20:01:53
问题 I have an ndarray such as >>> arr = np.random.rand(10, 20, 30, 40) >>> arr.shape (10, 20, 30, 40) whose axes I would like to swap around into some arbitrary order such as >>> rearranged_arr = np.swapaxes(np.swapaxes(arr, 1,3), 0,1) >>> rearranged_arr.shape (40, 10, 30, 20) Is there a function which achieves this without having to chain together a bunch of np.swapaxes ? 回答1: There are two options: np.moveaxis and np.transpose. np.moveaxis(a, sources, destinations) docs This function can be

Calculate weighted pairwise distance matrix in Python

由 白昼怎懂夜的黑 提交于 2021-02-06 20:01:48
问题 I am trying to find the fastest way to perform the following pairwise distance calculation in Python. I want to use the distances to rank a list_of_objects by their similarity. Each item in the list_of_objects is characterised by four measurements a, b, c, d, which are made on very different scales e.g.: object_1 = [0.2, 4.5, 198, 0.003] object_2 = [0.3, 2.0, 999, 0.001] object_3 = [0.1, 9.2, 321, 0.023] list_of_objects = [object_1, object_2, object_3] The aim is to get a pairwise distance

Calculate weighted pairwise distance matrix in Python

由 情到浓时终转凉″ 提交于 2021-02-06 20:01:18
问题 I am trying to find the fastest way to perform the following pairwise distance calculation in Python. I want to use the distances to rank a list_of_objects by their similarity. Each item in the list_of_objects is characterised by four measurements a, b, c, d, which are made on very different scales e.g.: object_1 = [0.2, 4.5, 198, 0.003] object_2 = [0.3, 2.0, 999, 0.001] object_3 = [0.1, 9.2, 321, 0.023] list_of_objects = [object_1, object_2, object_3] The aim is to get a pairwise distance

Rearranging axes in numpy?

由 大憨熊 提交于 2021-02-06 20:01:06
问题 I have an ndarray such as >>> arr = np.random.rand(10, 20, 30, 40) >>> arr.shape (10, 20, 30, 40) whose axes I would like to swap around into some arbitrary order such as >>> rearranged_arr = np.swapaxes(np.swapaxes(arr, 1,3), 0,1) >>> rearranged_arr.shape (40, 10, 30, 20) Is there a function which achieves this without having to chain together a bunch of np.swapaxes ? 回答1: There are two options: np.moveaxis and np.transpose. np.moveaxis(a, sources, destinations) docs This function can be

Calculate weighted pairwise distance matrix in Python

由 最后都变了- 提交于 2021-02-06 20:00:43
问题 I am trying to find the fastest way to perform the following pairwise distance calculation in Python. I want to use the distances to rank a list_of_objects by their similarity. Each item in the list_of_objects is characterised by four measurements a, b, c, d, which are made on very different scales e.g.: object_1 = [0.2, 4.5, 198, 0.003] object_2 = [0.3, 2.0, 999, 0.001] object_3 = [0.1, 9.2, 321, 0.023] list_of_objects = [object_1, object_2, object_3] The aim is to get a pairwise distance

ImportError: cannot import name add_newdocs

由 生来就可爱ヽ(ⅴ＜●) 提交于 2021-02-06 20:00:31
问题 I use Windows8.1 and python 2.7 and I installed the numpy1.8 . However, whenever I wanna import numpy it shows the following error : ImportError: cannot import name add_newdocs . >>> import numpy Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python27\lib\site-packages\numpy\__init__.py", line 153, in <module> from . import add_newdocs ImportError: cannot import name add_newdocs I have checked with C:\Python27\Lib\site-packages\numpy the add_newdocs does exist

Calculate weighted pairwise distance matrix in Python

由 梦想的初衷 提交于 2021-02-06 20:00:27
问题 I am trying to find the fastest way to perform the following pairwise distance calculation in Python. I want to use the distances to rank a list_of_objects by their similarity. Each item in the list_of_objects is characterised by four measurements a, b, c, d, which are made on very different scales e.g.: object_1 = [0.2, 4.5, 198, 0.003] object_2 = [0.3, 2.0, 999, 0.001] object_3 = [0.1, 9.2, 321, 0.023] list_of_objects = [object_1, object_2, object_3] The aim is to get a pairwise distance

ImportError: cannot import name add_newdocs

由 最后都变了- 提交于 2021-02-06 19:58:21
问题 I use Windows8.1 and python 2.7 and I installed the numpy1.8 . However, whenever I wanna import numpy it shows the following error : ImportError: cannot import name add_newdocs . >>> import numpy Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python27\lib\site-packages\numpy\__init__.py", line 153, in <module> from . import add_newdocs ImportError: cannot import name add_newdocs I have checked with C:\Python27\Lib\site-packages\numpy the add_newdocs does exist

B站上适合程序员的学习资源【建议收藏！】

由 最后都变了- 提交于 2021-02-06 15:47:45
“二次元，鬼畜，动漫”是大家提到B站，最容易冒出来的关键词！然而央视网一条微博却表示：过去一年有近2000万人在B站学习，相当于去年高考人数的2倍！B站正在成为年轻人学习的首要阵地。 下面整理一些适合程序员的学习资源，建议大家收藏！ 一、数学基础： 1.Up主：3Blue1Brown的数学基础： https://space.bilibili.com/88461692 用动画讲述数学专业知识，其视频涵盖了线性代数、微积分、拓扑学等领域，每门课都配有直观生动的动画演示，帮助观众加深对数学概念定理的理解。 2.数学分析： https://www.bilibili.com/video/av8042121 复旦陈纪修老师的数学分析视频课程，共214讲。 3.数学建模：www.bilibili.com/video/av8824879 清华大学数学建模公开课，共84讲。 4.统计学： https://www.bilibili.com/video/av7199273 可汗学院公开课，统计学所有内容都涵盖了。共85讲。 二、C与C++篇 1.《带你学C带你飞》（小甲鱼）： https://www.bilibili.com/video/av27744141 2.《C++快速入门》（小甲鱼）： https://www.bilibili.com/video/av28127959 三、Python 入门&

python 列表和字符串

由 旧城冷巷雨未停 提交于 2021-02-06 15:44:56
python 列表中保留所有字符串前三项，并保存到一个新的列表 l = [s[:3] for s in data] python 在列表中查找包含所以某个字符串的项，并保存到一个新的列表 l = [s for s in data if 'FF' in s] # 两个list的差集，并集和交集 https://blog.csdn.net/liao392781/article/details/80577483 方法一： list1 = [ ' a ' , ' b ' , ' c ' ] list3 = list1 list2 = [ ' a ' ] for i in list2: list3.remove(i) list3 Out[ 7]: [ ' b ' , ' c ' ] 方法二： list3 = list(set(list1) - set(list2)) # 列表相除、列表相加 import numpy as np a =[1,2 ] # 1、得到列表 <class 'list'> b=[i/2 for i in a]; print (b) # 2、得到<class 'numpy.ndarray'> b=np.array(a)/2; print (b) # 多个列表加减，用numpy c=np.array(a)+np.array(b)*2 print (c)
订阅 numpy