nsarray

How to do that without having to "scroll" the entire given array with a "for" loop? Josh Caswell Since nobody seems to agree with my comment that this is a duplicate of Better way to convert NSArray of NSNumbers to array of NSStrings , here's the same answer again: NSArray * arrayOfMutableStrings = [arrayOfStrings valueForKey:@"mutableCopy"]; From the docs : valueForKey: Returns an array containing the results of invoking valueForKey: using key on each of the array's objects. - (id)valueForKey:(NSString *)key Parameters key The key to retrieve. Return Value The value of the retrieved key.

I have this struct: struct MessageRandomWords { let message = MessageType.kMessageTypeRandomWords let randomWords : Array<Array<String>> } I'm trying to convert this struct to NSDate by doing this: var message = MessageRandomWords(randomWords: self.words) let data = NSData(bytes: &message, length: sizeof(MessageRandomWords)) But when i'm trying to convert this back to the original struct: var messageRandomWords : MessageRandomWords? data.getBytes(&messageRandomWords, length: sizeof(MessageRandomWords)) if let messageRandomWords = messageRandomWords { } I got a BAD_ACCESS erro on the if let

That's the content... [ { "id": "", "title": "", "website": "", "categories": [ { "id": "", "label": "" } ], "updated": }, { "id": "", "title": "", "website": "", "categories": [ { "id": "", "label": "" } ], "updated": } ] How can I insert every feed source in one array? NSDictionary *results = [string JSONValue]; NSArray *subs = [results valueForKey:@"KEY"]; Which key I must insert? THanks as I can see your structure, you will get out of this JSON-String NSArray: [ NSDictionary: { NSString: "id", NSString: "title", NSString: "website", NSArray: "categories": [ NSDictionary: { NSString: "id",

I have an NSArray of UILocalNotification objects that I need to sort according to a key within the UILocalNotification's userInfo property, which is an NSDictionary. I know how to sort NSArrays by a value that is one level deep, e.g., a key within an array of NSDictionaries, but two levels deep I'm lost. I want to do something like this is psuedo-code: NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"userInfo.personName" ascending:YES]; //the personName key within the userInfo NSDictionary property of a given UILocalNotification NSArray *sortDescriptors = [[[NSArray

I have already fetched data from server and passing the data is also populated with NSMutableArray after NSJSONSerialization . Output of array is as follow's: NSArray *jsonArray = (NSArray *)json; NSLog(@"Array - %@",jsonArray); I want to create a new array which will contain all the data of newsletter. Array - ( { error = 0; newsletter = ( { date = "2015-11-23"; description = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry\\'s standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it

(hmm.. long title) If I start out with an NSArray of custom objects (each object is a Person) like this: { surname:Allen forename: Woody, surname:Baxter forename: Stanley, surname:Clay forename: Cassius } ..etc.. You can see that the array is already in surname order. How do I use that array to create a a UITableView with a section headers A, B C etc, as well as an index thing on the side running vertically A B C EDIT I guess what I'm asking is how to turn my array of objects into a Section Array, with all the first letters of the Surnames, and a Surname Array which is perhaps a nested array

This question already has an answer here: What are the details of “Objective-C Literals” mentioned in the Xcode 4.4 release notes? 3 answers Going through iTunes U Developing iOS 7 Apps for iPhone and iPad and in Lecture 3 slides, on page 120, there's a Quiz question that asks what the following line of code does. Frankly, I'm a bit stumped, and hoped someone could break it down. cardA.contents = @[cardB.contents,cardC.contents][[cardB match:@[cardC]] ? 1 : 0]; So, I get the first part, cardA.contents = a new array with cardB.contents and cardC.contents in the array. But, next comes (I guess??