numbers

JDK1.5开始， 支持一个方法的定义可用来传递同类型的可变参数，但有要求： 1、在方法声明中，在指定参数类型后加一个省略号（...） 2、一个方法只能指定一个可变参数，它必须是方法的最后一个参数，任何普通的参数必须在它之前的声明。 用法例：常用于判断多个数值或某数组中的最大最少值 代码： public static void main(String[] args){ 　　printMax(23,43,12,56); // 　　printMax(new double[]{1,2,3}); //也可以是数组 } public static void printMax(double ... numbers){ 　　if(numbers.length==0){ 　　　　System.out.println("无数据"); 　　　　return; 　　} 　　double result=number[0]; 　　for(int i=1; i<numbers.length;i++){ 　　　　if(number[i]>result){ 　　　　　　result=number[i]; 　　　　} 　　} 　　System.out.println("最大值是"+result); } 来源： https://www.cnblogs.com/bbq668/p/11988516.html

For the following code snippet: $a = '5 USD'; $b = 10; echo $a + $b; The answer is 15. But in the variable $a if 5 is in between 'USD' or after 'USD' the output is 10 . Why it is so? Can somebody explain? Num6 From php.net : When a string is evaluated in a numeric context, the resulting value and type are determined as follows. If the string does not contain any of the characters '.', 'e', or 'E' and the numeric value fits into integer type limits (as defined by PHP_INT_MAX), the string will be evaluated as an integer. In all other cases it will be evaluated as a float. The value is given by

I have an array which contains lets say [25,15,8,20] I want to find all possible arrangements of numbers that is possible. expected output: 25 15 8 20 25 15 20 8 25 20 15 8 25 20 8 15 25 8 20 15 25 8 15 20 15 25 8 20 15 25 20 8 15 20 25 8 15 20 8 25 15 8 20 25 15 8 25 20 20 25 15 8 20 25 8 15 20 8 25 15 20 8 15 25 20 15 25 8 20 15 8 25 8 15 20 25 8 15 25 20 8 25 15 20 8 25 20 15 8 20 15 25 8 20 25 15 void print(int *num, int n) { int i; for ( i = 0 ; i < n ; i++) printf("%d ", num[i]); printf("\n"); } int main() { int num[N]; int *ptr; int temp; int i, n, j; printf("\nHow many number you want

Currently my program (see below) generates random strings (made of numbers) from 8 - 12 characters in length. public static string GenerateNewCode(int CodeLength) { string newCode = String.Empty; int seed = unchecked(DateTime.Now.Ticks.GetHashCode()); Random random = new Random(seed); // keep going until we find a unique code ` do { newCode = random.Next(Convert.ToInt32(Math.Pow(10, CodeLength - 1)), Convert.ToInt32(Math.Pow(10, CodeLength) - 1)).ToString("0000"); } while (!ConsumerCode.isUnique(newCode)); // return return newCode; } However, their is a problem with the method, when the

I have a string var x='abcdefg1234abcdefg'; I want to replace 1234 with 555 using the x.replace() function like x=x.replace(stuff here) I tried to pass '1234','555' as the parameters but it's not working. Any clues? thanks Edit: The string is in a hidden <input> field. The value of it is: <object id="player" classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" name="player" width="400" height="385"> <param name="movie" value="player.swf" /> <param name="allowfullscreen" value="true" /> <param name="allowscriptaccess" value="always" /> <param name="flashvars" value="provider=http&file=files

I don't have enough reputation points yet to leave comments, but saw numerous times when people (incorrectly) suggest using log10 to calculate the number of digits in a positive integer. This is wrong for large numbers! long n = 99999999999999999L; // correct answer: 17 int numberOfDigits = String.valueOf(n).length(); // incorrect answer: 18 int wrongNumberOfDigits = (int) (Math.log10(n) + 1); // also incorrect: double wrongNumberOfDigits2 = Math.floor(Math.log10(n) + 1); The logarithm-based solutions will incorrectly output 18 instead of 17. I'd like to understand why. Way to get number of