numbers

C/C++ Large number calculation

半腔热情 提交于 2019-12-04 10:44:17
I'm trying to compute the following number in a C program : result = (3 * pow(2,500000000) - 2 ) % 1000000000 The power of 2 is way to large to be handled properly => I'm under the impression I could split the calculation in many steps using the modulo to reduce the result size. Does someone has a strategy for doing so ? Any other idea ? Thanx in advance Manu The simplest method is exponentiation by repeated squaring reducing by the modulus in each step. unsigned long long mod_pow(unsigned long long base, unsigned long long exponent, unsigned long long modulus) { if (exponent == 0) return 1;

Convert mysql query results to CSV (with copy/paste)

耗尽温柔 提交于 2019-12-04 10:14:54
问题 I often work in command line mysql. A common need is to take a query's results and import them into a Numbers document (similar to an Excel document). What is the fastest method for doing this? Method 1: Select into outfile You can select into an outfile directly from MySQL, but this takes several steps. export your query with all the necessary arguments to make it a CSV format, like FIELDS OPTIONALY ENCLOSED BY and DELIMITED BY . sftp into the server and grab the file delete the file from

Are there any libraries for parsing “number expressions” like 1,2-9,33- in Java

亡梦爱人 提交于 2019-12-04 09:18:53
I don't think it is hard, just tedious to write: Some small free (as in beer) library where I can put in a String like 1,2-9,33- and it can tell me whether a given number matches that expression. Just like most programs have in their print range dialogs. Special functions for matching odd or even numbers only, or matching every number that is 2 mod 5 (or something like that) would be nice, but not needed. The only operation I have to perform on this list is whether the range contains a given (nonnegative) integer value; more operations like max/min value (if they exist) or an iterator would be

Faster way to find out if a number starts with 2?

时间秒杀一切 提交于 2019-12-04 08:53:42
In Java - what is the faster way to find if the given integer number is starting with the digit 2 without having to convert the number into a string? String.valueOf(number).charAt(0) == '2' Jon Skeet If you wanted to avoid converting it to a string, you could just keep dividing by 10 to find the most significant digit: int getMostSignificantDigit(int x) { // Need to handle Integer.MIN_VALUE "specially" as the absolute value can't // represented. We can hard-code the fact that it starts with 2 :) x = x == Integer.MIN_VALUE ? 2 : Math.abs(x); while (x >= 10) { x = x / 10; } return x; } I don't

Test cases for numeric input

给你一囗甜甜゛ 提交于 2019-12-04 08:34:10
What are some common (or worthwhile) tests, test questions, weaknesses, or misunderstandings dealing with numeric inputs? This is a community wiki. Please add to it. For example, here are a couple sample ideas: I commonly see users enter text into number fields (eg, ">4" or "4 days", etc). Fields left blank (null) Very long numeric strings Multiple decimals and commas (eg, "4..4" and "4,,434.4.4") Boundary Value Analysis: Lower Boundary Lower Boundary - 1 (for decimal/float, use smaller amounts) Upper Boundary Upper Boundary + 1 Far below the lower boundary (eg, beyond the hardware boundary

Oracle hibernate sequence generator problem

扶醉桌前 提交于 2019-12-04 08:02:26
问题 I am developing an application using oracle 11g, Java(struts2) and Hibernate. I have table named mytemp with column mytemp_id which is of type NUMBER(22,0). In my mytemp.hbm.xml file id is as given below <id name="mytempId" type="big_decimal"> <column name="MYTEMP_ID" precision="22" scale="0" /> <generator class="sequence"> <param name="sequence">MYTEMP_TEMP_ID_SEQ</param> </generator> </id> In my Oracle database sequence named "MYTEMP_TEMP_ID_SEQ" is created and working fine in Oracle. Now

Biggest number in computer ever

六月ゝ 毕业季﹏ 提交于 2019-12-04 07:41:43
问题 Just asked by my 5 year old kid: what is the biggest number in the computer? We are not talking about max number for a specific data types, but the biggest number that a computer can represent. Infinity is not allowed. UPDATE my kid always wants to print as well, so lets say the computer needs to print this number and the kid to know that its a big number. Of course, in practice we won't print because theres not enough trees. 回答1: This question is actually a very interesting one which

jquery input number [duplicate]

旧街凉风 提交于 2019-12-04 07:41:32
Possible Duplicate: Is it possible to customize an input field for amounts with +- buttons? how to make + (plus) and - (minus) value buttons for <input type="number" class="numbertype" value="10"> ? I think it's possible to do with jQuery or maybe simple javascipt, but i don't know how.. I want do something like this : when you push on + button, value will be bigger for 1 (0,12,3,4,5,6.... 10000) when you push on - button, value will be smaller for 1 (10,9,8,7,6,5,4... 0) $("#minus,#plus").click(function(){ var value = parseInt($(".numbertype").val(), 10); $(".numbertype").val(value + $(this)

The maximum value for an int type in Go

六月ゝ 毕业季﹏ 提交于 2019-12-04 07:26:01
问题 How does one specify the maximum value representable for an unsigned integer type? I would like to know how to initialize min in the loop below that iteratively computes min and max lengths from some structs. var minLen uint = ??? var maxLen uint = 0 for _, thing := range sliceOfThings { if minLen > thing.n { minLen = thing.n } if maxLen < thing.n { maxLen = thing.n } } if minLen > maxLen { // If there are no values, clamp min at 0 so that min <= max. minLen = 0 } so that the first time

Converting number into word

天大地大妈咪最大 提交于 2019-12-04 07:18:49
问题 I am a beginner and I have written a program in c++ to convert numbers between 0-99999 into words. It is working fine for numbers upto 100 but after that it gives wrong output. I know there are some serious logical errors but I am just unable to figure these out. //This program converts number into words between 0-99999 #include<iostream> using namespace std; main() { long int number,unit,ten,hundred,thousand,ten_thousand; cout<<"Please enter any number between 0-99999: "; cin>>number; ten