numbers

C#语言基础： 数组及数组的运用

由 空扰寡人 提交于 2019-12-27 14:46:56
　什么是数组？那数组又是怎么运用的呢？接下来，我来揭开谜底。 我们把能够存放任意多个同类型的数据的组合叫做数组。也可以说数组是由多个数组项组成，每个数组项的类型相同，并且每个数组项对应1个编号，这些编号叫做数组的索引，也称为下标。数组的数组项的编号都是从0开始，依次为数组项编号。　 数组声明的表达式为：数据类型[ ] 变量名 ；数组赋值表达式为：变量名=new 数据类型[ 长度] 　[长度]是int类型　，赋值的数据类型必须与声明的数据类型一致。 注意：一个数组创建后，它每个数组项的值，为数组项类型的默认值：数字类型，默认值为0；bool类型，默认值为false；char类型，默认值为转义符（\0.表示空字符）；string类型，默认值为null，表示“空”。 数组的读取：变量名[索引]，从指定数组中，通过编号取出某一个数组项的值，返回类型与数组项类型相同。 比如：int[ ] numbers=new int[5]; 意思就是，定义了一个number变量，它是一个数组，可以存放5个int类型的数据。 数组的修改：表达式为 变量名[索引]=值； 代码示例： int [ ] number=new int(5); numbers[0]=3; numbers[5]=-2; numbers[3]=numbers[0]*2+numbers[1]; console.writeline

python - checking odd/even numbers and changing outputs on number size

由 主宰稳场 提交于 2019-12-27 13:39:17
问题 I have a couple of problems to solve for an assignment, and am a bit stuck. The question is to write a program that gets the user to input an odd number (check it's odd), then print an upside down pyramid of stars based on the size of the input. For example, if you enter 5, it comes up with ***** *** * My problem is therefore two-fold. 1) How do I check if it's even or odd? I tried if number/2 == int in the hope that it might do something, and the internet tells me to do if number%2==0 , but

python - checking odd/even numbers and changing outputs on number size

由 泪湿孤枕 提交于 2019-12-27 13:37:44
问题 I have a couple of problems to solve for an assignment, and am a bit stuck. The question is to write a program that gets the user to input an odd number (check it's odd), then print an upside down pyramid of stars based on the size of the input. For example, if you enter 5, it comes up with ***** *** * My problem is therefore two-fold. 1) How do I check if it's even or odd? I tried if number/2 == int in the hope that it might do something, and the internet tells me to do if number%2==0 , but

python - checking odd/even numbers and changing outputs on number size

由 旧巷老猫 提交于 2019-12-27 13:37:36
问题 I have a couple of problems to solve for an assignment, and am a bit stuck. The question is to write a program that gets the user to input an odd number (check it's odd), then print an upside down pyramid of stars based on the size of the input. For example, if you enter 5, it comes up with ***** *** * My problem is therefore two-fold. 1) How do I check if it's even or odd? I tried if number/2 == int in the hope that it might do something, and the internet tells me to do if number%2==0 , but

Are there are any side effects of using this method to convert a string to an integer

由 我的梦境 提交于 2019-12-27 12:08:07
问题 Are there any side effects if i convert a string to a number like below.. var numb=str*1; If I check with the below code it says this is a number.. var str="123"; str=str*1; if(!isNaN(str)) { alert('Hello'); } Please let me know if there are any concerns in using this method.. 回答1: When you use parseFloat , or parseInt , the conversion is less strict. 1b5 -> 1. Using 1*number or +number to convert will result in NaN when the input is not valid number. Though unlike parseInt , floating point

PHP: Express Number in Words [duplicate]

由 纵然是瞬间 提交于 2019-12-27 11:41:40
问题 This question already has answers here : Is there an easy way to convert a number to a word in PHP? (11 answers) Closed 3 years ago . Is there a function that will express any given number in words? For example: If a number is 1432 , then this function will return "One thousand four hundred and thirty two". 回答1: Use the NumberFormatter class that are in php ;) $f = new NumberFormatter("en", NumberFormatter::SPELLOUT); echo $f->format(1432); That would output "one thousand four hundred thirty

PHP: Express Number in Words [duplicate]

由 ↘锁芯ラ 提交于 2019-12-27 11:41:32
问题 This question already has answers here : Is there an easy way to convert a number to a word in PHP? (11 answers) Closed 3 years ago . Is there a function that will express any given number in words? For example: If a number is 1432 , then this function will return "One thousand four hundred and thirty two". 回答1: Use the NumberFormatter class that are in php ;) $f = new NumberFormatter("en", NumberFormatter::SPELLOUT); echo $f->format(1432); That would output "one thousand four hundred thirty

add commas to a number in jQuery

由 前提是你 提交于 2019-12-27 11:02:49
问题 I have these numbers 10999 and 8094 and 456 And all i want to do is add a comma in the right place if it needs it so it looks like this 10,999 and 8,094 and 456 These are all within a p tag like this <p class="points">10999</p> etc. Can it be done? I've attempted it here with the help of other posts http://jsfiddle.net/pdWTU/1/ but can't seem to get it to work Thanks Jamie UPDATE Messed around a bit and managed to figure it out here http://jsfiddle.net/W5jwY/1/ Going to look at the new

add commas to a number in jQuery

由 一世执手 提交于 2019-12-27 11:01:38
问题 I have these numbers 10999 and 8094 and 456 And all i want to do is add a comma in the right place if it needs it so it looks like this 10,999 and 8,094 and 456 These are all within a p tag like this <p class="points">10999</p> etc. Can it be done? I've attempted it here with the help of other posts http://jsfiddle.net/pdWTU/1/ but can't seem to get it to work Thanks Jamie UPDATE Messed around a bit and managed to figure it out here http://jsfiddle.net/W5jwY/1/ Going to look at the new

Why does the html input with type “number” allow the letter 'e' to be entered in the field?

由 流过昼夜 提交于 2019-12-27 10:39:06
问题 I have the following html5 input element: <input type="number"> Why does this input allow for the character 'e' to be entered in the input field? No other alphabet character is able to be entered (as expected) Using chrome v. 44.0.2403.107 To see what I mean: http://www.w3schools.com/html/tryit.asp?filename=tryhtml_input_number 回答1: Because that's exactly how the spec says it should work. The number input can accept floating-point numbers, including negative symbols and the e or E character
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