numbers

How to divide large numbers and what algorithm to use

孤街浪徒 提交于 2019-12-01 05:37:06
问题 I want to manipulate really big numbers and I am trying to work with arrays. I have already implemented the multiplication operation, but now I want to implement the division operation. I was wondering which algorithm(s) should I use? Is it possible to use the Newton–Raphson division algorithm or maybe should I use the algorithm that we learned in the school? PS: I know that there are many libraries that work with big numbers, but I want to do this for practice. 回答1: These are my favorite

java number exceeds long.max_value - how to detect?

喜你入骨 提交于 2019-12-01 04:51:28
I'm having problems detecting if a sum/multiplication of two numbers exceeds the maximum value of a long integer. Example code: long a = 2 * Long.MAX_VALUE; System.out.println("long.max * smth > long.max... or is it? a=" + a); This gives me -2 , while I would expect it to throw a NumberFormatException ... Is there a simple way of making this work? Because I have some code that does multiplications in nested IF blocks or additions in a loop and I would hate to add more IFs to each IF or inside the loop. Edit: oh well, it seems that this answer from another question is the most appropriate for

SQLite issue with Table Names using numbers?

早过忘川 提交于 2019-12-01 04:46:33
I'm developing an app which requires that the user selects a year formatted like this 1992-1993 from a spinner. The tablename is also named 1992-1993 and the idea is that using SQL the values from this table are pulled through with a statement like this select * from 1992-1993 . When I run the emulator however, it throws an error. If I then relabel the Spinner item to NinetyTwo and rename the table to NinetyTwo and run the emulator it runs as expected and the data is pulled through from the table. Does SQLite have an issue with numbers in table names? eumiro Yes and No. It has an issue with

Python基本语法

喜欢而已 提交于 2019-12-01 04:36:36
在网易云课堂上参与了Python学习的课,竟然有1000+个视频。花了几天时间,已经看完了前100个Python基本语法入门的视频。 整理一下目前学到的知识。 1 学习环境 Python Pycharm Anaconda 学习这部分基本语法都是使用Python自带的IDLE。 2 变量,算术运算符,赋值运算符,布尔型运算符,比较运算符(and,or,not) Tips: 赋值运算时: x,y,z=1,2,3 可以快速赋值。 price+=2 或 price-=2 和 price=price+2 意义相同。 3 整数,浮点数,字符串,类型转换,字符串方法 Tips: type()查看数据类型 'I\'m learning Python!' 其中的斜杠可以将’抵消。 字符串支持乘法和加法,不支持除法和减法。 First_word='Hello' Second_word='World' print(First_word+' '+Second_word) 常用函数len() int(True)返回值是1,false是0 字符串方法: islower():判断是否都为小写 count(‘o’):计算字符串中出现’o’的次数 find(‘o’):寻找字符串中’o’出现的位置,空格计算在内,且初始位为0 4 列表及列表函数(list) 4.1 列表索引 A_list_of_things=[

How to rotate an image by a random amount using CSS?

偶尔善良 提交于 2019-12-01 04:30:22
I have a gallery of 20 images on my web page that I would like to rotate by a random amount (-5 to 5 degrees) upon hover over each image. If possible, I'd like to use just CSS. If not, I would be open to using JavaScript or jQuery. My CSS is as follows: .photo:hover { z-index:1; transform:rotate(6deg) scale(1.25); -webkit-transform:rotate(6deg) scale(1.25); -moz-transform:rotate(6deg) scale(1.25); -ms-transform:rotate(6deg) scale(1.25); } 6deg should be a random number, so every time the user hovers over an image, it rotates by a random amount between -5 and 5. Can I call a JavaScript function

Converting two Uint32Array values to Javascript number

南楼画角 提交于 2019-12-01 04:15:25
问题 I found a code from here that converts Javascript number to inner IEEE representation as two Uint32 values: function DoubleToIEEE(f) { var buf = new ArrayBuffer(8); (new Float64Array(buf))[0] = f; return [ (new Uint32Array(buf))[0] ,(new Uint32Array(buf))[1] ]; } How to convert the returned value back to Javascript number? This way: var number = -10.3245535; var ieee = DoubleToIEEE(number) var number_again = IEEEtoDouble(ieee); // number and number_again should be the same (if ever possible)

Representation of a Kilo/Mega/Tera Byte

心不动则不痛 提交于 2019-12-01 03:38:17
问题 I was getting a little confused with the representation of different units of bytes. It is accepted throughout that 1 byte = 8 bits. However, in a lot of sources I have seen that 1 kiloByte = 2^10 bytes = 1024 bytes AND 1 kiloByte = 1000 bytes Doesn't this contradict as in both cases it is stated that 1 byte is 8 bits...? Different sources claim different reasons for these different representations, thus I am not sure what the most important/real reason is for this rather confusing difference

Removing Digits from a Number

一笑奈何 提交于 2019-12-01 03:24:26
问题 Does anybody know if there is a way of removing (trimming) the last two digits or first two digits from a number. I have the number 4131 and I want to separate that into 41 and 31, but after searching the Internet, I've only managed to find how to remove characters from a string, not a number. I tried converting my number to a string, then removing characters, and then converting it back to a number, but I keep receiving errors. I believe I will be able to receive the first two digit by

PHP show only significant (non-zero) decimals

那年仲夏 提交于 2019-12-01 03:11:45
In PHP (using built-in functions) I'd like to convert/format a number with decimal, so that only the non-zero decimals show. However, another requirement of mine is that if it's a number without a decimal value, I'd still like to show that zero. Examples: 9.000 -> 9.0 9.100 -> 9.1 9.120 -> 9.12 9.123 -> 9.123 rtrim($value, "0") almost works. The problem with rtrim is that it leaves 9.000 as 9. . sprintf() seemed like a candidate, but I couldn't get it to have a variable amount of decimals. number_format() serves a different purpose, and those were all I could come up with... Again, I'd like to

Fixed decimal numbers with JAVA

吃可爱长大的小学妹 提交于 2019-12-01 03:03:23
问题 How do I represent numbers in the format 001 = 1 002 = 2 003 = 3 010 = 10 020 = 20 The number of digits is always 3. 回答1: If you want to output integers such that they always have leading zeros, use String.format with a zero before the number of digits in the format string, for example: int i = 3; String s = String.format("%03d", i); System.out.println(s); Gives the output: 003 回答2: Integer.valueOf("020") is sufficient for your purpose. It will give you 20 as a result. After that you can use