numbers

JSON Not converting long numbers appropriately

风流意气都作罢 提交于 2020-01-19 09:56:26
问题 I have a simple JSON where number is not getting parsed properly. [ { "orderNumber": 1, "customerId": 228930314431312345, "shoppingCartId": 22893031443137109, "firstName": "jjj" } ] I tried it @ http://www.utilities-online.info/xmltojson/ and the result was <?xml version="1.0" encoding="UTF-8" ?> <orderNumber>1</orderNumber> <customerId>228930314431312350</customerId> <shoppingCartId>22893031443137108</shoppingCartId> <firstName>jjj</firstName> As you can see....the XML is different from JSON

jquery how to empty input field

删除回忆录丶 提交于 2020-01-19 02:19:25
问题 I am in a mobile app and I use an input field in order user submit a number. When I go back and return to the page that input field present the latest number input displayed at the input field. Is there any way to clear the field every time the page load? $('#shares').keyup(function(){ payment = 0; calcTotal(); gtotal = ($('#shares').val() * 1) + payment; gtotal = gtotal.toFixed(2); $("p.total").html("Total Payment: <strong>" + gtotal + "</strong>"); }); 回答1: You can clear the input field by

Sum all the digits of a number Javascript

拥有回忆 提交于 2020-01-18 16:18:59
问题 I am newbie. I want to make small app which will calculate the sum of all the digits of a number. For example, if I have the number 2568, the app will calculate 2+5+6+8 which is equal with 21. Finally, it will calculate the sum of 21's digits and the final result will be 3 . Please help me 回答1: Basically you have two methods to get the sum of all parts of an integer number. With numerical operations Take the number and build the remainder of ten and add that. Then take the integer part of the

Sum all the digits of a number Javascript

我们两清 提交于 2020-01-18 16:13:44
问题 I am newbie. I want to make small app which will calculate the sum of all the digits of a number. For example, if I have the number 2568, the app will calculate 2+5+6+8 which is equal with 21. Finally, it will calculate the sum of 21's digits and the final result will be 3 . Please help me 回答1: Basically you have two methods to get the sum of all parts of an integer number. With numerical operations Take the number and build the remainder of ten and add that. Then take the integer part of the

Create Alphabet List from list : Java

我怕爱的太早我们不能终老 提交于 2020-01-17 05:52:05
问题 I have a list which contains the Filename from a given path, fileNamesList and from this list i would like to create a Alphabet list like if there are files name start with A then add A to list and like so upto Z and in the same way i want to create Numbers List also from 0 to 9 All these Alphabet and Number checking is based on Starts with from the file name . how to do this in java. Finally the AlphabetList will be like A B E F....Z and the Numbers list will be 1 2 3 9 thanks 回答1: After

jQuery UI Slider and jQuery Globalization with value delimited by comma [ , ]

浪子不回头ぞ 提交于 2020-01-16 16:15:11
问题 I'm developing an ASP.NET MVC 3 app that uses both jQuery Globalization and jQuery UI Slider. I'm localizing this app to Portuguese from Brazil (pt-BR) and it also supports English. The problem is that when I change the language to Portuguese, all Model float values come delimited by a comma ( , ) like 7,7. I then try to set the Slider initial value but it only accepts the value with a dot ( . ) like 7.7. To overcome such situation I'm doing this: $.CreateSlider("#sliderHeight", "#Height",

jQuery UI Slider and jQuery Globalization with value delimited by comma [ , ]

喜欢而已 提交于 2020-01-16 16:15:10
问题 I'm developing an ASP.NET MVC 3 app that uses both jQuery Globalization and jQuery UI Slider. I'm localizing this app to Portuguese from Brazil (pt-BR) and it also supports English. The problem is that when I change the language to Portuguese, all Model float values come delimited by a comma ( , ) like 7,7. I then try to set the Slider initial value but it only accepts the value with a dot ( . ) like 7.7. To overcome such situation I'm doing this: $.CreateSlider("#sliderHeight", "#Height",

C#之快速排序

不打扰是莪最后的温柔 提交于 2020-01-16 14:08:18
快速排序(Quicksort)是对冒泡排序的一种改进。 快速排序的基本概念是 : 通过一趟排序将要排序的数据分割成独立的两部分,其中一部分的所有数据都比另外一部分的所有数据都要小, 然后再按此方法对这两部分数据分别进行快速排序,整个排序过程可以 递归 进行,以此达到整个数据变成有序序列。 下面通过一个例子来了解快速排序的具体含义: { 23, 45, 60, 10, 17, 101,12} 第一遍排序: 由此思想,我们可以实现快速排序的代码: 注意基准数据永远不变,永远是和基准数据进行比较,无论在什么位置,最后的目的就是把基准数据放在中间,小的放前面大的放后面。 namespace QuickSort { class QuickSort { private int Func(int[] n, int left, int right) { int baseNum = n[left]; // 基准数据 int i = left; int j = right; while (true) { if (n[i] < baseNum && i < j) { i++; } else if (n[i] > baseNum && i < j) { int number = n[i]; n[i] = n[j]; n[j] = number; j--; } else if (n[j] < baseNum

How to avoid the multiple use of 'isnan' to filter inconsitent datasets?

不打扰是莪最后的温柔 提交于 2020-01-16 13:22:26
问题 I have two corresponded (has a relation and has the same dimension) dataset: Time Salinity Some data in salinity dataset is NaN. I can remove the NaN value by: Salinity_new=Salinity(~isnan(Salinity)) But it will not correspond to the Time dataset any more. How can I remove the corresponded time in also? Thanks 回答1: The comments of Diavakar and patrik are correct. To sum it up and get this question answered, some further remarks. mask = isfinite(Salinity) [Time,Salinity] = deal( Time(mask),

How to avoid the multiple use of 'isnan' to filter inconsitent datasets?

混江龙づ霸主 提交于 2020-01-16 13:21:29
问题 I have two corresponded (has a relation and has the same dimension) dataset: Time Salinity Some data in salinity dataset is NaN. I can remove the NaN value by: Salinity_new=Salinity(~isnan(Salinity)) But it will not correspond to the Time dataset any more. How can I remove the corresponded time in also? Thanks 回答1: The comments of Diavakar and patrik are correct. To sum it up and get this question answered, some further remarks. mask = isfinite(Salinity) [Time,Salinity] = deal( Time(mask),