numbers

Oracle NUMBER(p) storage size?

匆匆过客 提交于 2019-12-03 01:41:48
I've searched for it but i can't find a conclusive answer to my question... I need to know what is the storage size of a number(p) field in Oracle. Examples: NUMBER(1), NUMBER(3), NUMBER(8), NUMBER(10) etc... The storage used depends on the actual numeric value, as well as the column precision and scale of the column. The Oracle 11gR2 concepts guide says : Oracle Database stores numeric data in variable-length format. Each value is stored in scientific notation, with 1 byte used to store the exponent. The database uses up to 20 bytes to store the mantissa, which is the part of a floating-point

T-SQL: Pivot but for semicolon-separated values instead of columns

匿名 (未验证) 提交于 2019-12-03 01:41:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I've got semicolon-separated values in a column Values in my table: Values 1;2;3;4;5 I would like to transform it in a procedure to have there values as rows: Values 1 2 3 4 5 How could I do it in T-SQL? 回答1: Solution 1(using xml): declare @str varchar(20) declare @xml as xml set @str= '1;2;3;4;5' SET @xml = cast(('<x>'+replace(@str,';' ,'</x><x>')+'</x>') as xml) SELECT col.value('.', 'varchar(10)') as value FROM @xml.nodes('x') as tbl(col) Solution 2(using recursive cte) declare @str as varchar(100) declare @delimiter as char(1) set

asp.net Textbox Textmode Number, allow numbers only

匿名 (未验证) 提交于 2019-12-03 01:34:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I would just like to know if there is a way in ASP.NET to allow only numbers in textboxes with textmode="number" when I use this: <asp:TextBox runat="server" TextMode="Number" ID="TextBoxDuration" Width="250"></asp:TextBox> <asp:RequiredFieldValidator ControlToValidate="TextBoxDuration" runat="server" ErrorMessage="Dieses Feld darf nicht leer sein" /><br /> <asp:RegularExpressionValidator runat="server" ControlToValidate="TextBoxDuration" validationexpression="((\d+)((\.\d{1})?))$" ErrorMessage="Nur Zahlen" /> users can still input the char

How to call java function in Jenkinsfile using Pipeline plugin in Jenkins

匿名 (未验证) 提交于 2019-12-03 01:34:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am using pipeline plugin in jenkins. My Jenkinsfile has numToEcho =1,2,3,4 but I want to call Test.myNumbers() to get list of values. How can I call myNumbers() java function in Jenkinsfile? Or do I need to have a separate groovy script file and that file I should place inside java jar which has Test class? My Jenkinsfile: def numToEcho = [1,2,3,4] def stepsForParallel = [:] for (int i = 0; i < numToEcho.size(); i++) { def s = numToEcho.get(i) def stepName = "echoing ${s}" stepsForParallel[stepName] = transformIntoStep(s) } parallel

TCP Sequence Number

China☆狼群 提交于 2019-12-03 01:12:00
I'm trying to understand how the sequence numbers of the TCP header are generated. In some places I read that it is the "index of the first byte in the packet" ( link here ), on some other sites it is a random 32bit generated number that is then incremented. I don't really know which is which, so here are some questions: How is the initial sequence number generated? (Please provide an RFC number if there is one) How is it incremented? How is the secret key generated? I read some of the RFCs like RFC 6528 , RFC 793 , and RFC 1948 but I can't seem to understand which one is actually implemented.

How to Convert numbers to Words in Python

匿名 (未验证) 提交于 2019-12-03 01:11:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I need to turn numbers from 1 - 99 into words. This is what I got so far: num2words1 = { 1 : 'One' , 2 : 'Two' , 3 : 'Three' , 4 : 'Four' , 5 : 'Five' , \ 6 : 'Six' , 7 : 'Seven' , 8 : 'Eight' , 9 : 'Nine' , 10 : 'Ten' , \ 11 : 'Eleven' , 12 : 'Twelve' , 13 : 'Thirteen' , 14 : 'Fourteen' , \ 15 : 'Fifteen' , 16 : 'Sixteen' , 17 : 'Seventeen' , 18 : 'Eighteen' , 19 : 'Nineteen' } num2words2 = [ 'Twenty' , 'Thirty' , 'Forty' , 'Fifty' , 'Sixty' , 'Seventy' , 'Eighty' , 'Ninety' ] def number ( Number ): if ( Number > 1 ) or ( Number

Javascript concatenating numbers, not adding up

匿名 (未验证) 提交于 2019-12-03 01:06:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: It keeps concatenating my numbers into 2111 instead of 5. Why is this? I've tried using parseInt with no luck. res3 btw represents a query into my database that I'm executing. var dt_total_hours = 0; dt_total_hours += res3.fieldByName(dt_cost_per_hour); dt_total_hours += res3.fieldByName(dt_prod_dt_hours); dt_total_hours += res3.fieldByName(dt_prod_rate); dt_total_hours += res3.fieldByName(dt_cost_per_unit); dt_total_hours += res3.fieldByName(dt_scrap_startup_cost); dt_total_hours += res3.fieldByName(dt_labor_expense); dt_total_hours += res3

Javascript number placing and how to , 4 = 0.04, 14 = 0.14, 100 = 1.00

空扰寡人 提交于 2019-12-03 01:04:50
问题 I am trying to write a custom calculator but I am having trouble trying to work out a figure, I want to be able to add decimal points before the number which has been in puted. For example if the user puts in 4 I want the value in the string to look like this 0.04 and so on 14 = 0.14, 100 = 1.00. I tried using the inbuilt function var num = 4; fig = num.toFixed(2); But that doesn't work, the only way I can think to do it is with if(val.length >2){ do something; } which would be a long way to

Convert string to decimal number in ruby

筅森魡賤 提交于 2019-12-03 00:53:46
I need to work with decimals. In my program, the user need to put a number with decimals to convert that number. The problem is: If I try to convert the argument into a number I get a integer without decimals. # ARGV[0] is: 44.33 size = ARGV[0] puts size.to_i # size is: 44 # :( You call to_i , you get integer. Try calling to_f , you should get a float. For more string conversion methods, look here . If you want more accurate answer with the calculation to avoid bug like this https://www.codecademy.com/en/forum_questions/50fe886f68fc44056f00626c you can use conversion to decimal example :

扑克牌顺子

匿名 (未验证) 提交于 2019-12-03 00:39:02
题目描述 从扑克牌中随机抽5张牌,判断是不是一个顺子,即这5张牌是不是连续的。2~10位数字本身,A为1,J为11,Q为12,K为13,而大王,小王可以看成任意数字。为了方便我们将大小王看成0。 思路: 1.找出5张牌中得大小王,即0的个数 2.将牌排序,找出相邻牌中的空隙数 3.如果空缺的总数小于或等于0的个数,那么数组是连续的。 在下面的代码中,使用了sort函数,第一个参数为数组首地址,第二个参数为数组尾地址,第三个参数为排序规则。默认为升序 我的代码: bool IsContinuous( vector< int > numbers ) { int len = numbers.size(); if (len< 5 ) return false ; sort(numbers.begin(),numbers.end()); int ZeroNum = 0 ; int GapNum = 0 ; for ( int i = 0 ; i < len;i++ ) { if (numbers[i] == 0 ) ZeroNum ++ ; } int x = ZeroNum; for ( int j = ZeroNum+ 1 ; j < len;j++ ) { if (numbers[j] == numbers[x]) return false ; GapNum += numbers[j]