numbers

Basically I want to know how I would do this. Here's an example string: string = "hello123" I would like to know how I would check if the string ends in a number, then print the number the string ends in. I know for this certain string you could use regex to determine if it ends with a number then use string[:] to select "123". BUT if I am looping through a file with strings like this: hello123 hello12324 hello12435436346 ...Then I will be unable to select the number using string[:] due to differentiation in the number lengths. I hope I explained what I need clearly enough for you guys to help

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself. Example: Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 Explanation: 342 + 465 = 807. 题意 以各位数倒序排列链表的形式给定两个整数，要求计算出两者之和，并同样以各位数倒序链表的形式返回结果。 ˼· 从两链表的个位数开始，依次计算各位数之和并判断记录进位。最后注意对最高位的进位进行处理。(注意先转换为两个整数再相加的方法会存在测试整数值超过上限的问题) 代码实现 - Java /** * Definition for singly-linked list. *

题目： You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not contain any leading zero, except the number 0 itself. Example: Input : ( 2 -> 4 -> 3 ) + ( 5 -> 6 -> 4 ) Output：7-> 0 -> 8 Explanation：342 + 465 = 807 思路： example 1: 2->4->3 5->6->4 (2+5+0)->(4+6+0)->(3+4+1) 第三个数代表进位 7->0->8 example 2: 1 9->9 (1+9+0)->(0+9+1)->(0+0+1) 0->0->1 代码： /** * Definition for singly-linked list. * struct

4-1 比萨 ： 想出至少是三种你喜欢的比萨，将其名称存储在一个列表中，再使用for循环将每种比萨的名称都打印出来。 1 pizzas=['a','b','c'] 2 for pizz in pizzas: 3 print(pizz) 4 for pizza in pizzas: 5 print("I like "+pizza+" pizza.") 6 print('I really like pizza.') 输出： 1 a 2 b 3 c 4 I like a pizza. 5 I like b pizza. 6 I like c pizza. 7 I really like pizza. 4-2 动物 ：想出至少三种有共同特征的动物，将这些动物的名称存储在一个列表中，再使用for 循环将每种动物的名称都打印出来。 1 animals=['cat','dog','pig'] 2 for anima in animals: 3 print(anima) 4 for animal in animals: 5 print("A "+animal+" would make a great pet.") 6 print("Any of these animals would make a great pet.") 输出： 1 cat 2 dog 3 pig 4 A cat would

I need to find out if a string is numeric in dart. It needs to return true on any valid number type in dart. So far, my solution is bool isNumeric(String str) { try{ var value = double.parse(str); } on FormatException { return false; } finally { return true; } } Is there a native way to do this? If not, is there a better way to do it? This can be simpliefied a bit void main(args) { print(isNumeric(null)); print(isNumeric('')); print(isNumeric('x')); print(isNumeric('123x')); print(isNumeric('123')); print(isNumeric('+123')); print(isNumeric('123.456')); print(isNumeric('1,234.567')); print

I'm searching for an algorithm for Digit summing. Let me outline the basic principle: Say you have a number: 18268 . 1 + 8 + 2 + 6 + 8 = 25 2 + 5 = 7 And 7 is our final number. It's basically adding each number of the whole number until we get down to a single (also known as a 'core') digit. It's often used by numerologists. I'm searching for an algorithm (doesn't have to be language in-specific) for this. I have searched Google for the last hour with terms such as digit sum algorithm and whatnot but got no suitable results. Because 10-1=9, a little number theory will tell you that the final