numbers

I noticed the following fact with CPython3 and Pypy3, contrasting with the behaviour of both CPython2 and Pypy2: In Python3, it looks like leading zeros when parsing code yield an error except for a very single number wich is 0 . Thus 00 is valid but not 042 . In Python2, leading zeros are allowed for all integers. Thus 00 and 042 are valid. Why did Python change its behaviour between both versions? Python 3 standardized how all integer literals (other than base 10) were defined: 0?dddd... , where ? is a single letter indicating the base, and each d is interpreted as a digit in the appropriate

If I use decimal pad for input of numbers the decimal changes depending of country and region format. May be as a point "." or as a comma "," And I do not have control over at which device the app is used. If the region format uses a comma the calculation gets wrong. Putting in 5,6 is the the same as putting in only 5 some times and as 56 same times. And that is even if I programmatically allow both . and , as input in a TextField. How do I come around this without using the numbers an punctation pad and probably also have to give instructions to avoid input with comma "," It is only input for

I'm working on a program that converts numbers to words, but I'm having problems with the toString() method in the Numbers class. All the methods were given to me, so I could implement; therefore, I can't remove any of them... number: 4564 --> four thousand and five hundred and sixty four here's the code Numbers class package numberstowords; import java.util.*; public class Numbers { //array containing single digits words numbers:0-9 private final String[] SINGLE_DIGITS_WORDS; //array containing special words words eg:10-19 private final String[] TEEN_DIGITS_WORDS; //array containing tens

I have a Python assignment that is as following: "Write a complete python program that asks a user to input two integers. The program then outputs Both Even if both of the integers are even. Otherwise the program outputs Not Both Even ." I planned on using an if and else statement, but since I'm working with two numbers that have to be even instead of one, how would I do that? Here is how I would do it if it was one number. Now how do I add the second_int that a user inputs??? if first_int % 2 == 0: print ("Both even") else: print("Not Both Even") You can still use an if else and check for

when I calculate a very small number, matlab gives 1.12345e-15 What is this? I can interpret it as 1.12345*10^(-15) or its 1.12345*e^(-15) I am in very hurry. Sorry for the stupid question. e represents scientific notation as Rahul said but it is base 10, not base e. Run the following code to confirm. 1e1 It gives you ans = 10 e represents exponential. Its the scientific notation of writing numbers. The base is 10. For example: 1e2 =100 1e-2= 0.01 来源： https://stackoverflow.com/questions/29731027/what-is-the-small-e-in-scientific-notation-double-in-matlab

IEEE 754 specifies the result of 1 / 0 as ∞ (Infinity). However, IEEE 754 then specifies the result of 0 × ∞ as NaN. This feels counter-intuitive : Why is 0 × ∞ not 0? We can think of 1 / 0 = ∞ as the limit of 1 / z as z tends to zero We can think of 0 × ∞ = 0 as the limit of 0 × z as z tends to ∞. Why does the IEEE standard follow intuition 1. but not 2.? It is easier to understand the behavior of IEEE 754 floating point zeros and infinities if you do not think of them as being literally zero or infinite. The floating point zeros not only represent the real number zero. They also represent